Mathematical tricks to solve four problems

1, original = 125 8 11 4 101 25 1000 11 100 101 11000 10100 21100

2, original 32 440 68 440 (32 68) 440 44000

3, original 79 79 1 22 79 100 79004, original 25 57 42 1 25 100 2500

I don't understand.

4.(x-3) is greater than 0 in square +1, and when x = 3, there is a minimum value of 1

9999*5556+6666*6666

The final number is: 8 (2004) 71 (2004) 2

There is no result for this question.

Because 1+2+3+4+5+6+7+8+9=45, if you arbitrarily fill in the minus sign in between, what is subtracted is twice the original number, e.g. 1+2-3+45+5+6+7+8+9=45-6=39, so arbitrarily filling in the minus sign results in an odd number, and 10 is an even number, so it cannot be calculated.

One. =9999*(5555+1)+36*1111^2=9999*5555+9999+36*1111^2=45*1111^2+9999+36*1111^2=(45+36)*1111^2+9999

2.Original formula = (2000-15) (2000 + 15) = 2000 -15 = 4000000-225 = 3999775

2004 8s multiplied by 2004 9s equals.

2003 8 with 1 7 with 2003 1 with 1 2 two can not be because the front is 5 odd and 4 even.

No matter how you add plus minus signs, the final number must be odd.

So it can't be equal to 10

(-1 10) to the power of -2 + ( to the power of 0-

5 of 2016 to the 5th power of 2016.

1 2 5) to the power of 2016.

5 2) to the power of 2016.

x+2）²-x+1）（x-1）+（2x-1）（x-2）=x²+4x+4-x²+1+2x²-5x+2=2x²-x+7

x²（x-y）+（y-x）

x²(x-y)-(x-y)

x-y)(x²-1)

x-y)(x+1)(x-1)

What do you want to count? trace=41,determinant=520,inverse matrix is characteristic polynomial, and the feature polynomial is the solution.

The condition number is.