Chemistry masters, people can enter! Kneel down to solve a high school chemistry problem and have a

Because there is a surplus of acid, it means that Fe all becomes ferric iron (if there is a surplus of iron, it will eventually become ferric iron) Fe - Fe(NO3)3

Regardless of whether the amount of gas produced is NO2 or NO2, then the NO3- consumed is and the last hydrogen ion should exist in the form of HNO3.

Then the total Hno3 before the reaction = the amount concentration of the substance c = so a is wrong.

After the reaction, NO3 exists in the form of Fe(NO3)3 and HNO3 and the amount of total species is the amount concentration of the substance.

So C right.

According to the acid there is a surplus (the pH of the solution after the reaction is measured to be 1), so the reaction is:

Fe + 4Hno3 = Fe(No3)3 + No + 2H2O Remaining Hno3 =

Original total HNO3 = +

It turns out that the concentration of total Hno3 is =, and a is wrong.

b correct. C is false, the remaining NO3 - = = in the solution

c(no3－)=

d。There is also hno3 = in the solution, according to:

3fe + 8hno3 =3 fe(no3)2+ 3no + 4h2o

The solution after the reaction can be dissolved at most

Iron is a mole of gas produced by moles of nitrogen is also a mole of nitrogen produced by the equality of electrons gained and lost, so the nitrogen produced should be 3 valence, so the formation is a mixture of nitric oxide and nitrogen dioxide, and each accounts for half of it, so b is wrong The nitric acid consumed by the conservation of nitrogen atoms is known to be moles, so the concentration of nitric acid before the reaction should be moles, so a is wrong, c is wrong, so d is right.

First of all, I would like to thank the students of Shandong High School.

Solution: When NO2 can be absorbed by ammonia water, a mol NH4NO3 is dissolved in water, and the solution is acidic, the reason is NH4+ +H2O== (reversible) = NH3H2O+H+ (expressed by ion equation). After the solution is neutral after adding b l ammonia dropwise to the solution, the ionization equilibrium of the water will move in the reverse direction (fill in "forward", "no" or "reverse") during the dropwise addition of ammonia, and the concentration of ammonia dropwise is a 200b mol·l-1.

The ionization equilibrium constant of NH3·H2O is taken as KB=2 10-5mol·L-1).

The reasons are as follows:1The process of dropping ammonia water will inhibit the ionization of water. The reason is that the addition of alkali will inhibit the ionization of water, so the ionization equilibrium of water will move in reverse (fill in "forward", "no" or "reverse").

2.From the conservation of charge: n(nh4+) n(h+)==n(no3-) n(oh-), because the solution is neutral, n(h+)= +n(oh-), n(nh4+) ==n(no3-) =a

NH3H2O== (reversible) ==NH4+ +OH-

x a /b 10*-7

Ionization equilibrium constant of NH3·H2O.

kb=c( nh4+)*c（ oh-)/c(nh3h2o)=[ (a /b )*10*-7 ]/x=2×10-5mol·l-1

So x = a 200b mol·l-1

The first question is inexplicable? Either you're wrong or you're wrong.

The ionization equilibrium in the process of adding ammonia water will " Who is ionization equilibrium referring to here? According to the title, it can only be water, because ammonium sulfate is a strong electrolyte, and there is no ionization equilibrium!

In ammonium sulfate, the hydrolysis of ammonium ions will promote the ionization of water, and the addition of ammonia water inhibits the hydrolysis of ammonium ions, which also inhibits the ionization of water, so the ionization balance of water moves in the opposite direction;

The second one can't be done at all, only know the ammonium sulfate a mol, don't know the volume of the solution, even if V l ammonia is added, the total volume behind it is impossible to determine at all.

Reverse A 200b This is last year's Shandong college entrance examination question, and I memorized the answers to a lot. I am a senior in Shandong High School.

In fact, it is the knowledge of analogous acids, alkalis and other things.

H3O+ is water and hydrogen ions, in fact, it is usually abbreviated as H+ should be H3O+.

1) An analogy can be made.

HCl + NaOH = NaCl + H2O (Neutralization reaction occurs between acid and base to produce salt and water).

Hi + NaOH = Nai + H2O2Hi + Ca(OH)2 = CA2 + 2H2O(2) can be seen as metals reacting with water to form alkali and hydrogen.

The analogy of 2Na + 2H2O = 2NaOH + H2 CA + 2H2O = Ca(OH)2 + H2 (3) can be analogized: basic oxides react with acids to form salts and water.

cao + h2o= ca(oh)2

It's just that there will be analogies, and it depends on the situation. To be written as two substances.

4) The insoluble alkali is heated and decomposed to form oxides and water.

Cu(OH)2 = (heated) CuO + H2O

The first mnh is equivalent to the metal oxide mo reacts with NH4i, which is equivalent to the reaction with Hi, thus producing water and salt Here water is equivalent to NH3, therefore) 2NH4i + MNH 3NH3 + MI2

Do you understand this?

The second NH3 is equivalent to water, so M follows water to generate M(OH)2 and H2 OH- and is replaced by NH2-.

The third NH4Cl can be regarded as HCl, then it reacts with MO to produce water and salt, and water is ammonia.

The fourth ) m(nh2)2 is actually m(oh)2Heating produces MO+H2O and water is equivalent to NH3 thus.

m(nh2)2 (heat) m(nh) +nh3

NH3 and H2O are similar: both H are combined with N element and O element, the differences: 2 electrons saturated by O reach 8 electron stable structure, N gets 3 electron saturation reaches 8 electron stable structure and the order of H in the chemical formula.

The key to this question: 1. What are the reactions that can occur with ammonia? 2. What are the reactions that can occur in water? 3. The most important thing is to understand NH3 as water with 3 H atoms, and H2O as ammonia with 2 H atoms.

The ionization of water is the generation of a hydroxide and hydrogen ions. Think of ammonia as a ...... waterIonization is understood as an ammonia gaining a hydrogen into ammonium, and an ammonia losing a hydrogen into that NH2 ......For those four questions, you replace ...... with hydroxides or hydrogen ionsMobile phones are inconvenient to talk about ......That's it......

1) If the temperature of the original CaCO3 decomposition equilibrium system is increased and the volume of the reaction vessel is reduced, the original equilibrium: dThe direction of the balance movement could not be determined.

Explanation: The higher the temperature, the greater the pressure, indicating that the temperature is rising, and the equilibrium is moving in the positive picoland, and the reaction is endothermic in the positive direction. The heating equilibrium moves in the forward direction, and the pressurized equilibrium moves in the opposite direction.

When the temperature is raised to a certain temperature and then pressurized, the result of the equilibrium movement must be the equilibrium pressure when the pressure returns to that temperature.

2) In a closed container that cannot exchange heat with the outside world, a sufficient amount of CaCO3 establishes a decomposition equilibrium at 850, and if the volume of the sensitive container is doubled, the temperature in the container will decrease when the combustion equilibrium is re-reached. The pressure inside the container will be less than when equilibrium. Rationale:

Decompression, the equilibrium moves in the forward direction, because the positive reaction is an endothermic reaction, and the device is an adiabatic device, the temperature of the system is reduced.

It can be seen that the consumption is late.

Hydrochloric acid. So it is hydroxide ions that participate in the reaction.

Let the sodium hydroxide in the mixture be x

mol hydroxide and barium are sold as denier plexus ymol

then x+2y=

40x+171y=

The solution. y=

x = so the sodium hydroxide mass fraction is.

I remember that at 850, the equilibrium constant of this reaction was 1!

So when the equilibrium state is reached, k = c (co2) * c (h2) c (co) * c (h2o) = 1

At the same temperature, k is constant!

1) When x=5, at this moment (not moving) q=c(co2)*c(h2) c(co)*c(h2o)=5 3, so q is greater than k, so q=k, so the equilibrium should move in the opposite direction of reaction.

2) With the explanation of 1), to make the equilibrium move in the direction of the positive reaction, it is necessary to satisfy q to be less than k in an instant (without moving), so 0<=x<3

2) This is not difficult to understand, a is less than b, you can also press k = 1 to calculate the concentration!

（1）<

2 ）0≤x<3

If you analyze it well, it's too much to fight.

Existing reaction Co(g) + H2O(g) CO2(g) + H2(g) --1:1 == 1:1

Condition; 1:3==1:5

1) So the above equilibrium moves in the direction of the inverse) reaction.

2) Then the condition that x should be satisfied is x<3

x=and y=,-- x is h2, what is y?

Follow the analysis of feelings, more must be less moving, Le Chartret said