A Level 2 VB question, ask for advice!

private sub command1_click()(100, -100)-(100, 100)dim x%, y%

x = int((rnd - 200)y = int((rnd - 200)if x > 0 then

if y > 0 then

msgbox x & "," & y & "First"

end if

if y < 0 then

msgbox x & "," & y & "Fourth"

end if

elseif x < 0 then

if y > 0 then

msgbox x & "," & y & "Second"

end if

if y < 0 then

msgbox x & "," & y & "Third"

end if

end if

end sub

How could it not be used... I put it on after I tried it.

If you studied analytic geometry in high school.

If you've learned the basic conditionals of VB, then the question is obviously pediatric.

Take a center point, draw a coordinate axis, and find the angle of the point. Then judge: 0-90:

First Quadrant. 90-180: Second quadrant.

180-270: Third quadrant. 270-360：

Fourth Quadrant.

Just use if.

if x<0 x>0

if y<0 y>0

Finally, it is enough to judge the axis.

Question 1: No matter how many case clauses meet the condition, only the statement after the first case clause that satisfies the condition will be executed. In this case, case 1 to 20 is the first clause that satisfies the condition, so the program executes the x = 10 statement and jumps to the end select statement.

Question 2: Since the num variable is declared as integer, it will be automatically converted to the integer value 2 when added, and then the addition operation will be done.

Question 3: Since the loop condition is loop while, the value of the expression that follows it must be true in order to continue the loop. But a has a value of 7, so the loop ends, which means that the loop body only runs once.

Question 4: Although X is declared at the process level, since X is declared with static statements, the scope of X is global. That is, x is also valid in the function f.

In the function f, x is assigned a value of 20, and the value of x remains 20 after the function is called.

Question 5: Since the variable x in the process fun is passed by value (byval) instead of by address (byref), the variable x is a new variable in the fun process, but it is initially given the value of the variable x in the call process, and when the fun process is over, its x variable also dies. Therefore, the value of the variable x in the command1 click process is still 10.

7. A and B (I have been looking at them for a long time and found that these two answers are exactly the same).

8、c9、a

10、d

Answer to this question: a

xa and a=b is a logical expression, and the value of the logical expression can only be true or false, because x=2, y=5, so x