Why gravity is greatest at the poles and smallest at the equator

Answer: Because objects on the earth are affected by the centripetal force generated by the autobiography of the earth in addition to the gravitational force, the magnitude of g should be determined by both. The gravitational force is the same everywhere, but the magnitude of the centripetal force f=mw 2d varies everywhere—the farther away from the axis of the earth, the greater d and the greater the centripetal force; The closer it is to the axis of the Earth, the smaller d d and the smaller the centripetal force.

So the gravitational poles are the largest and the equator is the smallest.

The radius of the poles is small, and the radius of the equator is large. f=mg=gmm r2, g is the gravitational constant, m is the mass of the earth, and m is the mass of the object. r2 is the square of the radius. So g=gm r2, the larger the radius, the smaller g and the smaller the gravitational force.

The distance from the Earth's axis of rotation is not the same... The distance on the equator is the largest, the centripetal acceleration to be provided is the largest, the gravitational force of the earth in addition to providing centripetal acceleration is the gravitational force, the object at the poles is equivalent to no centripetal acceleration on the axis of rotation of the earth, the gravitational force of the earth is equal to gravity, and it is naturally the largest. To calculate centripetal acceleration, you can't use the radius from the center of the earth, you can calculate it from the axis of rotation.

Gravity is one of the components of gravitational force, and the other part of gravitational force is used to provide the centripetal force as a centripetal force, which needs to be provided near the equator is the largest (the radius around the earth's axis is the largest), so the gravitational force is the least.

1. On the ground, the gravitational force experienced by an object is a component of the gravitational force between the object and the earth, and the other component of the gravitational force is used to provide the centripetal force required for the object to rotate with the earth. So the acceleration due to gravity is greatest at the poles and minimum at the equator.

f is the gravitational force and g is the gravitational force.

2. For an object (such as a satellite) that moves in a circle around the earth, we can say that it is completely weightless, because the gravitational force is all used to provide the centripetal force required for the object to move in a circle. It can also be said that gravity at this time is gravitational force.

Gravitational accelerationOn both extremes. The gravitational pull of the earth on objects.

There are two effects: - is the rotation of the object with the earth.

The centripetal force required.

The other is gravity. The further towards the poles, the smaller the centripetal force, the greater the gravitational force, and therefore the greater the gravitational acceleration. Gravitational acceleration, a physics term.

The acceleration produced by gravity on a free-falling object is known as gravitational acceleration. If m is used to denote the mass of the object and g to denote the acceleration due to gravity, gravity g can be expressed as g=mg.

Introduction to Acceleration of Gravity:

If a stone and an iron ball are allowed to fall freely from the same place and at the same height, starting from a standstill at the same time, it can be observed that the velocity of both objects increases uniformly and changes in exactly the same way, and they finally reach the ground at the same time. This phenomenon shows that the movement of a free fall is done in the same place on the earth.

All objects, despite having different weights, have exactly the same magnitude and direction of acceleration during their fall.

This acceleration is known as free-fall acceleration.

It is produced by the gravitational force experienced by an object, also known as gravitational acceleration, which is usually denoted by the letter G. Gravitational acceleration is a vector quantity, its direction is always vertical downward, and its magnitude can be found experimentally. Experiments have proven:

The magnitude of gravitational acceleration varies slightly depending on its location on Earth. In the same place on Earth, the acceleration due to gravity is a constant vector. This determines that the free fall motion is essentially a uniformly accelerated linear motion with zero initial velocity.

Two greats. The gravitational pull of the earth on an object has two effects: one is the centripetal force required for the object to rotate with the earth, and the other is gravity. The further towards the poles, the smaller the centripetal force, the greater the gravitational force, and therefore the greater the gravitational acceleration.

Size, you have to give a reason, don't you?

Let's talk about the shape of the earth first, the earth is an ellipse? In fact he is closer to the shape of the lead cake, i.e. the diameter of the equator is greater than the diameter of the poles. This is caused by the action of the centrifugal force of the earth's rotation.

That is, at the same sea level, it is farther from the center of the earth at the equator than at the poles!!

Far from the center of the earth, the gravitational acceleration will be smaller! The closer it is, the bigger it is!

So in the two greats.

The closer to the equator, the larger, the two poles are certainly the smallest.

Gravitational acceleration is relatively large at the equator, if I'm not mistaken.

The gravity of the poles is greater than that of the equator, and g is the smallest at the equator, g=; At the poles g is maximum, g = .

Due to the rotation of the earth itself, except for the poles, objects in other places on the ground are moving in an approximate uniform circle around the earth's axis along with the earth, which requires a centripetal force directed vertically to the earth's axis, which can only be provided by the gravitational force of the earth on the object.

We can decompose the gravitational force of the earth on the object into two components, one component f1, which is directed towards the earth's axis, and the magnitude is equal to the centripetal force required for the object to move in an approximately uniform circular motion around the earth's axis; The other component, g, is the gravitational force on the object. where f1 = mrw 2 (w is the angular velocity of the earth's rotation and r is the radius of rotation of the object), it can be seen that the magnitude of f1 is zero at the poles, increases with the decrease of latitude, and is the maximum f1max in the equatorial region.

The gravitational acceleration on the surface of the earth is determined by the mass and radius of the earth, and because the earth is ellipsoidal, the radius of the equator is large, and the radius of the poles is small, so the gravitational acceleration at the equator is small, and the gravitational acceleration at the poles is large.

1. The meaning of gravitational acceleration:

1. The direction of gravitational acceleration g is always vertically downward.

2. The gravitational acceleration of any object is the same at the same height in the same area.

3. The value of gravitational acceleration decreases with the increase of altitude. When the height of the object from the ground is much less than the radius of the earth, g does not change much. However, when the height above the ground is large, the value of gravitational acceleration g decreases significantly, and g cannot be considered as a constant at this time.

2. The gravitational element of gravitational acceleration:

1. Size: related to quality and location; (g=mg) (where g= m s2, the hand stop is the standard gravitational acceleration).

2. Direction: vertically downward; (to the center of the earth).

3. Action point: center of gravity.

3. Calculation method of gravitational acceleration:

Because f=gmm r 2, f=g=mg, the land dust is g=gm r 2.

1. g: gravitational constant =;

2. m: the mass of the central celestial body in kilograms;

3. r: the distance between the center of the celestial body and the center of the object m;

4. The unit of g is m s 2 or n kg.

On both extremes. Because, on the surface of the earth, the centripetal force of the rotation of the object m with the earth is f, f m r, and near the poles, the radius of rotation r is relatively small, and the centripetal force required for rotation is also relatively small.

In this way, near the poles.

The corresponding gravitational component is larger, and the gravitational acceleration is also larger.

Gravitational acceleration increases with latitude, which means that it is larger at the poles and smaller at the equator.

Change in gravitational acceleration g.

It is mainly caused by the rotation of the earth.

That is, the gravitational force of an object at the equator is minimal.

According to gravitational pull, an object close to the center of the earth.

The gravitational pull is also great.

That is, the acceleration due to gravity g

Increases with latitude.

So the equatorial circle is the smallest and the poles are the largest.

The acceleration due to gravity is as great at the equator as it is at the poles.

The positive and negative particles of solar radiation are reflected less directly in the air at the equator, and the two poles are reflected more due to oblique radiation, but the time of the solar particles hitting the equatorial region in the fixed time (such as 24 hours) is less than that of the poles (such as the polar daylight phenomenon at the poles), the unit solar energy in the equatorial and polar regions can be given by the effective time in the energy flow density x fixed time (such as 24 hours), and the solar current density in the equatorial region is greater than that of the poles, and the 24-hour solar photon collision time in the equatorial region is less than that of the poles. It can be seen that the gravitational acceleration and gravitational force of the equator and the poles are greater than the product of the energy flow density and the effective time in the fixed time (e.g., 24 hours), because the effective collision time of solar photons in the polar region is longer within 24 hours of the fixed time, it is estimated that the gravitational and gravitational acceleration of the poles is greater than that of the equator, and the aurora phenomenon is more likely to occur in the polar region than in the equatorial region, which is also determined by the solar current density x fixed time (e.g., 24 hours) in the polar region is greater than the equator, which is for reference only.

The gravitational acceleration at the poles is slightly greater than at the equator, because in addition to gravity, there is also a centrifugal force that is reversed by rotation, and the poles do not have this centrifugal force.

The g-value of the Earth's polar regions is , and the g-value of the equatorial regions is about 5 (5 thousandths).

Among them, because the Earth is not an ideal sphere, the polar radius is slightly smaller than the equatorial radius, causing a difference of a little more than 2 thousandths, and the rotation of the Earth causes a difference of more than two thousandths, adding up to about 5 thousandths.

If you're good at physics in high school, do the math yourself.

As long as you try it a few times by yourself, there is no problem at all, and the computer and mobile phone have no effect.

The Earth's equatorial radius is larger than the polar radius, and the same object experiences the least gravitational pull at the equator.

But the linear velocity of the same object at the equator is the greatest and the centripetal force required is also the greatest.

The smallest gravitational force provides the maximum centripetal force, and the rest is gravity.

It can be seen that the gravitational force is the smallest, and the mass of the same object is constant, so the gravitational acceleration is the smallest.

The magnitude of the acceleration of gravity is related to the gravitational force, which is a component of the gravitational force, and the other component of the gravitational force acts as the centripetal force for the object on the ground to move in a circle. So the main reason why gravitational acceleration is different in different places is that the gravitational force is different in different places on the earth.

The radius of the equator is about forty or fifty kilometers larger than the radius of the poles, so the objects on the equator are farther away from the center of the earth and receive slightly less gravitational force than the poles.

The acceleration due to gravity at the equator is smaller than that at the poles.

Because the radius of the equator is greater than two maximums, there is also the centrifugal force of the earth's rotation The effect of centrifugal force is as follows:

Because a = v 2 r, and v = 4 * 10 7 3600 24 = 463 m s, = 6367 * 10 3 m, so a =

The acceleration due to gravity is between , and the difference between the two.

So it's mainly from the effect of centrifugal force.

It is the size of the poles.

First of all, it is important to know that gravity is a component of the gravitational force.

1.Let's not think about that complicated.

Let's start by assuming the Earth as a positive sphere.

When it rotates, because the angular velocity is the same, and the pole position is on the axis of rotation, if the object is there, it can be said that there is basically no linear velocity. Without doing circular motion, there is no need for centripetal force.

The object at the equator is farther away from the axis of rotation and has a great linear velocity. Centripetal force is required.

If the Earth is assumed to be a sphere, the gravitational attraction on the objects in each position is the same.

Objects at the poles, since they do not move in a circle, the gravitational force is gravity.

Whereas, an object at the equator has to provide centripetal force due to a part of the gravitational force, and the remaining part of the gravitational force is the gravitational force.

It can be seen that the gravitational force of the late position must be smaller than that of the poles, and divided by the equal mass, the gravitational acceleration of the natural poles is greater.

2.Taking into account the irregularity of the Earth, the Earth is an irregular sphere with slightly flattened poles and slightly bulging equators. Therefore, the gravitational pull on the object at the poles is inherently greater than at the equator.

Therefore, the gravitational force at the poles must be greater than the gravitational force at the equator minus the centritorial force.

To sum up, it can be seen that the gravitational acceleration is large at the poles.

The gravitational acceleration at the poles is large. Because:

1.The radius of the Earth's poles is smaller than the radius of the equator, and the gravitational force is inversely proportional to the square of the distance, so the gravitational force on the objects at the poles is larger.

2.The radius of the circular motion is the largest near the equator, and the radius of the circular motion decreases with the increase of latitude, and the radius of the circular motion at the poles of the poles is zero. The centripetal force that sustains the object in a circular motion is proportional to the square of the radius with the same angular velocity.

Therefore, the centripetal force required for the circular motion of an object at the equator is large, and the gravitational force minus the centripetal force is the gravitational force.

The objects at the poles are subjected to a greater gravitational force, and then subtract the smaller centripetal force, so the gravitational acceleration at the poles is large.

Poles. Absolutely.

Consider two reasons:

1.Gravitation. 2.Centrifugal force.

The Earth is an irregular sphere with slightly flattened poles and slightly bulging equators. Hence close to the center of the earth at the poles, hence the gravitational pull is great. The farther away from the axis of rotation, the greater the centrifugal force.

The value of gravitational acceleration is gravitational minus centrifugal force, whereas at the poles, the gravitational force is large and the centrifugal force is small. So the value is greater than anywhere on Earth.

According to the law of gravitation, the attraction of the earth f=gmm r*r, gravity f=mg, f=f, where m, m, g are unchanged, the smaller the radius f, the greater the gravitational acceleration g, because of the centrifugal force of the earth's rotation, the earth forms an irregular sphere, and the radius of the poles is smaller, so the gravitational force is large, the gravitational force is large, and g is larger.