Math Problem Today there are five cows, two sheep, and ten taels of gold. Two cows, five sheep, eigh

Solution: Set the cow x gold sheep y gold.

There are systems of equations. 5x+2y=10 ①

2x+5y=8 ②

Result: 5x=10-2y

x=(10-2y)/5 ③

Bring in 20-4y) 5+5y=8

y=20/21

Bring y=20 21 in

Get x = 34 21

So the solution of the original system of equations is x=34 21

y=20/21

Answer: Cattle and sheep are each straight gold 34 21, 20 21

Hope it helps

If you don't, you can discuss it.

Good luck with your studies (o).

Cattle. 5. Sheep two, straight gold ten taels, then (at the same time*2) ox 10, sheep 4, straight gold 20 taels.

Cattle. 2. Sheep five, straight gold eight taels, then (at the same time*5) ox 10, sheep 25, straight gold 40 taels.

Use 40-20=20 (taels) to find the money for 21 sheep.

20 21 = 20 21 (two) Find the money for 1 sheep.

10-20 21 *2) 5 = 2 3 (taels) Find the money of a cow.

Let the ox be worth x gold and the sheep be worth y gold.

5x+2y=10

2x+5y=8

Multiply by 210x+4y=20

Multiply by 510x+25y=40

y=20/21

x=34/21

Do it with binary equations.

Ancient arithmetic: "There are cows today."

Fifth, two sheep, worth ten taels of gold; Cattle.

Second, sheep five, worth eight taels of gold What is the value of cattle and sheep? "Please read the meaning of the question, this question is from the "Nine Chapters of Arithmetic" It means: 5 cows and 2 sheep, a total of 10 taels of gold; 2 cows and 5 sheep are worth 8 taels of gold How much are each a cow and a sheep worth of 8 taels of gold?

A cow is worth gold x taels, and a sheep is worth gold y taels, according to the title, it has to be solved.

Equation: 5x+2y=10

2x+5y=8 solves the system of equations composed of , 2 yields: 10x+4y=20

Get: 10x+25y=40

Get: 21y=20

Solution: y=20 21

Put y=20 21

Substituting gets: x=34 21

So, each cow is worth it"Kim"

2. Set the value of each sheep"Kim"

20 21 taels.

5x+2y=12

2x+5y=9

3(x-y)=3

x-y=1x=y+1

2(y+1)+5y=9

7y=7y=1

x = 2 cow scum steak Zheng is worth 2 gold Rusong, and sheep is worth 1 gold for this ante.

Hello, each cow is worth x two "gold", each sheep is worth y two "gold", according to the title Lu Wu has {5x+2y=10,2x+5y=8 solution answer: each cow is worth two "gold", each sheep is worth two "gold".You can directly set the equation according to the disturbance problem, please refer to it!

Solution: Let each cow be worth x taels, then each sheep is worth (10-5x) 2 taels, then 2x+5* (10-5x) 2 = 8

x=34/21

Answer: The ox is worth 34 21 taels, and the sheep is worth 20 21 taels.

Solution: Let each cow be worth x taels, then each sheep is worth (10-5x) 2 taels, then 2x+5* (10-5x) 2 = 8

x=34/21

10-5x)/2=20/21

Solution: Let the ox be worth x taels and the sheep be worth y taels.

5x+2y=10

2x+5y=8

Multiply by 210x+4y=20

Multiply by 510x+25y=40

Use 10x+4y=20-10x+25y=40 to get y=20 21

Put y=20 21 generations 5x+2y=10

Get x = 34 21

So the solution of the group of the original equation is y=20 21 and x=34 21

From the first sentence: the sheep is (two.

From the second sentence, we can get it: 2x+5(

x=34/21

Answer: Ox straight 34 21 taels, sheep straight 20 21 taels.

Solution: Let the ox value x tael, the sheep value y tael, and the column equation system obtains:

5x+2y=10

2x+5y=8

The solution is x=34 21, y=20 21

Well, it should be a cow for x two straight gold.

then the sheep is (10-5x) 2 taels of straight gold.

2x+(50-25x）/2=8

34 21 for cattle and 25 21 for sheep

The ox is two, and the sheep is two.

5a+2b=10（1）

2a+5b=8（2）

7a+7b=18

a+b=18/7（3）

3a-3b=2

a-b=2/3（4）

2a=18/7+2/3

2a=68/21

a=34/21

b = a-2 3 = 34 21-2 3 = 20 21 21 taels for cattle and 20 21 taels for sheep.

Let the value of the cow a and the value of the sheep b , then.

5a+2b=10

2a+5b=8

So a = 21 molecule 34, b = 21 molecule 20

5x+2y=so the ox is worth 34 21 taels. The sheep is worth 20 21 taels, ask....

Solution: Let each cow be worth a gold, and each sheep worth b gold, and the system of equations can be listed according to the meaning of the question

5a+2b=10

2a+5b=8

Solve this system of equations, get.

a=34/21

b=20/21

Answer: Each cow is worth 34 21 gold, and each sheep is worth 20 21 gold.

Cattle. Five, two sheep, ten taels of straight gold.

Cattle. Second, sheep five, straight gold eight taels.

Cattle. Seven, sheep seven, straight gold eighteen taels.

Cattle. 1. Sheep one, 18/7 taels of straight gold.

Ox = (10-18 7*2) 3=34 21 (taels) Sheep = (8-18 7*2) 3=20 21 (taels).

Set ox x gold, sheep y gold.

Niu five, sheep two worth ten taels, that is, 5x+2y=10, the bureau is sold as a formula.

The cow takes the jujube two, and the sheep is worth the gold and eight elimination of the wax and splits the two, that is, 2x+5y=8, which is recorded as the formula.

For a system of simultaneous equations, multiply by 2 - multiply by 5 to get y=20 21, and bring in equation x=34 21

Therefore, 34/21 gold for cattle and 20/20 gold for sheep are still expensive!

5 cattle 2 sheep = 10 taels.

2 cattle 5 sheep = 8 taels

Get. 5 cattle 2 + 2 sheep 2 = 10 taels 2

That is, 10 cattle + 4 sheep = 20 taels in the spring of the first draft

Get. 2 cattle 5 + 5 sheep 5 = 8 taels 5

That is, 10 cattle + 25 sheep = 40 taels

Get. 21 sheep = 20 taels. Sheep.

Bull 34 21

In the end, it turned out that Yinnai was a score of respect, which was really troublesome.