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The country's first independent development of embedded LCD touch screen queuing machine (without PC structure) research and development enterprises, the country's first embedded LCD touch screen queuing machine practical application enterprises, the country's first set of embedded LCD touch screen queuing machine IE network version queuing system production enterprises. This product solves the shortcomings of PC queuing machine instability, crash and maintenance trouble, and will become the mainstream of China's queuing products.
Product concept: to repay customers with the best products with the lowest **!
APT (Apate) queuing machine application field ( industry ) customer service center, business hall, service hall, window service industry. Such as: banks, postal and telecommunications, insurance, hospital outpatient waiting, telecommunications, customs, civil aviation railway stations, labor bureaus, personnel bureaus, social security centers, public security, courts, procuratorates, import and export customs declaration and inspection, commodity inspection and inspection, health bureaus, technical supervision bureaus, industry and commerce, finance, tax business halls, one-stop (one-stop) service halls, one-stop office service centers, administrative service halls, transportation bureaus, traffic management bureaus, vehicle management offices (vehicle management offices), driving schools, automobile trading markets (automobile sales centers), Power supply bureaus (power bureaus, power companies), embassies, consulates, mobile phones, mobile service centers (call centers)...
Looking forward to China's increasingly important role on the world stage, we feel unprecedented pressure, and we are confident to strive for a place in the new world industrial pattern!
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At the beginning, there are x people lined up at both windows A and B.
If Xiao Li continues to queue up at window A, it will take x 4 minutes to transfer from window A to the back of window B and queue up again, and the number of people in front of him is x+2*5=x+10, and the time is (x+10) 6
30 seconds = 1 2 minutes.
x/4)-[x+10)/6]=1/2
3x-2(x+10)=6
x=2626*2=52 people.
At the beginning, there were 26 people queuing at both windows A and B, and a total of 52 people queued.
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There are 6 people walking every minute from window b.
It should be (x-4 2) 4=(x-6 2+5 2) 6+1 2
x=26
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Suppose that if you continue to queue up at A to get food, the time required is t1=(x-8) 4
The time required to queue up to buy food at B is t2=(x-2*6+2*5) 6
t1-t2=1 2 (i.e. 30 seconds), the answer is 26
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It turns out that there are x people, which is derived from the title.
A window turned out to have x people, and after two minutes, it was x-8 people, and to continue to take his turn was x-8 4 people.
There were also x people in window b, and after two minutes, there were 5 people per minute, so after two minutes, there was actually x-12+10=x-2, so it was his turn, x-2 6
So listing the equation, (x-8) 4=(x-2) 6+ solution gives x=26x=26
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30 seconds = 1 2 minutes.
x/4)-[x+2*5)/6]=1/23x-2(x+10)=6
x=26A: At the beginning, there were 26 people in each team in line.
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At this time, there are A-8 people in window A, and A-12+10=A-2 people in window B, because the time spent queuing at both windows is the same, 4 fewer people per minute in window A, and 6 fewer people per minute in window B, so.
a-8)/4=(a-2)/6
6a-48=4a-8
2a=40a=20
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There were x people at the beginning.
Then two minutes later, there are x-8 people in front of Xiaojie in window A, and x-12+10=x-2 people in front of window B.
x-8/4=x-2/6 x=20
So at the beginning there were 20 people in front.
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At the beginning, there are x people lined up at both windows A and B.
If Xiao Li continues to queue up at window A, it will take x 4 minutes to transfer from window A to the back of window B and queue up again, and the number of people in front of him is x+2*5=x+10, and the time is (x+10) 6
30 seconds = 1 2 minutes.
x/4)-[x+10)/6]=1/2
3x-2(x+10)=6
x=2626*2=52 people.
At the beginning, there were 26 people queuing at entrances A and B, and a total of 52 people were queuing.
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1) There are 4 people leaving window A every minute, so the time it takes for Xiaojie to reach window A is t=(a-8) 4 minutes.
2) After 2 minutes, there are A-6 2+5 2=A-2 people in front of window B, so the time it takes for Xiaojie to reach window A T2 is.
t2=(a-2)/6
According to the title, t220 is the range of values of a.
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Analysis: (1) According to the topic, it is enough to directly list the formula;
2) According to the column inequality of "it takes less time to reach window B than it takes to continue queuing at window A to reach window A", (A-4 2) 4 (A-6 2+5 2) 6 can be solved
Answer: Solution: (1) The time it takes him to continue queuing at window A to arrive at window is (a-4 2) 4=(a-8) 4;
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Maybe Xiaojie re-queued after T minutes.
Known to be available.
a-4t)/4=(a-6t+5t)/6
The solution yields a=10t
A=20 after two minutes
This means that this may have happened when there were 20 people in the queue before.
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(1) After 2 minutes, if Xiaojie continues to queue up at window A, the time taken to reach window A is (a-4x2) 4=(a-8) 4
2) Get (a-8) 4 (a-6 2+5 2) 6, solve a 20
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Solution: (1) The time it took him to continue queuing at window A to arrive at window was A-4 24, which is A-84 (points).
2) From the inscription, get A-4 24
The value of a can be 20
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Set up x people in line at the beginning, by the title:
x-4×2)÷4=(x-6×2+5×2)÷6+1÷2
x=26
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