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1.A, B, C, D.
1998-2) is divisible by period 4, so the answer is 8.
2.Because 130 is divisible by 5, left-to-right and right-to-left are consistent, so the problem can be reduced to"On a 130 cm long stick, apply green dots every 5 cm from right to left, and every 4 cm from right to left", the least common multiple of 4 and 5 is 20, so the period is 20, and there are 2 segments in each cycle, so the answer is 13.
3.In the end, a total of 201 cups were advanced counterclockwise, divided by 16 to make a difference of 9, and from 1 to 9 is the 10th cup, so the answer is 10.
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Want the answer: no? If you want the answer, you'll be there. 1.A, B, C, D.
1998-2) is divisible by period 4, so the answer is 8.
2.Because 130 is divisible by 5, left-to-right and right-to-left are consistent, so the problem can be reduced to"On a 130 cm long stick, apply green dots every 5 cm from right to left, and every 4 cm from right to left", the least common multiple of 4 and 5 is 20, so the period is 20, and there are 2 segments in each cycle, so the answer is 13.
3.In the end, a total of 201 cups were advanced counterclockwise, divided by 16 to make a difference of 9, and from 1 to 9 is the 10th cup, so the answer is 10.
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The cycle is 4
Algorithm: Another x=x+1 is brought into the known equation to obtain: f(x+2)=[1+f(x+1)] [1-f(x+1)].1)
It is also known that f(x+1) [1+f(x)] [1-f(x)].2)
2) Bring in (1) to simplify: f(x+2)=1 [-f(x)].3)
From Eq. (3) and x=x+2 into Eq. (3), we obtain:
f(x+4)=1/[-f(x+2)].4)
Bringing Eq. (3) into Eq. (4) gets:
f(x+4)=f(x)
The period definition with a function gives that the minimum positive period of f(x) is 4
If that's not the standard answer.
Then I can't help it.
This method is the dead way to solve all cycle problems!
Doesn't the landlord give extra points?
The first reply was garbage.
I actually wrote like that, fainted!
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(1) Add to 7 and 1, the cycle section is 7654321, a total of 7 digits, 300-2 = 298;298/7=42……4
Then it's the 4th, it's the 4th
2) If it is 9 and 1, then 100 9 = 11 ......1, is 9, and if it is 8 and 1, then (100-1) 8=12......3, is 6, if it is 7 and 1, then (100-2) 7=14, then is 1, if it is 6 and 1, then (100-3) 6=16......1, is 6, if 5 and 1, then (100-4) 5=17......1, then is 5 If it is 4 and 1, then (100-5) 4=23......3, then is 2 If it is 3 and 1, then (100-6) 3=31......1, then is 3, if it is 2 and 1, then (100-7) 2=46......1, then it is 2 and only 5.
1. Fit the topic.
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1.If f(x+m)=f(x-n) is constant, it means that x is always true no matter what value f(x+m)=f(x-n) is constant, then it may be used.
x+n instead of x to get f(x+m+n)=f(x) holds, which is consistent with the periodic function definition:
f(x+t)=f(x), so f(x) is a periodic function, and the period t=m+n
2. If f(x+m)=f(x), then f(x) is a periodic function, and the period t=m
If f(x+m)=1 f(x) always holds (1), then f(x+2m)=1 f(x+m)(2).
From (1) and (2) f(x+2m)=f(x), then f(x) is a periodic function, and the period t=2m
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The definition of period is f(x+t)=f(x), then the period is tf(x)=-f(x+a).
Then -f(x+a)=f(x+a+a) (here x+a is considered as a whole) then f(x)=f(x+2a) period is 2a
This kind of problem starts with the definition and transforms the known conditions into the equations given in the definition.
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-f(x+a)=f(x)
Replace x+a with the x above.
f(x+a+a)=f(x+a)
i.e. -f(x+2a)=f(x+a)=-f(x), so f(x)=f(x+2a).
So t=2a
Hope it helps!
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There are five Sundays in February of a certain year, and the first day of June of this year is the week of the week
Because 7x4=28, there are five Sundays in February of a certain year, so February of this year should be 29 days, and February 1 and February 29 are both Sundays, and March 1 is a Monday, so a total of March 1 to June 1 of this year has passed.
31 + 30 + 31 + 1 = 93 (days).
Because 93 7 = 13....2, so June 1 of this year is Tuesday.
This question is to infer the day of the week after a certain number of days, months or years, and the answer to this kind of question is mainly based on the law of a seven-day cycle of the week, and the periodic solution is used. When calculating the number of days, it is necessary to follow the provisions of "one leap in four years, no leap in four hundreds, and one leap in four hundred years", that is, when the Gregorian calendar year is not an integer hundred, as long as it is a multiple of 4, it is a leap year, and when the number of Gregorian years is an integer hundred, it must be a multiple of 400 to be a leap year.
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For a function f(x), if there is a positive number t such that when x takes every value in the defined domain, there is f(x+t)=f(x), then the function f(x) is called a periodic function. The positive number t is called the period of this function.
For a function f(x)=asin(x+), the minimum positive period of the function f(x) is t=2|
For a function f(x)=atan(x+), the minimum positive period of the function f(x) is t=
f(x+2)=-f(x-2) is subtracted to a fixed value in parentheses, then the period of this value f(x) is t=4
The essence of the periodic function: when the difference between the values of the two independent variable values is equal to the multiple of the period, the function values of the two independent variable values as a whole are equal. As.
f( x+6) =f( x-2) then the period of the function is t=8
The physical quantity of alternating current – period.
Cycle. The time it takes for a sinusoidal alternating current to complete a cyclic change is called a period, which is represented by the letter t and is measured in seconds (s). Obviously, the interval of time between two maximums (or two adjacent minimums) of a sinusoidal alternating current or voltage is a period.
Cycle. The name of a person or thing for a specific period of time, which can be set by the rules of nature or artificially.
The period is 4 algorithms:
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So 2f(m)=2f(m)f(0), so f(0)=1, so f(0)=1
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Since f(x) is continuous, the integrals can be determined on both sides of the equation at the same time, and if the interval is [0,1], then the original function of t = arctan(1) -arctan(0) +t 41 (1+x 2) is arctan(x), and the original function of x 3 is x 4 4). >>>More
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