A simple math problem! Can anyone help me understand the steps to solve the problem!!! Urgent!!!

The original formula is equal to 2004 times 2003 times 10001 minus 2003 times 2004 times 10001

It is equal to 2003 times 2004 times 10001 minus 10001

I made it!!

Here's how he solved it.

Original = 2004 (2003000+2003)-2003 (2004000+2004).

Did you add an extra 0 to 10001? If you add more, this is the solution.

20032003 becomes 2004*10001, and the whole becomes 2004*2003*10001-2003*2004*10001, and finally equals zero.

You'll get the formula you wrote.

Once you know this, it's simple, original form.

This kind of question must be regular, it is impossible for you to really calculate it step by step, and it is naturally no problem to pay attention to accumulating more and discovering more

Bring seven-ninths to tease, and then fifteen stupid to sell fourteen plus fifteen annihilation one-half is one, <>

According to the reciprocal of dividing by a number equal to multiplying this number, it can be quickly imitated to become:

Re-interest multiplication method mu trouser fiber distribution law, get:

7 9 (14 15 + 1 15)

Hello! Glad for your question!

7 9 14 15 Bright answer with 7 9 15 simple calculations.

Original 7 Jingfu 9 14 15 7 9 1 15 You are the greatest support for me! Break a leg! Thank you!

This should be the easiest, right?,Closed and although it's a little troublesome.,But it's all the old waiter at the sedan track.,Hehe.。

Isn't this very simple, it is (9 5) * (3 2) + (3 2) * 18=

Is the title wrong? One more (1+2 cubes).

1+1/2) (1+2 to the 4th power) (1+2 to the 8th power) +2 to the 15th power.

2 (1 half).

1+1/2) (1+2 to the 4th power) (1+2 to the 8th power) +2 to the 15th power.

2 (1 2 to the fourth power) (1 + 2 to the fourth power) (1 + 2 to the eighth power) + 2 to the 15th power.

2 (1 2 to the eighth power) (1 + 2 to the eighth power) + 2 to the 15th power.

2 (1 1 2 to the 16th power) + 2 to the 15th power.

2 2 15 to the 15th power 2 2 to the 15th power 2