Elementary school math problems Good can add 100 points

1.Each cage contains 24 chickens (here assuming x cages), then there are 5 chicks left, reduce 2 chicken cages, and keep the rest of the cages unchanged, so that there are 24 + 24 + 5 = 53 on the outside, and these 53 chickens should be evenly distributed among (x-2) cages, because 53 is a prime number, there is no least common divisor. So the remaining (x-2) = 53, so x = 55, after evenly distributing the 53 cages with 25 chickens each.

So there are 1,325 chickens.

2.I think the process is a bit troublesome, there are 2 Young Pioneers, and there are 12 original saplings.

3.More new coins came out of 995, and the new magic tree came out after May 1st, so the number of new coins is less than 31, so find the largest common multiple of 31 less than 995, which is 992You can also divide 995 by 31 to get 32, which is the original number of magic trees, and the remainder is 3, that is, the number of gold coins obtained by the new magic tree, so the new magic tree appeared on May 28.

4.Simple permutation questions. There are 60 sets of numbers, arranged from largest to smallest, the 51st is 263, and the remainder divided by 6 is 5

The new four-digit number is 6 times more than the original four-digit number, and the extra 6 refers to the difference between the single digits, and it can be inferred that the single digit is 0. Because the single digit becomes 6 after adding 6, and 0 times 4 is still equal to 0, so the new four-digit number is 6 times more than the original four-digit number.

The single digit has been determined and is 0. Millions of digits are all 2, and the original number is 2220, is the process successful? I drew it on the paper and came out, each assuming an unknown number, xyz0 is the original number, and it can be checked. o(∩_o~

6.The topic is not complete, and the road conditions in stage B are not introduced. Is it an implicit question???

7.The most knife-saving cutting method is that the nth power of 2 is equal to or greater than 218, n=8, and 256 pieces are cut, so at least 8 knives are required.

8.is the score composition of CA: 2+2+2+2+1=9

The score composition of b: 1+1+1+1+5=9

The score composition of c: 5+5+5+5+2=22

Because C's score is 22 points, it is determined that there are 5 subjects, and C has won 4 firsts and 1 second. And because B is the first place in language knowledge, there is a score of 5. In this way, A does not have the first place.

So the score structure should look like above. And the scores of each one correspond to the top and bottom, that is, A is the second place in the four subjects, and 2 points are awarded; The corresponding B is the third place in all four subjects, that is, 1 point; All four of C are in first place, with 5 points.

Why is the first language of B, and the second place can only be C, because C must have a 2 points, that is, the second place.

It can't be a!! Because if A is second, then C is third, 1 point, from the above analysis, we know that C is the least 2 points, there is no third place!!

Times: 1 type. 3 times: 1 type.

4 times: 1 type.

5 times: 3 types.

So there are 6 kinds in total.

1325 human chicken coop Key points: This uses Euclidean division (domestic is called division with remainder, right?) 53 is a prime number.

2 Young Pioneers, 192 Trees Points: Same as above, use Euclidean division to do it, note that 20 is not a prime number, so it is necessary to discuss the situation of 10, 4, and 20 Young Pioneers.

May 29 Takeaway: The essence is the remainder of 995 divided by 31.

5 Points: A total of 5x4x3 = 60 numbers, and the 51st number is 263

2220 Points: 6666=3x+6

The topic is not complete, please tell me the situation of phase B, the method should be a general system of equations.

At least 21 knives Key points: 1 piece at the beginning, cut 1 knife into 2 pieces, the number of blocks increased by the nth knife is 1 + the number of intersection points between the knife and the previous n-1 knife, so the maximum number of blocks is increased, n(n+1) 2+1 is not less than 218, so n is at least 21

Student C Key points: A total of 40 points, there are 5 items, C won 4 first and 1 second, C took the second in Chinese (the first was robbed).

6 types of points: enumeration by number of times.

1. There are x chicken coops.

24x+5=（24-2）x

x=？？The title is wrong.

2、..Too much.

1. Reducing two cages, 48 chickens are added, plus 5 for a total of 53, 53 is a prime number, so a total of 53 cages, 25 chickens in each cage is therefore 25 * 53 = 1325.

Too much.

Regarding the divisibility problem, no!

Too much, right?? How many points do you want to give first??

Amateur type Local tariff Foreign tariff.

Within the first 100 grams, each weighing 20 grams.

Less than 20 grams will be counted as 20 grams].

The renewal weighs 101 to 2000 grams and weighs 100 grams each.

Less than 100 grams will be counted as 100 grams].

The first is that the waifu tariff is or.

The letter weight is 120 grams, and there are 20 grams beyond 100, which meets the second criterion.

More than 20 grams, although less than 100 grams, but also charged according to 100 grams, so the 20 grams need yuan.

And there's another 100 grams in 100 grams that meet the first criterion.

Every 20 grams of dollars so 100 grams need dollars.

A total letter itself needs meta.

It costs 3+ yuan in total.

The cost of less than 100 grams is yuan

The weight over 100 grams = 120-100 = 20 grams, and the cost of the part exceeding 100 grams is yuan

A total of dollar postage is required.

The least common multiple of a, b, and c is 60, the greatest common divisor of a and b is 4, and the greatest common divisor of a short b and c is 3

There must be a multiple of the values of a, b, and c, and in order to make the minimum value of a+b+c, we can obtain:

Not a multiple of 5, b = 12

2.Let c be a multiple of 5, then c=15, a=4, a+b+c=31 is a multiple of 5, then the dust is blind a=20, c=5 at this time, a>b+c, so discord is a.

Therefore, the minimum limb reserve of A+B+C is 31

Because abc is an integer, the greatest common divisor of A,B is 4,b,c The greatest common divisor is 3 So we can know that the factor of b must contain 3 and 4 But to make a+b+c the smallest, then we must take Wang Chun 12

A and b have the greatest common divisor of 4, so a must be a multiple of 4, so you can take 4, 8, 12, 16 ......But to make a+b+c the smallest, then you have to take 4

b and c have the greatest common divisor 3, which can be taken as 3,9, but 3+4 less than 12 cannot form a triangle, so c takes 9

4+9 12 So you can form a triangle, so a+b+c has a minimum value of 25

It's good, don't rob your points.

There are already people, but there are 2 answers, a simple analysis should be 31, 25 that says c is 9, but the common multiple of the three is 60

There are 8 people in the third group of Class 3 (2) of the experimental primary school, and a total of 144 yuan was donated in the donation activity for the disaster area, how much yuan did each group donate on average?

144 8 = 18 yuan.

The circumference of a square is 112 centimeters, what is the area of this square in centimeters?

Area = Side Length * Side Length = (Perimeter 4) * (Perimeter 4) = (112 4) * (112 4) = 28 * 28 = 784

There are a total of 120 students in the fifth grade, divided into 3 classes, each class has an equal number of 2, and each class is divided into 4 study groups, how many people are in each study group on average?

Group size = class size 4 = (total number of 3) 4 = (120 3) 4 = 10 people.