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35*34=1220；49*41=1609；82*88=7216；Rule: The first digit of the result is the ten digit of the first number (e.g., 3 in 35*34=1220) and the ten digit of the second number plus one (i.e., 3+1=4) multiplied to 12; The last two digits of the result are the first digits multiplied by the second digits, and the result is one or two digits, which is 5*4=20 in the above example, such as the second 49*41=1609, 9*1=09, so that the result can be calculated, 35*34=1220[12(3*4) 20(5*4)]; 49*41=1609（16 09）；82*88=7216（72 16）；

Got it, huh.

Answer It feels like elementary school math...

The last two digits are the product of two single digits, e.g. 23*27=2*2+2 and 3*7 to get 621, plus 0 in front of the singular number, e.g. 1*9=09

The first is a ten-digit result, plus a ten-digit number, such as 35*34=3*3+3 and 5*4, which gives 1220

If the two ten-digit numbers are multiplied, if they are the same ten, and the single digit digits are added to give ten, then the result of their multiplication is that the last two digits are equal to the product of the two digits added to the ten, and the preceding digit is equal to the square of the ten-digit number plus the ten digits themselves, such as 36*34=(3*3+3)*100+4*6=1224....67*63=(6*6+6)*100+3*7=4221

Number of small squares: 1 2 3 4 ·· 8 ）·n

Number of exposed surfaces: 5 9 13 ( 17 ) 33 · · 4n+1 ）

4 is 5*4-3=17. And so on 5 uses 5*5-4=21Use an exposed surface * the number of squares - (the number of squares - 1—) = the number of exposed surfaces.

19/55

The upper numerators are arranged in odd numbers, 2n-1

The lower denominator is equal to the sum of the first two denominators.

1/1,3/1,5/2,7/3,9/5,11/8,…, the numerator is 1 3 5 7 9 ...2n-1) The denominator is 1 1 2 3 5 8 and the 10th digit of the Pebonacci sequence is 19 56

It's 19 55, three adjacent numbers, and the sum of the denominators of the first two numbers is the denominator of the third number, and the numerator is always added by 2

These are two sets of data.

3,7,15,31 is a group, the rule: the latter number is twice the previous number plus 1, so 31x2+1=63;

4, 9, 16, 25 is a group, the law: respectively 2 to the 2nd power, 3 to the 3rd power, 4 to the 4th power, 5 to the 5th power, then the latter one is 6 to the 6th power, that is, 36

Let's look at the odd digits first: the first digit is 2 to the 2nd power minus 1, the 3rd digit is 2 to the 3rd power minus 1....And so on, the 9th place is 2 to the 6th power minus 1, i.e. 63; Similarly, the 2nd digit is 2 squared and the 4th digit is 3 squared.

So the last number is 6 squared, which is 36

3 4 7 9 15 16 31 25 63 36 This is a combination of two sets of arrays, 3 7 15 31 63 is a group, and 4 9 16 25 36 is a group.

1）-1,3,-5,7,-9...The nth number is (-1) n*(2n-1).

2) The fifth number is 242

3) 3 dots n=1....6 dots n=2....9 dots n=3 (I don't understand this question) rolls macros.

4) 1 2 1 5, 1 big brother 10, 1 17, 1 26...The nth number is 1 (n 2+1).

5）1 。3 3 。5 5 。a

5 。20 7 。56 b 。c

Then a = 7 b = 9 c = 108

It's all 495 in the loop

Answer: 327,732-237=495;954-459=495…；

So it's all 495 in the loop;

Let the three numbers be abc and a b c respectively

abc-cba = (a-1-c) (10 ten b-1-b) (10 ten c-a) then the three digits add up to 18, and because the ten digits are always 9

After subtraction, the items are m9n, mten, nine, ten, n=18, so mtenn=9, and after subtraction, it is m9n.

10 ten, n-9=n, ten, 1=m or n, so after an infinite loop, m-n= 1 is solved to get m=4, n=5 or m=5, n=4, so the last time it is reduced to 954-459=495

So the answer is 495

Subtracting the minimum from the maximum number gives the three digits that add up to 18

The newly obtained three-digit number is 0 in the middle, and the number in the hundred digit and the single digit are the same, and then subtracted to zero. Don't believe you!