6th grade math problems help solve the process of doing so

Let's find the indicator first:

t) and then find the amount of another plan to complete:

15·182%=tons).

Excess amount: tons).

2.If there are x ducks, then there are (x+24) geese and chickens.

3x+18) only, according to the meaning of the equation:

x+24）=50%·（3x+18）

Solve x=30

Chickens have 3x+18=108 (only).

The goose has x+24=54 (only).

3.Let cucumbers have x baskets, beans have x (3 2), and eggplants have (76-x) baskets, according to the meaning of the equation:

x/（3/2）+x]·50%=76-x

Solution: x=32

The quota is: tons.

Another worker's excess: 15 * (182%-1) = tons.

There are 18 chickens 3 times more than ducks.

The goose is 50% of the chicken, then.

The goose is 3 * 50% = more than 18 * 50% = 9 ducks.

That is, the number of ducks plus 9 is 24 more than all the ducks.

Ducks have: (24-9) (only.)

There are 30 + 24 = 54 geese.

Chickens: 54*2=108.

5 6 of cucumbers is equivalent to 2 3 of beans

The beans are equivalent to cucumbers: (5 6) (2 3) = 5 4 The total number of cucumbers and beans is equivalent to cucumbers: 1 + 5 4 = 9 4 Eggplant is equivalent to cucumbers: 9 4 * 50% = 9 8

The total number of beans and eggplant is equivalent to that of cucumber: 9 8 + 5 4 = 19 8 cucumbers have: 76 (19 8) = 32 baskets.

1. Find the number of standard quotas first:

15*（182%-100%）=；Hence the excess ton.

2. Set x ducks, 3x+18 chickens, and x+24 geese.

3x+18)*50%=x+24 The solution is x=30 3x+18=108 x+24=54

30 ducks, 108 chickens and 54 geese.

3. Set beans x basket eggplant 76-x box cucumber 2 3 * x 5 6 = 4 5x76-x = (x + 4 5x) * 50% solution x = 40, 4 5x = 32 cucumber 32 baskets.

1.set to xt, then, x=

2.Let the chickens be x, the geese be y, and the ducks be z.

x=3z+18, y=50%x, z=y-24, solve the system of equations to get x=108, y=54, z=30

3.Set cucumber x basket, bean basket y, eggplant z basket, then have.

5x 6=2y 3, z=(x+y) 2, y+z=76, solve the system of equations to get x=32, y=40, z=36

ax-2by=-5c①

2ax-by=2c②

First *2- gives by=4c, then *2- gives ax=3c, because x=1, y=1, gives a=3c, b=4c, so a:b:c=3c:4c:c=3:4:1

2.If the original ** of selling jujube Kuan A is x yuan, and the original ** of B is y yuan, then there is a title to show the rock disadvantages, x+y=100, (1-10%)x+(1+5%)y=100(1+2%)

Solution, x=20, y=80

1.The sum of length, width and height is 216 4 = 54 cm.

Length 54 * 4 9 = 24 cm.

Width 54 * 3 9 = 18 cm.

Height 54 * 2 9 = 12 cm.

The surface area of this rectangle is (24*18+24*12+18*12)*2=1872 square centimeters.

The output value of the two factories is as follows:

6960*6 110,000 yuan, 6960*5,110,000 yuan.

3.Missing conditions.

4.At the time of the encounter, car A traveled 180 * 5 6 = 150 km.

The distance between the two places is 180 + 150 = 330 kilometers.

216 divided by 4=54 should be bad at math. , 4+3+2=954*4/9 = 24 almost. *It is multiplied.

54*3/9 = 18 Don't blame me for the miscalculation.

54*2/9 = 12 Uh-huh, write me to death.

6960 * 6/11 = Tooth ho. Except for the impurity.

6960*5/11. Do the math yourself.

Yes. I don't write it, in fact, I shouldn't give a specific rice, no conditions.

180 divided by 5=36 units to write speed units.

36*five-sixths = 30 units of velocity.

36+30)*5 = 330 should be miscalculated.

Yo Xi, it's gone.

That's it. Break, Ang.

Truck speed: 90 (8-6) = 45 km/h.

Distance: 45 15 = 675 km.

Number of parts produced by B: 36 = 90.

The original payment for the first time: 198 = 220

The original payment for the second time over 400 yuan: (462 - 400 = 102 = 120 yuan.)

220 + 400 + 120 = 740 RMB.

400 +340 = 360 + 289 = 649 RMB.

Question 1: 1 10 + 1 15) x = 1 x = 6 That is, they meet after 6 hours of travel, and the passenger cars travel 60% at this time

It can also be seen that trucks travel 90 kilometers and passenger cars travel 20%. Speed Passenger car: Truck = 3:2 So the truck travels 90 km, the bus travels 135 km.

135 = 20% x x = 675 km.

Question 2. Choose B, compare AB to know why B is wrong.

Question 3. A does 1 6 per hour, 5 12 hours for A, and B can do one per hour. Question 4.

Landlord, the question is not difficult, but for my sake, please chase the score.

Question 1 A Question 2.

Choose B, compare AB to know why B is wrong.

Question 3. A does 1 6 per hour, 5 12 hours for A, and B can do one per hour. Question 4.

Let B's velocity be x km, then A's velocity is (x+24) km/h.

Think of the length of the road as a unit of 1

x;(x+24) = 1/8 : 1/5

Solution: Let the speed of A be x km, the distance is 5x km, and the speed of B is 5 8 * x km, then.

x-5/8*x=24

Solution x=64

A has a speed of x km = 64 km/h, and B has a speed of 5 8 x x km = 40 kmh.

The sum of them is 64 + 40 = 104 kmh.

Let the total distance be x km.

The velocity of A is x 5 and the velocity of B is x 8, so x 5-x 8 = 24, i.e. x = 320

So A's velocity is 320 5 = 64 km, and B's velocity is 320 8 = 40 km.

The sum of speeds is 104 km/h.

v A: v B = 8:5, let A have a speed of 8x kilometers and B a speed of 5x kilometers.

8x-5x=24 x=8 v A+v B=8 (8+5)=104 (kmh).

Solution: Let the velocity of B be x km, then the equation can be listed when the velocity of A is (24+x) km: 5(24+x)=8x

Solution: x=40

24+x+x=24+40+40=104

With an inversely proportional solution, time is inversely proportional to velocity.

Solution: Let the speed of B be x kilometers and the speed of A is (24+x) kilometers, then we get 8x=(x+24)*5

x=4024+x=64

Since t A: t B = 5:8, V A: v B = 8:5

v A + v B = 8 * (8 + 5) = 8 * 13 = 104

1: Probably, according to the rounding rule, 155 and 165 are all about 160, so a height difference of 10 cm is possible!!

2:3 [10-(6-4)] or 3 6 + (10-4) or (10-3 2) (4 6).

3: Shift the term, mention the common factor x, then there is: x multiplied (2010/2011 minus 2011/2010 plus 2010 minus 1/2010 minus 9/2011) = 0, no need to calculate, get: x=0

4: accurate to one decimal place, 6 significant digits, respectively 4,0,0,0,0,0,0,5: It can be seen from the question that the average investment per game is (16 3 + 42 4) 2, and the average ** per game is k 3, then there is [(16 3 + 42 4) 2] (1 + 20%) = k 3, calculate it yourself.

6：|5x-3|=3-5x, the equation holds, indicating that 5x-3<=0, so there is x<=3 5

7: Get x 2/2 m, which means m<0

I would say it's not a ......... of elementary school

I'm here to watch LZ.

I only know that the first question is impossible, and I don't know the reason (Cha Du Niang's).

I also want to say that this question is not within the scope of middle school, it should be high school!!

1. Set the original length of the rope to be x meters.

x-5=60%x-1 x-60%x=-1+5 40%x=4 x=10

A: This rope was originally 10 meters long.

2. If there are x pear trees, then 80% of the apple trees have x trees.

x+80%x=450 180%x=450 x=250Answer: There are 250 pear trees and 200 apple trees.

3. Set the cost to x yuan.

140*90%*26%=140*26%-x x= x=

A: The cost is RMB.

1. (5+1) 60%=10 meters.

80% = 180% 450 180% = 250 --- pear trees 250 80% = 200 trees -- apple trees.

90%=126 yuan 126 (1+26%)=100 yuan1If you don't need to list equations, I'll give it to you.

Let the original length be x meters.

From the inscription, it gets: 60% x-1 = 5 meters.

Solution: x=10

1 . 2 .3 Do you want me to do the math for you?

1 Solution: Let the original length be x meters.

1-60%）x+1=5

x=102 pear trees: 450 (1+80%)=250 apples: 450-250=200 trees.

3 140 90% (1+26%) = 100 yuan, the main key to this kind of score application problem is to find unit one.

(1) Equation (2) 450 times 80% = ? 450-?=?No, yes, I won't be the third I am also in sixth grade.