Advanced math books have those advanced math questions

Is it 6 times + 6 times + 8 times + 8 times + 8 times + 8 times + 8 times + 12 times + 12 times + 24 times = 3000, or multiply it to equal 3000

(1) If you can't do it, it's more than 3000. In other words, given any number, you can only reach a maximum of 96% of that number.

2) 480 480 360 360 360 360 240 240 120 This is the closest. Whichever one comes out, the result is 2880.

The method of allocation is: if the given number is x, then.

6 times the place to assign x, assuming that this number is y. That is, y=x.

8 times the place allocation.

12 times the local allocation, 24 times the local allocation.

That's the best option.

Supplementary questions are a few people can understand, landlord, your ability to express is not good, or on the original question, word for word, there must be an answer.

6:6:8:8:8:8:12:12:24 = 3:3:4:4:4:4:6:6:12 (approx. 2).

Total 3 + 3 + 4 + 4 + 4 + 4 + 6 + 6 + 12 = 46 servings. .Divide 3000 into 46 servings, how much is each serving?

Answer: 64 or 66. Therefore, one . With 64, it is less than 3000

192 192 256 256 256 256 384 384 768 per copy 2944 less than 3000

Two. More than 66 words than 3000

198 198 264 264 264 264 396 396 792 per copy 3036 More than 3000

Therefore, as long as the even number is greater than or equal to 66, you can multiply this even number by 3:3:4:

6:6:12 A series of numbers of this ratio, the sum of which is greater than 3000, multiplies an even number less than or equal to 64 or greater than 0 by a scale whose sum is less than 3000

For multiples of only one number, you can use the following method:

Coata 6:6:8:

6:12 (Jos. 2).

Total 3 + 3 + 4 + 4 + 4 + 4 + 6 + 6 + 12 = 46 servings. .Divide 3000 into 46 servings, how much is each serving?

Answer: 64 or 66. Therefore, one . With 64, it is less than 3000

192 192 256 256 256 256 384 384 768 per copy 2944 less than 3000

Two. More than 66 words than 3000

198 198 264 264 264 264 396 396 792 per copy 3036 More than 3000

Therefore, as long as the even number is greater than or equal to 66, you can multiply this even number by 3:3:4:

6:6:12 A series of numbers of this ratio, the sum of which is greater than 3000, multiplies an even number less than or equal to 64 or greater than 0 by a scale whose sum is less than 3000

It's a permutation problem:

If the position of "1" is used as the calculation method:

c51 c52 c53 c54 c55, that is, there is a 1 in these five digits, two 1s, 1 in 1, four 1s, and five are all 1s.

c51＝5 00001 00010 00100 01000 10000

c52＝10 00011 00101 01001 10001 00110 01010 10010 01100 10100 11000

c53＝10 11100 11010 10110 01110 11001 10101 01101 10011 01011 00111

c54＝5 11110 11101 11011 10111 01111

c55＝1 11111

Result: A total of 31 number combinations.

Five digits, each bit has two possibilities, i.e. a total of 2 to the fifth power = 32 sets.

Elementary math problems are the most naïve of them (12 balls).

Your algorithm is wrong.

1-1+1-1+1-1+1...0 There are 2n 11-(1-1)-(1-1)-(1-1)...1 This formula has 2n-1 1, so 1-(1-1)-(1-1)-(1-1)...

1 (which must be a 1 to satisfy the condition) = 0

You're missing a 1!

In the last digit it should be 1, which is 1 - (1-1) - (1-1) - (1-1) ...1=0

1-1+1-1+1-1-1+1 (the end here should be -1 to be true)...0 then look at the top again.

With 1-1+1-1+1-1-1+1....0 as an example 1-1+1-1+1-1-1+1...=0 to 1-1+1-1+1-1+1-1+1-1=0 Suppose that this equation ends here, and then using the additive distributive and associative properties to get 1-1+1-1+1-1+1-1=1-(1-1)-(1-) 1-1)-1 The result is 0

Khan, this is the divergence function.

f(x) 0 or 1, equal to 0, the condition is that n is even; When it is equal to 1, n is an odd number.

There's no contradiction.

1-1+1-1+1-1+1...0 Is this right?

1-1+1-1+1-1+1...The result is determined by the number of 1. When the number tends to infinity, it is still impossible to judge its size, let alone equal to 0.

What is the term? The result is divergent.

The mathematician Noumberly thinks the answer to this question is.

It's infinite progression, upstairs wrong.

Tan Bin, a Chinese mathematician, believes that the answer should be no answer.

Upstairs is all wrong!!

If you don't believe it, ask Tan Bin.

Alas, such a simple question still needs to be asked.

Sad.

a+b=0, b+c=0, so a=c;

c+d=0, d+f=0, so c=f

From the above, we can see that a=c=f

b+c=0, c+d=0, so b=d

First of all, I can tell you clearly, no, the title says, you can only use addition, subtraction, multiplication and division.

Factorials can't be used, it's almost the same as playing 24 points, and the answer is (5-1)*5+5=25

The topics are all said, and they can only be multiplied and divided by addition, subtraction, multiplication, and division.

Factorial is also an operation.

The answer is (5-1)*5+5=25