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Anonymous users2024-02-111) If there are x people transferred to the library, then there are 15-x people transferred to the laboratory, the total number of people who go to the library is 26+x, and the total number of people who go to the laboratory is 19+15-x=34-x. According to the question, 26 + x = 2 * (34-x), the solution x = 14, and 14 people were transferred to the library.
2) Definitely not If so, there are only 11 people on standby in the classroom, and even if all of them are transferred to the library, the total number of people who go to the library is only 37, which is not twice the total number of people who go to the laboratory. If you have to transfer some people from it to the lab, then there is no double amount So, this kind of distribution will definitely not work. If you want to make more sense, you can solve negative numbers by following the equation in the first question, then it can also be explained that it is impossible
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Anonymous users2024-02-101) X number of people were transferred to the library, and 15-x people were transferred to the laboratory.
Column equation: 26+x=2 [19+(15-x)]26+x=68-2x
26-68=-3x
x = 142) x people were assigned to the library and 11-x were transferred to the laboratory.
Column equation: 26+x=2 [19+(11-x)]26+x=60-2x
26-60=-3x
x=34/3
Can't have 34 3 people No.
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Anonymous users2024-02-09(1) In the second year, you need to pay a house payment of 10,000 yuan. x = 5 + 120 - 40) *5% = 5 + 4 = 9 (10,000 yuan).
2) If you need to pay 10,000 yuan in the first year of y, the total arrears in the year before y should be 120 - 40 - y - 2) * 5, and it is known that the total amount to be paid in the current year is 10,000 yuan, and the equation has 5 + 120 - 40 - y - 2 ) 5 ] Solve the equation to get y = should be greater than or equal to 2, then the equation can be established.
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Anonymous users2024-02-086.Relief spine width: Rotten field shelter x hours to meet.
40x=360 - (Hungry 60)*60x=
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Anonymous users2024-02-07Step 1: Move.
The second step is to merge filial piety and similar items x=
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Anonymous users2024-02-06Car 23 tons.
8 hours.
Ton. 24 people process pants.
16 people produce screws and 16 people produce nuts.
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Anonymous users2024-02-05Solution: Solution 1: If Wang Qiang ran x meters at a speed of 6 meters per second, then he ran (3000-x) meters at a speed of 4 meters per second
According to the equation of the question: x 6 + 3000 - x 4 = 10 60 to remove the denominator to obtain: 2x+3 (3000-x) = 10 60 12 to remove the parentheses to get:
2x+9000-3x=7200 Shift: 2x-3x=7200-9000
Merge the same kind of terms to obtain: -x=-1800
The coefficient of transformation is 1: x=1800
Solution 2: Suppose Wang Qiang ran at a speed of 6 meters for x seconds, then Wang Qiang ran at a speed of 4 meters for (10 60-x) seconds
According to the equation 6x+4(10 60-x)=3000, remove the parentheses: 6x+2400-4x=3000 and move the term to obtain: 6x-4x=3000-2400
Merge similar items to obtain: 2x=600
The coefficient of 1 is 1: x=300, 6x=6 300=1800 Answer: Wang Qiang ran 1800 meters at a speed of 6 meters per second
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Anonymous users2024-02-04If Wang Qiang ran x meters at a speed of 6 m s, then 4 m s ran 3000-x m, so the time is x 6 + (3000-x) 4 = 10 60x 6 + 750 - x 4 = 600
x/12=150
x=1800
Answer: Wang Qiang ran 1800 meters at a speed of 6 meters.
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Anonymous users2024-02-03Let Wang Qiang run x meters at a speed of 6 meters s.
Then 4*[10*60-(x 6)]+x=30002400-(2x 3)+x=3000
x/3=600
x=1800
So Wang Qiang ran 1800 meters at a speed of 6 meters.
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Anonymous users2024-02-02Solution: (1) The first cross is composed of 4 basic figures, namely: 1+3 1
The second cross is made up of 7 basic figures, namely: 1+3 2
The third cross is made up of 10 basic figures, namely: 1+3 3
Therefore, the k-th cross is made up of (1+3k) base figures. This is a series of equal differences.
The formula for summing the difference series: (first number + mantissa number) number of terms 2
Suppose 2012 figures can form x crosses, and the xth cross is composed of (1+3x) basic figures.
The total number of base figures contained in these x crosses is: x[4+(1+3x)] 2 2012
x is the largest positive integer satisfying the inequality, x=35
At this point, there are a total of 35 complete crosses, and the 35th cross consists of 106 base figures.
The total number of basic figures contained in these 35 crosses is: 35 [4+(1+3 35)]=1925 (pieces).
The 36th cross is composed of 109 basic figures, 1925 + 109 = 2034 (pieces), which is greater than 2012 and also greater than 2014.
Then 2012 basic figures can only form 35 crosses, and 2014 can only form 35 crosses.
You don't need to solve this inequality in a tedious way, just substitute the integer into the calculation and satisfy the equation.
2) Let the side length of the square be x m, then the circumference of the square is 4x m, and the perimeter of the rectangle is ( m.
Then the sum of the length and width of the rectangle is ( m, and the length of the rectangle is: 2 3 ( m.
The length of the rectangle is longer than the length of the sides of the square, then there are: 2 3 (
To solve this equation, we get: x=
Answer: The side length of the square is.
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Anonymous users2024-02-01Let a total of x crosses be formed, then.
The number of crosses contains the number of crosses.
No. 1) (number of base figures).
3 104 135 16...x ？
The number of basic figures and the number of crosses have the following rules:
The number of crosses contains the number of crosses.
No. 1) (number of base figures).
1 3*1+12 3*2+13 3*3+14 3*4+15 3*5+1...x 3*x+1x crosses by =(3*1+1)+3*2+1)+3*3+1)+3*x+1
3(1+2+3+..x)+1*x ( 1+2+3+..x)=(1+x)x/2)
3(1+x)x/2+x
3x(x+5) 2 composition.
3x(x+5) 2 hand(x=1,2,3,4 .Substitute compared to 2012.
x=35 The total number of base shapes is 2100x=36 The total number of base shapes is 2214 2 Let the width of the rectangle be x, then the length is 2x, and the side length of the square is (the perimeter of the rectangle is (2x+x)*2 The side length of the square is (the sum of their perimeters is the total length of the wire: (2x+x)*2+( Solve the equation to get x=so the side length of the square is meters.
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Anonymous users2024-01-313x2012+1=6037
3x2014+1=6043
The first graph is 1x3+1=4
The second graph is 2x3+1=7
The third graph is 3x3+1=10
And so on, the nth graph is 3n+1
Substitute n = 2012 and 2014 to calculate it. Rice.
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