A few questions about math sets, about math sets?

1. (1) If a=empty set, then the unary quadratic equation x mx+3=0 has no solution. That is, the discriminant formula is less than 0

m）^2-12<0

Solution: -2 32}

cr b={x x<-3 or x>2}

cr b a={x x<-3 or x -1}2) should be c and contain a

With the help of the number line, it can be concluded that a should be to the right of -1, that is, a -1, that is, the set of values of a is {a|a≥-1｝

1. x mx+3=0 has a solution.

b²－4ac≥0

m²-12≥0

m 12m 2 plant 3 or m -2 plant 3

The set of b is x=3 substituting a

9-3m+3=0

m=4a is x -4x+3=0

x-3）（x-1）=0

x=3，x=1

a=﹛1,3﹜

2、u=a+cua=(-3，-1,0,1,2,3,4,6) b=u-cub=（-3,1,3,4,6）

3. A is y= x 1 1

The minimum value of y is -1 and a is x -1

b is -3 x 2

ANB is -1 x 2

cr(anb)=(x -1 or x 2);

crb=（x＜-3，x＞2）

crb)ua=(x -3 or x -1).

2) If the question is correct, you can't solve it, how to get C bigger than A.

If it is contained in then cna=c

a≥-1

{0,-1,1} is included in {-1,0,1}

That's right, collections are disordered.

0,0)} is the set of points.

And {0} is a set of numbers, so it is not equal.

Note: {(0,0)}

and {0} are not empty sets.

{0,-1,1} is included in {-1,0,1} and rightly .

The elements of 0,0)} are (0,0) and an empty set.

0} is:

0 and empty sets. So wrong.

You go to the book and read the definition.

Set a = Set B condition.

The first, equal, is therefore also included in, and the second element of the set on the left is a point, and the element of the set on the right is a number, so it is unequal and is wrong.

For sets, although -1, -2, and -3 do not belong to 0, then the set does not have the property p

For sets, 1, -2, -3 do not belong, so the set has the property p

So s=so t=

Yes, because the meaning of can be less than or equal to.

2 3 3 3 3 are all correct.

So a+1 x where a+1 can be equal to x x x can also be equal to 2a-1, so a+1 can = 2a-1

Yes, a+1=2a-1, a=2, a+1=2a-1=3, and there is only one element in the set that is a=

1.[a,a) denotes an empty set. i.e. [0,0] does not include 0

2.[5,3] and [3,5] are not equivalent. [5,3] is -5 x 3, which also means an empty set.

It should be that x is unknown, i.e. a variable, and any x that satisfies x a is desirable. So, b={0,1}.

Hopefully the answer is preferable.

Because the math multiple-choice questions are chosen. b={x x a} means that b includes all the elements in a.

X a means that x is an element in a, and x a means that x is a subset of a.

Let x 2+2x-3=-x 2+2x+15 get x 2=9, and because x n, get x=3.

Bringing x=2 into the equation of the set, we get a b==. It can be brought into another equation to prove that the result is correct. It is important to note that the elements in the set are y, not x.

Sure the topic is correct, it seems that there is a problem.

Solution: Since x belongs to n, the solution is a= and b= (both are easiest to multiply by cross), so a intersects b=

1.It's x -5x+6=0 and his solution is x1=2, x2=3 so the set a=

If b is a true subset of a, then m may be 1 2 and 1 3 m = 2There are several combinations x=2x y=y2; x=y2 y=2x (assuming y2 is y's square).

x1=0 y1=0;x2=0 y2=1;x3=1/4 y3=1/23.I rely on this, there are a lot of combinations, see 2

A: Don't always take the balance into the pants to stop the dust.

b: [a*(b*a)]*a*b) =b*(a*b) =ac: b*(b*b) =b

d: mark c=(a*b), a*b)*[b*(a*b)] c*[b*c] =b