The largest angle in any triangle must be obtuse, right, or wrong?

Wrong. Because it is an arbitrary triangle, then the triangle can be divided into obtuse triangles according to the number of degrees.

Right triangles and acute triangles. Right triangles and acute triangles have the largest angles.

Not obtuse angles.

Wrong, not necessarily, the maximum angle may also be a right angle or an acute angle, the inner angle of the triangle and 180 degrees, each angle is arbitrary, so the largest angle can be arbitrary.

Of course, this statement is wrong, how can there be obtuse angles in any triangle? Maybe this triangle is an acute triangle, and the biggest angle in them is also an acute angle! It is also possible that the triangle is a right triangle, and its largest angle is a right angle.

It is incorrect to say that the largest angle in any triangle must be obtuse.

The sum of the inner angles of a triangle is 180°, and a triangle may have an obtuse angle, but not all triangles have an obtuse angle. For example, the three corners of a triangle are °

This one is wrong. The sum of the inner angles of the triangle is equal to 180 degrees. If it's a right triangle. The biggest angle is the right angle.

The largest angle in a triangle is not necessarily obtuse, but can be a right or acute triangle.

Wrong, for example, in an equilateral triangle, the largest angle is also the smallest angle, both of which are 60 degrees.

This statement is wrong. The definition is not precise enough.

Wrong. What is the largest angle in a single right triangle? What is the largest angle in an acute triangle?

The answer to this question is wrong.

Acute triangle: Because the three inner angles are all acute angles, the outer angles correspondingly have three obtuse angles;

Obtuse triangle: Because one of the three inner angles is obtuse and the remaining two are acute, the corresponding outer angles have two obtuse angles.

Right triangle: Because one of the three inner angles is a right angle and the remaining two are acute angles, the corresponding outer angles have 2 obtuse angles.

To sum up: there are at least 2 obtuse angles in the outer corners of the triangle. ( Included in obtuse triangles and right triangles).

Acute triangle: because the three inner angles are all acute angles, the outer angles correspondingly have 6 obtuse angles;

Obtuse triangle: Because one of the three inner angles is obtuse and the remaining two are acute, the corresponding outer angles have 4 obtuse angles.

Right triangle: Because one of the three inner angles is a right angle and the remaining two are acute, the corresponding outer angles have 4 obtuse angles.

Because there is a triangle with an obtuse angle called an obtuse triangle, the most or largest angle of the obtuse triangle is an obtuse angle, which cannot be less than 90°

So the answer is:

From the figure, it can only be seen that one corner of the hand is an acute angle, and the other two corners can be completely destroyed as an acute angle, or there is an obtuse angle of the fiber cover, or there is a right angle;

So all three scenarios are possible

Therefore, d

In a triangle, there is an angle that is obtuse, which is called an obtuse triangle closed branch. It is also possible that there is a sedan with a right angle, called a right triangle.

Any triangle has at least two acute angles, and friends can only have at most one right or obtuse angle. If a triangle has all three angles of acute angles, it is called an acute triangle. Acute triangles and obtuse triangles are collectively referred to as oblique triangles.

This is a true proposition.

For example, in the known δabc, a 90°Assuming that at least one of the other two corners is greater than or equal to 90°, such as b 90°, then there must be.

a+∠b+∠c＞180°

This contradicts the triangle with three inner angles equal to 180°.

So the other two angles must be acute angles.

The above is a counter-argument).

This is a real imitation of Bi.

For example, in the known δabc, a 90°Assuming that at least one of the two angles is greater than or equal to 90°, such as b 90°, then it must be.

a+∠b+∠c＞180°

This contradicts the triangular three-inner corner skin with a stupidity equal to 180°.

So the other two angles must be acute angles.

The above is a counter-argument).

Summary. Dear, The answer is: there is only one right or obtuse angle at most and a minimum of 0 right or obtuse angles in a triangle. There are a maximum of 3 acute angles and a minimum of 2 acute angles.

I've found a triangle with a minimum of a few obtuse angles and a maximum of a few right or acute angles.

Kiss, the answer is: there is at most only one right angle or obtuse angle in the triangle, and at least 0 right angles or pure obtuse angles. There are a maximum of 3 acute angles and a minimum of 2 acute angles.

Solution: There is only one right angle or obtuse angle at most and at least 0 right or obtuse angles in a triangle. There are a maximum of 3 acute angles and a minimum of 2 acute angles.

Suppose that the number of degrees of an obtuse angle of a triangle is 91 degrees, then the sum of the two acute angles is equal to 89 degrees, so in a triangle, one obtuse angle is greater than the sum of the two acute angles

So the answer is: