Hurry, hurry!! About C51 MCU programming and application solutions, I hope there are experts to help

Updated on technology 2024-05-22
3 answers
  1. Anonymous users2024-02-11

    Do you want a physical object? I do MCU design.

  2. Anonymous users2024-02-10

    Hello! Is it a 4-bit or 6-bit digital tube?

  3. Anonymous users2024-02-09

    Summary. Hello dear. We'll be happy to answer for you; Dear, to realize that the single-chip microcomputer continuously sends 0-9 to the PC, use the serial port mode 2 and use the even check, you can follow the steps below:

    1.Set the baud rate of serial port 2 to 9600. Since the crystal frequency is, the prescaler value of the baud rate generator can be calculated using the following formula:

    Baud rate = crystal frequency divider value 32) divider value = crystal frequency baud rate 32) In this example, the divider value = 9600 32) Select the nearest integer value 36 as the divider value. 2.Set the working mode of serial port 2.

    The data sent as needed is 0-9, and even check is adopted, which can be set to 8-bit data bits, even check mode. 3.Write a program that sends data from 0 to 9 in a loop.

    You can use a loop, sending one number at a time, with a delay of some time after you finish sending. Here's an example in C**: C include define baudrate 9600void init serial()void serial send(unsigned char data)void delay()void main(){unsigned char i; }

    Assuming that the crystal oscillator is, the baud rate is 9600

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    Assuming that the crystal oscillator is, the baud rate is 9600

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    What if the other conditions remain unchanged and become a strange check.

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    So how does that change?

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    Assuming that the crystal oscillator is, the baud rate is 9600

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    Assuming that the crystal oscillator is, the baud rate is 9600

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

    Assuming that the crystal oscillator is, the baud rate is 9600

    The C51 program wants to realize that the single-chip microcomputer continuously sends 0-9 to the PC, and tries to use the serial port mode 2 to achieve, and adopts even check.

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