Find the maximum number in a two dimensional array and its position

In C, here's the main part.

int x,y,x_max,y_max,max;

int a[m,k];

max=0;

for(x=0;x<=m;x++)

for(y=0;y<=k;y++)

if(i>max)

max=a[x,y];

x_max=x;

y_max=y;

The resulting max is the maximum, and (x max, y max) is the position of the maximum.

# include

# define m 10

# define n 5

void main()

int a[m][n];

int i,j,row=0,col=0;

int *p;

p=&a[0][0];

for(i=0;ifor(j=o;j Enter data.

for(i=0;ifor(j=o;jif(*pp=&a[i][j];

row=i+1;

col=j+1;

Determine the size of the number referred to by p and the current number, and if it is small, change the pointing of p to ensure that it always points to the largest number. Since the subscript starts at 0, add 1 to the rows and columns of the output.

printf("the largest num is %d;it is in %drow,%dcol",*p,row,col);

The calculation is to divide the number of elements in the array by the number in the second dimension, if there is a remainder.

Then the quotient +1 is the size of the first dimension, and the quotient without remainder is the size of the first dimension. For example, in your example, 9 4 = 2 and 1 remains, then 2 + 1 = 3, and the size of the first dimension is 3The rest is not set, and the system will depend on the data type.

Automatic value assignment. <>

The calculation method is: divide the number of elements of the array by the number of the second dimension, if there is a remainder, then the quotient +1 is the size of the first dimension, and the quotient without a remainder is the size of the first dimension. For example, in your example, 9 4 = 2 and 1 remains, then 2 + 1 = 3, and the size of the first dimension is 3

If the rest is not set, the system will automatically assign values based on the data type.

Numeric index, incrementing from zero.