Is sliding friction on an inclined plane a component of gravity? Why? Beginners, please be patient

No! First of all, their properties are different, gravity is a conservative force (i.e., the work done is only related to the position of the beginning and the end, and has nothing to do with the path, while the work done by friction is related to the path), while the frictional force is not. So the sliding friction force on the inclined plane is not a component of gravity.

Secondly, friction is caused by the pressure on the inclined plane caused by the component of gravity perpendicular to the downward side of the inclined plane, one is the cause and the other is the effect.

Finally, the direction is different. If the slider slides downward, its frictional force is parallel to the inclined side, while the two components of gravity are perpendicular to the downward slope and the other is parallel to the downward slope.

From the above three aspects, it can be judged that it is not!

Hope you figure it out! Good luck with your studies!

No, it is because there is a component of gravity that produces friction, mainly gravity produces a component of the vertical inclined downward side, which produces friction, according to f=fn u, u is the coefficient of friction, and fn is the component of gravity!

A bit of a problem on the ground floor huh.

Because the component of gravity in the inclined plane is a force of gravity nature, which is different from the force of friction, and the reason for the friction force is because the object and the contact surface are extruded, and there is a friction coefficient, and the friction force is indeed caused by gravity, but it is not the component force along the inclined plane, but the component force perpendicular to the inclined plane, so that the inclined plane produces a supporting force on the object, and the force analysis sequence is like this: one gravity, and elastic force, three friction forces, first of all, these three nature forces, and finally see if there are other property forces, such as electric field force, magnetic field force In short, all kinds of physical forces have their definitions.

The second floor is good. The component of gravity in the inclined plane is a force of gravitational nature, which is different from the force of friction, and the reason for the friction is because the object and the contact surface are extruded, and there is a friction coefficient, and the friction force is indeed caused by gravity, but it is not the component force along the inclined plane, but the component perpendicular to the inclined plane, so that the inclined plane produces a supporting force on the object, and the force analysis sequence is like this: one gravity, and elastic force, three friction forces, first of all, these three nature forces, and finally see if there are other property forces, such as electric field force, magnetic field force In short, all kinds of physical forces have their definitions.

Sliding friction is related to the coefficient of friction u.

When the object is at rest on the inclined plane, the downward component of the gravitational force along the inclined plane is equal to the frictional force and is a static frictional force, and the magnitude of the frictional force is mgsin

When the object slides at a constant speed, the maximum static friction experienced by the object is equal to the component of gravity, i.e., mgcos = mgsin

When this component is greater than the maximum static friction, the object will slide downwards and the experienced friction force is mgcos, which is not necessarily equal to the component of gravity.

The object is at rest.

f=mgsinθ

f= mgcos when sliding

Friction ForceWhen two objects in contact with each other are in relative motion or have a relative motion tendency, a force that hinders the relative motion or relative motion tendency will be generated on the contact surface, and this force is called frictional force. Friction is a contact force, i.e., there can be friction between objects that are in contact with each other.

Friction generation conditions:

First, objects are in contact with each other;

Second, there is a mutual squeezing effect between objects;

Third: rough contact surface of the object;

Fourth, there is a tendency or relative motion between objects;

Classification of friction:

Static friction. Rolling friction.

Sliding friction.

The magnitude of friction.

on a horizontal plane.

The magnitude of friction when at rest.

f=f The direction of friction is opposite to the direction of thrust.

The amount of friction when sliding.

f= fnfn refers to the positive pressure, and the direction of friction is opposite to the relative direction of motion on an inclined plane.

If the object is stationary on an inclined plane, frictional force.

f=f1=mgsinθ

The direction is upwards along the inclined plane.

If the object is moving on an inclined plane, the frictional force is sliding friction.

f=μf2＝μmgcosθ

The direction of friction is opposite to the relative direction of motion of the object.

When the object is at rest on the inclined plane, the downward component of the gravitational force along the inclined plane is equal to the frictional force and is a static frictional force, and the magnitude of the frictional force is mgsin

When the object slides at a constant speed, the maximum static friction experienced by the object is equal to the component of gravity, i.e., mgcos = mgsin

When this component is greater than the maximum static friction, the object will slide downwards and the experienced friction force is mgcos, which is not necessarily equal to the component of gravity.

Let the inclination be

Positive pressure of the object on the inclined plane = mgcos

Without drawing, you can also imagine the case of a special position: =0, positive pressure = mg, =90 positive pressure = 0, so it is cos, which is the opposite of the gliding force = mgsin).

Sliding friction f=n· =mgcos · The direction of the force is opposite to the direction of motion.

Answer: The direction of friction on the object is downwards along the inclined plane, and the reaction force of the object on the inclined plane goes upwards along the direction of the inclined plane.

Judgment method: In this case, the frictional force hinders the movement of the object in the opposite direction to the direction of the object's motion, and then the direction of the force of the object on the inclined plane can be judged according to the action force and the reaction force. Satisfied! Thank you!

Frictional force. In the college entrance examination, there are many contents and a wide range, which is a relatively troublesome force in mechanics. Through visual examples, we can understand the method of judging the direction of friction and the calculation of size.

Friction is divided into static friction and dynamic friction, when the object is at rest on the inclined plane, the frictional force is static friction, which is balanced by the force, which is the component of gravity along the inclined surface downward, when the object slides on the inclined plane, the frictional force experienced is sliding friction, which is obtained by the formula of sliding friction, which is fn.

Just like stone

It is said that the sliding friction of the same object on a flat surface is greater than that on an inclined plane, but the force used to pull the object up the inclined plane is greater. The reason for this is that on a flat surface, you only need to overcome friction to do work, while on an inclined plane, you need to overcome gravity and sliding friction to do work, of course, the force used is much greater.

I hope you will adopt it!!

The guy above thought a little angrily....The reason for the problem of lz is that part of the gravitational force of the object on the inclined plane is divided into a parallel inclined plane as a sliding force, so the pressure on the inclined plane is less than on the flat plate, and f=un, so it is ......ok!

You say the opposite!

f=u*f is the gravitational force of the object f=m*g in the plane and f is a component of the gravitational force f=m*g*sin in the inclined plane

So the sliding friction of the same object on a plane is greater than on an inclined plane (with the same coefficient of friction and only the gravitational field).

The friction force on the slider is less than the downward force of gravity along the inclined surface, which means that the slider cannot be stationary on the inclined plane and will slide downward.

If it is greater than, it can only be when moving on an inclined plane (it can only be equal to when stationary on an inclined plane). Regardless of whether the slider is moving upwards or downwards, it is decelerating (until it comes to rest on an inclined plane).

If it is equal, it depends on whether the original slider has a great reputation for speed, the original is stationary, then it remains stationary, and the front vertical void skin originally has a downward speed, then it moves downward at a uniform speed. (If there is an upward velocity, then do a deceleration motion upwards).

It means that the power is greater than the resistance.

The slider slides down the slope.

equal to the time.

The slider or rock does not move.

The friction will not be greater than the power.

You should know the difference between dynamic friction and static friction.

Suppose the minimum force to push the slider is 50N

When you push this slider with a force of 0 to 50N.

The static friction on the slider is equal to the force you push it.

At this point it does not move.

When you push the slider with a force greater than 50n.

The slider will be pushed by you.

At this time, the slider is subjected to dynamic friction, and the calculation method of dynamic friction is the product of positive pressure and friction coefficient.

At this point, the friction force on the slider must be less than the force you push it.

Otherwise, it wouldn't move.

I got it out.

When it is less than, it means that in the direction of the inclined surface, the power is greater than the resistance, and the slider will slide downward. Equal, balanced, the slider stops stationary or uniform linear motion. If it is greater, it is not good to say that the shield is said, how can the friction force be greater than that component?