To make 65 and the number in the tens of digits is 5, what single digits can be filled in?

Because the two digits of 5 on the ten digits are 59 at the maximum and 50 at the minimum, there are: 65-59=6, 65-50=15, so you can fill in 6,7,8,9.

For example, if you want to make the quotient a single digit, you can fill in (1,2,3,4,), and if you want the quotient to be a two-digit number, you can fill in (5,6,7,8,9).

12 5 2 surplus 2

22 5 4 surplus 2

32 5 6 surplus 2

42 5 8 surplus 2

52 5 10 more than 2

62 5 12 surplus 2

Find patterns and fill in the blanks:

1, 2, 4, 7, 11, 16, (22), (29), the difference is: 1, 2, 3, 4, 5, 6 ,...

2, 5, 10, 17, 26, (37), (50), the difference is: 3, 5, 7, 9 ,...

0, 3, 8, 15, 24, (35), (48), - the difference is: 3, 5, 7, 9 ,...

There are simply too many types to find patterns. Some of them have regularities between the given numbers, and some have regularities between the next number. There is also a pattern of difference between two adjacent numbers. The law may be the same addition, the same subtraction, the same multiplication, a number or a series of numbers, or squares.

Because the two digits of 5 on the ten digits are 59 at the maximum and the smallest is.

5o, so there are: 65-59=6, 65-5o=15, so you can fill in 6,7,8,9,

Everything is to say, if you don't have such a thing in life for a long time, minimize losses? At home! It's so delicious, all for your own sake to fight for someone to talk to him, all for yourself to fight for someone to talk to him, everything will fly to the sky to have a home......Won't leave her if she really has.

Answer: It depends on the meaning of the question.

To make the number in the tens of digits of 65-() be 2, the minimum can be filled in (36).

Let the difference of ten digits be 2, and the minimum can be 36

The minimum is 36 and the maximum is 45

Solution: From the meaning of the question, it can be known that the tens of digits are 2, then the maximum result is 29, the minimum is the positive source 20, the minimum is required to fill in the mouth, that is, to find the minimum subtraction is a few, in the subtraction is unchanged, when the difference is the largest, the subtraction is the smallest, that is, the result is 29 time pattern, the number in the mouth is the smallest. The minimum number of rents in the mouth is equal to 65-29=36.

Summary. Solution idea: 65-29=3665-20=45 Therefore, to make the ten digits of the number 2, the box in the question can be filled in any number from 36 to 45 to meet the requirements of the question.

Hello, you can fill in a number in 36 45.

Problem solving ideas: 65-29=3665-20=45 Therefore, to make the ten digits of the number 2, the box in the Shanjing question can tease Li Shen to fill in any number from 36 to 45 to scramble to meet the requirements of the question.

64 Subtract a number, the old position of ten slips is 5, which means that the number is greater than 4, here you can fill in 5,6,7, and Song Rang Jin 8,9.

Because the two-digit number of 4 on the ten digit is 49 at the maximum and 40 at the minimum, so to make the number on the tens of digits 4, the number filled in the mouth must be between 0 and 9.

So there are: 54-5 = 49, 54-9 = 45, narrow the range, to ensure that the number filled in is between 5 9, and the number between 5 9 has .

To sum up, the single digit that can be filled in the mouth is .

Summary. Hello, happy to answer for you! To make 64 a mouthful, the number of tens is 5, and the mouth can be filled with 5, 6, 7, 8, 9

Hello, happy to answer for you! To make 64 a mouthful, the number of tens is 5, and the mouth can be filled with 5, 6, 7, 8, 9

Analysis: In the question, if you want to make the number macro regret word on the dozens of digits is five, then fill in the minimum 5 in the box and repentance box, and because the box is filled with a single number, the maximum is 9, so the number that can be filled in the box is 5 6 7 8 9

When it is equal to 5, the result is 59 when it is equal to 6, when the result is 58 when the carrying segment is equal to 7, when the result is 57 when it is equal to 8, and when it is 56, when it is equal to 9, the result is 54

If you change it to equal 9, the result is 55

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Summary. Hello, dear. We're happy to answer your <>

According to the conditions you give, you can know that the dozens of digits are 2, then the maximum result is 29, the minimum is 20, and the minimum number in the mouth is required to fill in the minimum, that is, to find the minimum number of subtractions, when the subtraction is unchanged and the difference is the largest, the subtraction is the smallest, that is, when the result is 29, the number in the mouth is the smallest. So the minimum number in the mouth is equal to 65-29=36

65 of the dozens of places on the 2, the smallest can fill in (+) pro question seems to be incomplete, can you send ** look at the question.

Hello socks, dear. We're happy to answer your <>

According to the conditions you give, you can know that the dozens of digits are 2, then the maximum result is 29, the minimum is 20, and the minimum number in the mouth is required to fill in the minimum number, that is, to find the minimum number of subtractions, when the subtraction is unchanged and the difference is the largest, the number of subtractions is the smallest, that is, when the result is 29, the number in the mouth is the smallest. Therefore, the minimum number in the rent is equal to 65-29=36

A 6 in the ten digit represents 60, and a 5 in the single digit represents 5, so the number in the ten digit is 55 more than the number in the single digit. （60-5=55）

6-5 = 1, the number in the ten digit is 1 more than the number in the single digit