A simple relativity problem, 20 points! , thank you 20

I think it's a matter of conventional thinking.

We see that the snail climbs very slowly, but it does not necessarily think of itself as slow.

We are born in such a space, and we are taught that the speed of light is insurmountable, and that time cannot be reversed.

But in antispace, the speed of light is the lower limit of speed, and time is distorted, which is completely different from the way we think.

If you put that aside, this problem is not a problem.

In fact, you can understand it this way, the two times are actually synchronized, but in A's opinion, A's own time passes faster than B's, and B's view, A's time also passes faster than B's.

On the first floor, the thing you connected to is ridiculous, using the theory of classical physics to deny macroscopic physics and microscopic quantum, and also denying the wave-particle two-image nature of light, and always only taking one of the particle properties or wave properties of light in the discussion to calculate, it will naturally come to absurd conclusions.

On an object that moves at the speed of light, time is not slow, but it exceeds the speed of light, for example, in a supersonic airplane, it's not that the sound is slow, it's that it moves in front of the sound, so I think the reference object is like a supersonic plane and a sound

I think there is a reference at this point in time, and everything is relative

You can't use the time of common sense to understand the time mentioned in the theory of relativity, and what the landlord says is only the time of subjective consciousness.

Einstein's second hypothesis.

Time and space.

Unlike the special theory of relativity, which is the shrinkage effect, the same is true of time, and the time interval is relative.

In classical mechanics, if two times are observed in different frames of reference, their time intervals are always the same, for example, if a pendulum swings from one end to the other, and the person performing the test next to it records the time of 1s, then the person who flies over the laboratory in an airplane measures the time of 1s. However, according to the special theory of relativity, the time measured by the two is not the same, as in the case of the time given, the Earth clock is 20 years, but the spacecraft is 12 years.

Give you a formula to check for yourself to see if what I said is correct. △t=△t/[1-(v/c)]^

That's what you do according to the special theory of relativity.

Spacecraft and Earth are not equal in the special theory of relativity, with the former being (in general) non-inertial frames and the latter being inertial frames.

Because it is necessary to use the principle of ruler reduction to calculate the two events corresponding to the two ends of the so-called ruler at the same time, but in the view of the spacecraft system, the two events of the light pulse reaching the stern and reaching the bow of the ship are not the same time, because t'=90/

So it can only be done with the Lorentz transform:

The spatial interval between the two events measured by the Earth system x= ( x'+v△t'）=5/3×（90+。

Definitely not! I take the observer on the train as my standard. Two events that appear to be simultaneous on the ground (in this case, two bolts of lightning striking the mouth of the tunnel at the same time) do not appear to be simultaneous on a moving train.

So what kind of phenomenon does an observer on the train seem? Due to the movement of the tunnel (note, the point of view of the train), the tunnel became shorter! When the locomotive reaches the bottom of the tunnel, that is, when there is still a section of the train outside the tunnel.

A bolt of lightning struck the bottom of the tunnel, and the train was safe. When the rear of the train was all in the tunnel, another lightning bolt came. Safe.

It doesn't matter if the train is struck by lightning, the train is iron, the track is also iron, and it has reached the earth, whether there is it or not, it is fine!!

Einstein's theory of relativity knows that time is relative to the land, and the faster an object moves, the longer the time it perceives.

The formula for change is t=t'The root number (1-v2c2), where t is the time perceived by motion physics, and t'It's the time it seems.

v makes the velocity of the object.

Here we find t = root number celery buried (1-(

The distance is s=vt=10500m>8000m, so it can reach the ground, of course, this is done without considering air resistance. In fact, these rays are avoidable due to the presence of the atmosphere.

There is also a physical quantity missing, the relative velocity of the two frames of reference, assuming that V is in S, the transverse length is LCOS, and the vertical length is LSIN, in S', the transverse length is LCOS (under the root number (1-v*v c*c)), and the vertical length is LSIN

The total length is the result of the synthesis of the two, and the tangent of the angle is the vertical length divided by the transverse length.

This is Einstein's patent.