High Score If m 3 n 2 0 then solve the equation 3m x 1 x n

Solution: x=-3 8

Because:|m-3|+|n-2|=0 and the absolute value of any number is greater than or equal to 0, so: |m-3|=0,|n-2|=0;

So: m=3, n=2

Substituting the values of m,n into 3mx+1=x-n.

9x+1=x-2

Solution: x=-3 8

m-3|+|n-2|=0

Since the sum of the non-negative numbers is zero, both non-negative numbers are 0 to get |m-3|=0

n-2|=0, and the solution is m=3 n=2

Substitute m=3 n=2 into the equation.

3mx+1=x-n

9x+1=x-2

8x=-3x=-3/8

Because:|m-3|+|n-2|=0, so |m-3|=0 |n-2|=0 so we get m-3=0 m=3 , n-2=0 so n=2 brings m=3, n=2 into the equation 3mx+1=x-n to get 9x+1=x-2

9x-x=-2-1

8x=-3x=-3/8

The original form is 0+0=0 form.

i.e. m-3 = 0 and n-2 = 0

m=3, n=2

Bring m=3, n=2 into the equation.

9x+1=x-2

Solve this equation.

x=-3/8

For Equation 1 to be true, if and only if|m-3|=0 |n-2|=0 (absolute non-negative).

m=3 n=2

The equation is 9x+1=x-2

Solution: x=-3 8

There is a question that knows m=3, n=2 and brings in 9x+1=x-2 and finally 8x=-3 x=-3 8

From 3mx+7=0 and 2x+3n=0 are the same equations about x, we can know that m≠ pants are 0 before the pants, and n ≠ is pure and sensitive

The solution gives x=- 7 3m =-3n 2

9mn = 14, Bozhi mn = 14 9 , mn ) 2 = (14 9 ) 2 = 196 81 = 2 34 81

Therefore, fill in: 2 34 81

m(3x+n)-n=(3+m)x+mn

3mx+mn-n=3x+mx+mn

2m-3)x=n

x=n 2m-3 (m does not sell this Wang Yu Ao 3 2).

x^2 - m(3x-2m+n)-n^2=0x^2-3mx+2m^2-mn-n^2=0x^2-3mx+(2m+n)(m-n)=0x-2m-n)(x-m+n)=0

So talking about the Jiling can be obtained: the front type.

x=2m+n or x=m-n

The square term and the absolute term are constant and non-negative, the sum of the two terms = 0, and both terms = 0m-1 = 0 m = 1

n+2=0 n=-2

The equation becomes. 4x+2=4

4x=2x=1/2

Solution: Due to |3m-n+1|≥0,2m+3n-25|0 and |3m-n+1|+|2m+3n-25|=0 so |3m-n+1|=0,|2m+3n-25|=0 solution gives m=2, n=7

Therefore, the equation 2mx-7(x-n)=19

is 4x-7 (x-7) = 19

4x-7x+49=19

3x=-30

x=10

Solution: There are meanings from the title:

3m-n+1=0

2m+3n-25=0

Solution: m=2, n=7

So the equation 2mx-7(x-n)=19 is:

4x-7(x-7)=19, i.e.: -3x+49=19 so x=10

The sum of the two absolute values is zero.

Because the absolute value must be greater than or equal to zero.

How two 3m-n+1=0

2m+3n-25=0

m=2n=7

Equation 4x-7x+49=19

x=10

Solution: If there is a problem, you can know that 3m-n+1=0

2m+3n-25=0 can be solved to m=2, n=7

Generation: 2mx-7(x-n)=19, which can be solved to x=-10