Math problem y 2x 5 x find the range of values for y

First, define the domain.

2x 5 is greater than or equal to 0, and x is greater than or equal to 0, and the solution is x greater than or equal to 5 2 so x is greater than 0

You can deform y= (2x 5) x as follows:

y= [(2x-5) x 2], where the brackets are all in the root number.

Continue to deform, y= [(2 x)-5 (x 2)], where the middle parentheses are all inside the root number.

At this point, you can use the matching method to complete it.

y= 5· [2 5x)-1 (x 2)] 5· [2 5x)-1 (x 2)+1 25-1 25] 5· [2 5x)-1 (x 2)+1 25-1 25] 5· [1 25-(1 5-1 x) 2] Therefore, it is sufficient to find the range of 1 25-(1 5-1 x) 2.

And x is greater than or equal to 5 2, so 1 x is less than or equal to 2 5 and greater than 0 Therefore, only z=1 25-(1 5-t) 2 is required, where t is less than or equal to 2 5 and greater than 0

The range of this quadratic function can be found.

The range of z is the range of y.

The square of both sides yields y 2*x 2=2x-5

becomes a quadratic equation for.

y^2*x^2-2x+5=0

Since x is a real number, 4-20y 2=>0

So 0<=y<=sqrt(5) 5

0, 1 5] The root number is 1 5, using the substitution method learned in high school, replacing 1 x with t, we know that t is in (0, 2 5], when t = 1 5. Take the maximum value of 1 5, and when t=2 5, take the minimum value of 0

Because of the silver wide ant|x|=5,|y|=2, so x=5 or -5, y=2 or -2, so x-y has 4 tricks.

One, 5-2 = 3

Two, 5-(-2) forward burial = 7

Three, -5-2 = -7

Four, -5-(-2) = -3

|x|=5，|y|=2 and the rock is x 0, x=-5, the thick bridge is y= 2, when x=-5, y=2, x+y=-5+2=-3, when x=-5, y=-2, x+y=-5-2=-7

Let x 2y a(x y) b(2x y) compare the coefficients of x and y on both sides of the equation, yes.

A Songzheng 2b 1, a b 2, a 1, B 1, so 5 x y 2, 1 2x y 4, and 6 x 2y 6.

|x|=2,|y/=5

The previous answer is x = 2 and y = 5

Again Hui Bi Hui x Hui Ruined Y

x=2,y=-5

x+y=2+（-5）=-3