A string of characters is read from the keyboard, and the number of occurrences of numbers, letters,

#include

main()

char cstring[256];

int i,nnum=0,cnum=0,onum=0;

scanf("%s",cstring);

for(i=0;i<256;i++)

if (cstring[i]=='\0') i=255;

printf("%c",cstring[i]);

if (cstring[i]>=48&&cstring[i]<=58) nnum+=1;

else if (cstring[i]>=65&&cstring[i]<=90) cnum+=1;

else if (cstring[i]>=97&&cstring[i]<=122) cnum+=1;

else onum+=1;

printf("The characters you enter contain %d numbers, %d letters, and %d other characters",nnum,cnum,onum);

I'm a rookie, don't laugh at me! */

Don't know what language you want to write this program in.

Write one from the key field quarrel plate inputStringsA program that uses a pointer to output the first 5 characters of a string:

import

public class a

public static void main(string args)

scanner sc=new scanner(

string str= new string[5]

Please enter 5 strings from the console and press enter to confirm! ")

for(int i=0;i<5;i++)

str[i]=

for(int j=4;j>=0;j--)

Usually the overall inspection of the string is used as the object of operation.

For example, find a substring in a string, answer a substring for the spine, insert a substring at a certain position in the string, delete a substring, etc. A sufficient and necessary condition for two strings to be equal.

Yes: The length is equal, and the characters are equal in each corresponding position. Let p and q be two strings, and the operation of finding the position where q first appears in p is called pattern matching. The two most basic ways to store strings are sequential and linked.

Summary. Enter 5 characters from the keyboard and count the number of times the "0" character appears?

This question is up to me, it takes a little time to type, so please be patient.