Does CH3 R have to be a tetrahedral structure

Not necessarily! If it's an H atom, it certainly is.

But if it is other atoms, then the bond length is not consistent with the c-h bond length, and it is not a tetrahedral.

If it is an H atom, it must be a tetrahedral structure, which is CH4.

If it is other atoms, then if the bond length is not equal to the c-h bond length, it is not a tetrahedron, but it is still a tetrahedron.

r is an atomic time.

It must be a regular triangular pyramid.

It is a tetrahedron when it is h.

Only CH4 is a tetrahedron, because they are all C-H bonds, the bond length is the same, if R is not H then it is not a tetrahedron.

Based on the valence bond theory, it can indeed be considered that the derivatives of methane have certain tetrahedral structural characteristics. However, it should be noted that the valence bond theory is more or less from a static point of view, and believes that the molecule has a certain geometric structure, or an average over a period of time.

But strictly speaking, except for solid crystals, where atoms are bound to vibrate in a certain space, fluid molecules do not have a fixed geometric structure, especially rarefied gases at high temperatures.

That is, the bond is not rigid.

With the gradual acceptance of quantum mechanics by various disciplines other than physics, it has become a common recognition to look at the microscopic world from a quantum perspective, that is, to describe the state of the system in the form of wave functions, to describe the characteristics of the system in terms of energy, and to describe the way it is presented in front of people's eyes with probability. It's incredible, but it's closer to the truth.

The length of the covalent bond is determined by the electronegativity and atomic radius of the bonding atoms.

So it is clear that if R is an H atom, then the four bonds are equal in appearance and have exactly the same relative positions, and the molecule must be a tetrahedron;

If it is an atom other than H, then the bond length is obviously not equal, but the three C-H bonds are exactly the same, so it is a regular triangular pyramid.

The structure of the CH4 is Zheng Lu style.

h|h-c-h|h。Methane.

The name of the system is "Carbon", but only the nomenclature of the system is introduced.

Methane is the simplest organic matter, the main component of natural gas, biogas, pit gas, etc., commonly known as gas.

The structural formula is a chemical composition formula that represents the arrangement and binding of atoms in the molecule of a compound (or element) with a high band element symbol and **. is a simple way to describe the structure of a molecule.

Summary. Hello, the conclusion is that there is no octahedral configuration, only a pentahedral configuration. Co(NH3)6]3+ has a regular octahedral structure with six vertices, four NH3 molecules are square, the CO atom is in the center of the square, and the other two NH3 molecules are directly above and below the square, respectively, to form a regular octahedron.

Two NH3 molecules are replaced by Cl- and H2O respectively to form [Co(NH3)2Cl2(H2O)2]3+, six vertices, and three groups, set as ABC, the first type is the same group with CO atom as the symmetry center, regardless of optical isomerism, there is only one; In the second category, the upper and lower vertices remain unchanged based on the first type, only the square is changed, and there is only one change, that is, the same groups in the original square are adjacent, because there are three groups, so there are three geometric isomers in this class; In the third category, all the same groups are adjacent, and there is only one isomer regardless of optical isomerism.

Does CR(NH3)6] 3+ have regular octahedral configuration and why.

Hello, the conclusion is that it does not have an octahedral configuration, only a pentahedral configuration. Co(NH3)6]3+ has a regular octahedral structure with six vertices, four NH3 molecules are square, the CO atom is in the center of the square, and the other two NH3 molecules are directly above and below the square, respectively, to form a regular octahedron. The two NH3 divisions are replaced by Cl- and H2O respectively to form [Co(NH3)2Cl2(H2O)2]3+, six vertices, and three groups, set to ABC, the first type is the same group with CO atom as the symmetry center, regardless of optical isomerism, there is only one; In the second category, the vertices of the upper and lower limbs of the first type are unchanged, only the square is changed, and there is only one change, that is, the same groups in the original square are adjacent, because there are three groups, so there are three geometric isomers in this class; In the third category, all the same groups are adjacent, and there is only one isomer regardless of optical isomerism.

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Methane, chemical formula CH4, is the simplest hydrocarbon, which is composed of one carbon and four hydrogen atoms by the way of sp2 hybridization, so the structure of the methane molecule is a regular tetrahedral structure, and the bond length of the four bonds is the same and the bond angle is equal. In its standard state, methane is a colorless and odorless gas. The biogas produced when some organic matter decomposes in the absence of oxygen is actually methane.

Theoretically, the bonding formula of methane can be expressed as a point "·" But I haven't actually seen this usage, probably because of "·" The number can also represent electrons. That's why methane is considered unbonded in secondary school.

1 methane molecule contains 1 C and 4 H atoms, the molecular formula is CH4, the outermost shell of the carbon atom has 4 electrons, the outermost shell of the hydrogen atom has 1 electron, a carbon atom forms 4 pairs of shared electron pairs, and a hydrogen atom forms a pair of shared electron pairs, so the electronic formula is:

a Since the bond energy of the four carbon-hydrogen bonds of methane is also equal when methane is a planar square structure, it cannot be judged that methane is a regular tetrahedral structure, so a is wrong;

b Methane, whether it is a tetrahedral structure or a square, there is only one structure of the CH3Cl molecule, and the structure of methane cannot be judged, so B is wrong;

c Methane has only one type of CHCL3 molecule, whether it is a tetrahedral structure or a square, which does not mean that the molecular structure is tetrahedral, so C is wrong;

d If it is a planar square structure, there are two isomers of dichloromethane, while there is no isomer of dichloromethane in tetrahedral, indicating that the molecular spatial structure of CH4 is tetrahedral, so D is correct;

Therefore, choose D

a. The carbon dioxide molecule is a linear structure, so a is wrong;

b. All atoms of benzene molecule are coplanar, and all benzene is a planar structure, so B is wrong;

c. The molecular structure of methane is a tetrahedral structure, so C is correct;

d. Ethylene is a planar structure, and all atoms in the ethylene molecule are coplanar, so D is wrong;

Therefore, C

3. All a, carbon dioxide molecules are linear structure, so a is wrong;

b. All atoms of benzene molecule are coplanar, and all benzene is a planar structure, so B is wrong;

c. The molecular structure of methane is a tetrahedral structure, so C is correct;

d. Ethylene is a planar structure, and all atoms in the ethylene molecule are coplanar, so D is wrong;

Therefore, C