The IP address of a host is known to be 192 73 65 181 and its subnet mask is 255 255 255 248

The answer upstairs is not what you asked, it is the subnet address! The 21 here is a representation of the subnet mask in network engineering, which is simple and intuitive, and it means that the IP address [I think you should know that the IP address is converted into binary is 32 bits, one for every 8 bits. Separated into four 8-bit binary, usually we use decimal representation, more convenient Inside, the first 21 bits represent the network address, and the last 11 bits are the host address That is to say, the first 21 bits of the subnet mask are 1, and the back is 0 [Common sense:

The subnet mask consists of all connected 1s followed by several consecutive 0sWe can express it in the form of:

Convert to decimal is that.

That is, its subnet mask

1. IP addresses are divided into 5 categories: ABC is for ordinary computers, and D is for multicast.

e is reserved for experiments.

2. The address is a Class C IP

The subnet mask is used to specify the network address in the IP address, and if there is no subnet, Class A is Class B.

Class C is. Actually.

When the computer wants to transmit data, first of all, the computer is to use the IP + subnet mask to calculate the network address of its own computer, and then compare the IP to be sent, if it is the same network number, it will be broadcast in the network to find the target host, if it is not the same network, it will be handed over directly to the gateway

3. The IP address network number is.

Summary. The IP address of a host is and the subnet mask is . The mask is 27 zeros.

Therefore, the network address accounts for the top 27 bits of the IP address. After equalizing the IP address and mask into binary, the network address of the network segment where the address is located can be obtained by doing logic and operation. In the binary state, the IP address network bits (the first 27 bits) remain unchanged, and the host bits (the last 5 bits) are all set to 1, and the broadcast address can be obtained.

1.The IP address of a host is, the subnet mask is, and the subnet address (represented by dot decimal system); How many bits are the subnet address and the host address? What is the maximum number of hosts that can be accommodated on the network where the host is located (all 0s and all 1s of the subnet address and host address are not used)?

1.The IP address of a host is, the subnet mask is, and the subnet address (represented by dot decimal system); How many bits are the subnet address and the host address? What is the maximum number of hosts that can be accommodated on the network where the host is located (all 0s and all 1s of the subnet address and host address are not used)?

1. The current mask is, converted to binary; 2. The number of bits with the tail 0 in the mask corresponds to the host number in the IP address, that is, the last 10 bits correspond to the host number; 3. Convert IP address to binary:; 4. The result is that restoring the decimal system to is its host number.

Brother, there are three questions in total, can you directly give me the answers to the three questions? Thank you.

The IP address of a host is and the subnet mask is . The mask is 27 zeros. Therefore, the network address accounts for the top 27 bits of the IP address.

After equalizing the IP address and mask into binary, the network address of the network segment where the address is located can be obtained by doing logic and operation. In the binary state, the IP address network bits (the first 27 bits) remain unchanged, and the host bits (the last 5 bits) are all set to 1, and the broadcast address can be obtained.

Subnet address: 22 bits of network number, 10 bits of host number.

Are these three sure are the answers to those three questions I have?

The number of hosts on the network where the host resides is 1,022 excluding the network segment and broadcast.

OK. ok

Give a thumbs up. Okay

Network ID and host number. The network number identifies the subnet on the internet, while the host number identifies the host in the subnet. IP addresses are classified into three types: A, B, and C based on the number of network numbers and host numbers.

An IP address (Internet Protocol address) refers to an Internet Protocol address, also known as an Internet Protocol address. IP address is a unified address format provided by the IP protocol, which assigns a logical address to every network and each host on the Internet to mask the difference in physical addresses.

To determine that the IP addresses of two hosts are not in the same network segment, first calculate the network number where the two IP addresses are located, and then compare them according to the network number. Otherwise, it is divided into two networks.

Since the bits are the same and both are 24-bit masks (, just compare the 3rd field.

The third field is converted to binary.

Based on the subnet mask bit of 1 consecutively, the two network numbers are and are not in the same network.

PS: It's just a standard step, and if it does, it's actually obvious at a glance. Hope it helps.

The IP address of a host is and the subnet mask is yes. What is the last available IP address in the subnet and the last available IP address in the lead fiber subnet? Henghu.

The network address of the subnet is: The broadcast address of the subnet is: Therefore, the first available IP address in the subnet is: The last available IP address in the subnet is:

Pls the direct broadcast address is.

According to the IP address and subnet mask provided in the question, it can be calculated that the subnet address where the host is located is, and there are 4 zeros in the binary representation of the subnet mask, and Zheng Tan should be able to accommodate up to 2 4-2=14 hosts in the subnet. Therefore, the first available IP address within that subnet is the subnet address plus 1, ie. The last available IP address within this subnet is the direct broadcast address minus cluster ruler 1, i.e.

The direct broadcast address is the address obtained by setting all host bits to 1, so the direct broadcast address of the subnet is.

The IP address category and host number too.

This IP address is classified as Class B because its first byte ranges from 128-191.

The host number is the unique identifier of each host within the subnet. In this case, the main change is the third byte (nucleus 130) and the fourth byte (77).

The IP address of a host is, and the subnet mask is, 1 to find a subnet address (represented by a decimal celery system); 2. Find out how many bits of the subnet address and host address each occupy, and 3. Ask the number of hosts that can be accommodated in the network where the main Zen burning machine is located.

Dear, thank you for your patience According to the teacher's understanding [Flower Zen Tree]1The first 19 bits of the subnet mask are the network address, and the last 13 bits are the host address. Therefore, the subnet address can be obtained by performing logic and operation on the host IP.

The subnet mask is, with 13 bits being used for the host address. This means that the network can accommodate up to 2 13-2 = 8190 hosts. where -2 is because the network address and broadcast address cannot be used for the host.