Chemical Equation and Ion Equation 5

Hey, I don't even want to write about it, didn't you learn all this in the academy?

The bounty is too small, and I am not interested in spending so much effort.

High pressure ==2no

2no+o2==2no2

3no2+h2o=2hno3+no

Or: 4NO2 + O2 + 2H2O = 4Hno3 concentrated) == Heating = == MnCl2 + Cl2 +2H2OMN (+4) Mn (+2 is reduced) (2E-) Cl(-1) Cl2 (0 is oxidized) (loses 2E-) 3A small amount of chlorine gas is passed into the ferrous bromide solution, and because the ferrous ions are more reducible than the bromine ions, only the ferrous ions are oxidized.

The chemical equation is: 3Cl2+6Febr2===4Febr3+2FeCl3 is replaced by an ionic equation: Cl2

2fe2+===2fe3+

2Cl- A sufficient amount of chlorine gas is passed into the ferrous bromide solution, and in addition to the ferrous ions being oxidized, the bromine ions are also oxidized by the chemical equation of 3Cl2

2febr2===2fecl3

The equation for 2br2 to ion is: 3cl2+2fe2+

4br-===2fe3+

2br26cl-

1.Baking soda (sodium bicarbonate).

If Ca(OH)2 is insufficient.

ca(oh)2

2nahco3===caco3↓

na2co3

2H2O ion equation: 2oh-

ca2+2hco3-

caco3↓+2h2o

If Ca(OH)2 is excessive.

ca(oh)2

nahco3===caco3↓

naohh2o

Ionic equation: Ca2+

hco3-=caco3↓+oh-

h2obaoh

baso4↓+

H2O + Na2SO4, which is 2NaHSO4 in case of sodium bisulfate excess

2baoh2baso4

H2O2NaOH, which is in case of barium hydroxide excess.

Ion equation: (Ba2+)+OH-)+H+)+SO42-)==BASo4 +H2O

。Ion equation: 2oh-

ca2+2hco3-

caco3↓+2h2o

If Ca(OH)2 is excessive.

ca(oh)2

nahco3===caco3↓

naohh2o

ionic equations; 2nh3

Then 4NH3+5O2 <, N2 and O2 are so synthesized that you don't think the cost is very high.

1;===High temperature and high pressure catalyst===>

2nahso4

baohbaso4↓+

H2O+Na2SO4,4NO2+O2+2H2O=4HNO3 concentrated)==Heating==MnCl2+2H2O+Cl2Mno2+4H+

2cl - == heating = = mn2+

2h2o+cl2

12f：(ba2+)+oh-)+h+)+so42-)==baso4↓+h2o

I'm sorry I don't want to fight. It should be N2+3H2<===High temperature and high pressure catalyst===>, and then NO+O2==NO2:Ca2+

hco3-=caco3↓+oh-

H2O2, which is in case of sodium bisulfate excess.

2nahso4

2baoh2baso4

H2O2NaOH, which is in case of barium hydroxide excess, copy it; 4no+6h2o

Well. Baking soda (sodium bicarbonate).

If Ca(OH)2 is insufficient.

ca(oh)2

2nahco3===caco3↓

na2co3

2H2O ion equation.

All ions generated from non-ionic substances such as water, gas, difficult, insoluble, elemental, etc., must be retained. All ions that generate non-ionic substances such as water, gases, difficult, insoluble, and elemental substances must be retained. In the case of ionic reactions with redox reactions, all the ions (generated, reactants) where the redox reaction takes place are retained.

Just three, you can synthesize the opinions of other people. Or you can write the material energy on both sides of the equation as ions (in principle), and then eliminate all the equal numbers that are on both sides, and you're good to go. If you don't know what is dissolved and what is not, you have to ask and remember....The basics are not just a few categories...

An ionic equation, i.e., a formula that represents an ionic reaction with the symbol of the ions that actually participate in the reaction. Refers to the reaction in which soluble substances are detachable. The ionic equation not only represents a certain reaction between certain substances, but also represents the same type of ionic reaction.

For example, H++OH-=H2O can represent the neutralization of many strong acids and bases.

Whether a variety of ions can coexist in large quantities in the same solution can be summed up as: one color, two sexes, three special, and four reactions. To write the ionic equation local cracking, we must first determine whether the reaction is an ionic reaction or not.

For example, the reaction of acetic acid with sodium carbonate is an ionic reaction, and the reaction of acetic acid with ethanol to produce ethyl acetate and water is not an ionic reaction.

In the title, A and B belong to the same family in the periodic table. A has 7 electric blobs in the outermost shell, which belongs to group VII, so B also belongs to group VII, and the outermost shell has 7 electrons missing. The electronic configuration of b is 2

7, is chlorine Cl. Chlorine is a fairly strong chlorinating agent, and when used as an oxidizing agent, its semi-reactive formula is as follows: Cl2(AQ) +2E-2Cl-(AQ) On the other hand, the iron(ii) ion in ferric sulfate(ii) is a reducing agent, and as a reducing agent is, its semi-reactive formula is as follows:

Fe 2+(AQ) Fe 3+(AQ) +E - When two phases are mixed, a redox reaction occurs. Chlorine is reduced to chloride ions, while iron(II) ions are oxidized to iron(III) ions. From the above two halves of the reaction formula, the complete reaction formula can be obtained as follows:

Cl2(aq) +2Fe 2+(AQ) 2Cl -(AQ) +2Fe 3+(AQ) Since b is used in the title to denote chlorine, the complete reaction formula can also be written as follows: B2(AQ) +2Fe 2+(AQ) 2B -(AQ) +2Fe 3+(AQ) Expected observation: The solution changes from light green to yellow (or yellowish-brown).

Reference: ADAM

High temperature = = mg(OH)2+h2

6hcl == 2alcl3 + 3h20al2o3 + 6h+ = = 2al3+ +3h20+ 2naoh = 2naalo2 + h2oal2o3 + 2oh - = 2alo2- +h2o

4.When the NaOH solution is in small amounts.

Chemical equation: AlCl3+3NaOH=3NaCl+Al(OH)3 Ion equation: Al3+ +3OH-=AL(OH)3 when there is an excess of NaOH solution.

The chemical equation is: AlCl3+3NaOH = 3NaCl + Al(OH)3 Al(OH)3+NaOH = Naalo2+2H20Al(OH)3+3H+ =Al3+ +3H2O=Naalo2+2H2O

al(3+) 4oh¯ = alo2¯+h2o9. 2cu+s=cu2s

10.If there is not enough bromine water or there is an excess of iron: Fe + Br2 = Febr2 = Febr2 = Febr2 = Febr2 = Febr2 = Febr2 = Febr2 = Febr2 = Febr2

Catalyst ==3O2

2 O3 discharge is a condition that is generated.

h2o2 = 2h2o+ o2 ↑

16. h2s↔h2+s

17.Less than 2H2S + O2 ====2S + H2O Excess 2H2S + 3O2 ====2SO2 + 2H2ofes + 2H+==Fe2 + + H2S

20.When H2S is insufficient, 2NaOH+H2S==Na2S+2H2O, when H2S is excessive, NaOH+H2S==NaHS+H2OS2- +H2S=Hs-

Excess) ===Na2SO4 + H2O + SO2 ion equation: SO32-+2H+====SO2 +H2O

The product is omitted from the water).

Calcium bicarbonate is added to a small amount of sodium hydroxide solution: calcium carbonate, sodium bicarbonate (dissolved).

HCO3(-)OH(-)Ca(2+)=CaCO3(precipitate)+H2O

Calcium bicarbonate is added to excess sodium hydroxide solution: calcium carbonate, sodium carbonate (dissolved).

2HCO3(-)Ca(2+)+2OH(-)CO3(2-)+CaCO3(precipitate)+2H2O

Magnesium bicarbonate is added to a small amount of sodium hydroxide solution: magnesium carbonate, sodium bicarbonate (dissolved).

Mg(2+) + OH (-) HCO3 (-) MGC3 (precipitate) + H2O

Magnesium bicarbonate branch bend to add excess sodium hydroxide solution: magnesium hydroxide, sodium carbonate (dissolved).

mg(2+)+2HCO3(-)4OH(-)mg(OH)2(precipitate)+2H2O+2CO3(2-)

Ammonium bicarbonate is added to a small amount of sodium hydroxide solution: ammonia, sodium bicarbonate (dissolved).

nh4(+)oh(-)nh3+h2o

Ammonium bicarbonate is added to excess sodium hydroxide solution: ammonia, sodium carbonate (dissolved).

NH4 (+) HCO3 (-) 2OH (-) NH3 (gas) + CO3 (2-) + 2H2O

Sodium hydrosulfide + a small amount of barium hydroxide: barium sulfide, sodium sulfide (dissolved).

2Hs(-)2OH(-)BA(2+)=2H2O+S(2-)+Bas (precipitation).

Sodium hydrosulfide + excess barium hydroxide: barium sulfide, sodium hydroxide (soluble).

HS(-)OH(-)BA(2+)=H2O+BAS(precipitation).

Sodium bicarbonate + a small amount of lead hydroxide collapsing barium: barium carbonate, sodium carbonate (dissolved).

2HCO3(-)2OH(-)BA(2+)=2H2O+CO3(2-)+BACO3(precipitate).

Sodium bicarbonate + excess hydrogen acacia round barium oxide: barium carbonate, sodium hydroxide (soluble).

HCO3(-)OH(-)BA(2+)=H2O+BAC3(precipitate).

1. CO2 + Na2CO3 + H2O == 2NaHCO3CO2 + CO3 2- +H2O == 2HCO3- The title does not say saturated Na2CO3 solution, so NaHCO3 does not write precipitate 2, CO2 + Na2CO3 + H2O == 2NaHCO3 CO2 + 2Na+ +CO3 2- +H2O == 2NaHCO3

Because it is a saturated Na2CO3 solution, NaHCO3 should be written precipitate.

1. (co3 2-) co2 + h2o === 2(hco3-)

2.2(Na+) CO3 2-) CO2 + H2O === 2NaHCO3 precipitate.

Unsaturated and not precipitated.

The saturated ones have precipitation.

na2co3+co2+h2o=2nahco3

Na2CO3 + CO2 + H2O = 2NaHCO3 (precipitate).

Good luck (high school textbook standard answers).