J2ME is a simple problem with helloworld running

Updated on technology 2024-04-13
12 answers
  1. Anonymous users2024-02-07

    You go here and check it out for sure to help.

  2. Anonymous users2024-02-06

    WTK comes with an emulator Or you package the program,Use the phone naughty boy simulation display,Again。。 Put it on your phone (MIDP supported).

  3. Anonymous users2024-02-05

    You don't have a helloword class in your classes or bin directory... You delete the classes directory or bin directory entirely, and then recompile the project.

  4. Anonymous users2024-02-04

    It should be a little! I'm using a jsp, tomcat server, and I add a dot to the classpath in my environment variable.

  5. Anonymous users2024-02-03

    It should be that your wtk is not configured right... Delete the original wtk.,It's deleted in the configuration.,And then reconfigure the wtk.。。。

  6. Anonymous users2024-02-02

    Workaround:

    Run the preferences in the wtk from the start menu and find security, which will be'unidentified third party to'identified the third party to the right security domain

  7. Anonymous users2024-02-01

    Is your JDK configurable?

    The JDK path must be configured.

    Your ** can't see clearly

  8. Anonymous users2024-01-31

    I can't see it clearly.,,** Look.

  9. Anonymous users2024-01-30

    You** are right, there is a problem: the above is not wrong, abstract should be removed, the class of extends midlet is not an abstract class, this is the program entry class of j2me.

    Environment version: The general version can be configured successfully, only, some plug-ins may have version requirements, you just learned, with a usable on the line. There is also an Eclipseme plug-in installed on the Internet, Eclipse

    The textbox cannot be displayed in a form.

  10. Anonymous users2024-01-29

    It's not a problem, I've also encountered it, I can run it in other classmates, it's a configuration problem, uninstall and reconfigure it.

  11. Anonymous users2024-01-28

    New Thread constructs an anonymous thread class and calls the class's method start().

  12. Anonymous users2024-01-27

    The problem with the program, but I don't have the tools here, I can't help you, the fault is in the main method, it's the error on line 13 of the program.

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