51 single chip microcomputer serial port receiving for LCD display data error, wealth full delivery

There is a problem with the visual inspection of the LCD program, not the driving aspect Yes"Data Processing"。Give you a direction, take a good look for yourself.

Each time a byte transfer is completed, the RI is set to and an interrupt is made.

In other words, after sending 0, the program will immediately jump into the serial port interrupt.

In general, we will set up a buffer queue to store the data that has just come in in time, and set a flag to notify the status of the serial buffer of the main function.

sendchar1=(lednumval1%10);

send_char(sendchar1);

changed to sendchar1=(lednumval1%10+'0');

send_char(sendchar1+‘0’);

It should be sent as a string.

Baud rate inconsistencies.

It may be caused by a mismatch in the baud rate or too much error. It is recommended to try with a crystal oscillator, and change th1=0xf3 to 0xf4 to try.

Receive all the data first, and then separate the digits of each bit. Don't separate from side to side.

First of all, you have to determine what base code you are sending?

If you use this way to send VB data I phone, send ASCII code, for example, if the data sent is 123, the computer will send 0x31, 0x32, 0x33 continuously, so the MCU receiver program, you need to convert it again, you can try to send hexadecimal data in another way.

For the microcontroller receiver, because the amount of data you send is relatively small, and when sending data, the time interval between two adjacent data is also very short, you can receive data packets by query in the interrupt.

void serial ()interrupt 4 using 3}es=1;Reopening the serial port is interrupted.

Here you can make a flag bit that receives the array, which is used for the main program to query and process the relevant data mc=str[0];

n=str[1];}

void serial ()interrupt 4 using 3

If you receive the character '7', just subtract '0' to get the number 7, i.e. n=str[1] -'0'

Note that static method A will always be accumulated, and you need to add judgment when A should be reset to 0

For the first problem, a is assigned a value of 0 once every time an interrupt is entered, so only str[0] can receive the data, and uchar a; changed to static uchar a; Static variables can only be initialized once, so the second and nth interrupts cannot change the value of the previous time, but pay attention to the zeroing of a.

For the second, I don't know, I'm sorry.

Appropriate join delay for sending and receiving.

send_buf[79+15] = 'd';

send_buf[79+16] = 'r';

send_buf[79+17] = 'i';

send_buf[79+18] = 'v';

send_buf[79+19] = 'e';

Changed to: send buf[79+05] ='d';

send_buf[79+06] = 'r';

send_buf[79+07] = 'i';

send_buf[79+08] = 'v';

send_buf[79+09] = 'e';

In addition, these two sentences are faulty:

send_buf[79+22] = ('0';

send_buf[79+42] = ('0';

A quotient divided by 10 may be greater than 10.

I'm also looking for this kind of program.,I've tried the following C language program.,Whether it's using hex and character data to send data, it's displayed garbled on the LCD.。。。

I seem to have written it or seen it. Find out.

AD value, 51LCD display, correct or not?

The computer shows the AD value, is it correct?

The landlord himself will try it first.

When asking, make it clear what the problem is.