Urgent math problem The difference between the reciprocal of two consecutive odd numbers is 2 323, w

Equation solution? Let the two odd numbers be x,x+2;1 x-1 (x+2)=2 323, general score: (x+2)-x x(x+2)=2 323, further simplified:

2 x(x+2)=2 323, we get: x(x+2)=323=17*19=-17*(-19)So x=17 or -17, i.e. these two odd numbers are 17 and 19, or -17, -19

Let two consecutive odd numbers be (2n-1) and (2n+1), then 1 2n-1-1 2n+1=2 323

2/4n^2-1=2/323

8n^2-2=646

n= 9 so the sum of the two numbers is (17+19)=36

These two consecutive odd numbers are 2n-1, 2n+1

1/(2n-1)-1/(2n+1)

2/(4n^2-1)=2/323

n^2=81

n = 9 The sum of these two consecutive odd numbers 17, 19 or -19, -17 is 36 or -36

1/x-1/(x+2)=2/(x+2)*xx*(x+2)=323=17*19

So these two odd numbers are 17, 19 or -19, -17 and are 36

Let the smaller one be x

1/x -1/(x+2)=2/323

x(x+2)-323=0

x=17 or -19

So it's 17, 19 or -19, -17

Let one odd number be x and the other x+2, and solve the equation according to the conditions.

Any two consecutive odd numbers are coprimes.

The difference between the reciprocal of two consecutive odd numbers is 2 143Denominator.

And: 13 11 2

So, the odd number of these two consecutive ridge dust poses is 11 and Sakura is 13

Categories: Education Jujube Science >> Learning: 2n-1, 2n+1

1/(2n-1)-1/(2n+1)=2/3992/(2n-1)(2n+1)=2/399

2n-1)(2n+1)=399

4n^2-1=399

n^2=100

n=102n-1+2n+1=4n=40

The sum of these two odd numbers is 40

Let these two consecutive odd numbers be a, a+2, according to the meaning of the title:

1/a)-[1/(a+2)]=2/195==> (a+2-a)/a(a+2)=2/195==> 1/a(a+2)=1/195

> a(a+2)=195

> a²+2a-195=0

> (a-13)(a+15)=0

> a=13, or a=-15

then the two consecutive odd numbers are 13 and 15, or -15 and -13

Let : the small odd number is x, then the large odd number is (x+2);

1 x)-(1 (x+2))=143 2-way solution: x=11

x+2=13

You can find out, these two odd numbers are 11, 13

Because: 143 = 11x13

So: the reciprocal of these two consecutive odd numbers is 1 11 and 1 13 respectively

Because two consecutive odd numbers are coprime over each other, 143 is decomposed into prime factors and then rewritten as the product of two consecutive odd numbers: 143 = 11*13, so one is 1 11 and the other is 1 13

1/(2n+1)-1/(2n+3)=2/1432/[(2n+1)(2n+3)]=2/143(2n+1)(2n+3)=143

I tidy it up and get it. n²+2n-35=0

n+7)(n-5)=0

n = -7 or n = 5

n=-72n+1=-13

2n+3=-11

n=52n+1=11

2n+3=13

These two numbers are 11 and 13 or -13 and -11, respectively

Because two consecutive odd numbers are co-prime, 143 is decomposed into the prime factor and then rewritten as the product of two chains and a continuous odd number: 143=11*13, so one is 1 11 and the other is 1 13

143 2 2=143 Sun San 1

Split 143 1: 143 = 11 13

143 2=11 1-13 1

These two consecutive odd horses are 11 and 13 respectively

The difference between the reciprocals of two consecutive odd numbers is 2 143, and the sum of the reciprocals of these two consecutive odd numbers is 1 11 + 1 13 = 24 143

Decomposing 323 into prime factors, 323 = 17*19, we can see that these two consecutive odd numbers are 17 and 19, 17 + 19 = 36.

It is known that the difference between the reciprocal of two consecutive odd numbers is 2 323, and it can be seen that the product of two consecutive odd numbers is 323, and the sum of two consecutive odd numbers is 36

I wish you progress in your studies and go to the next level! (

2/323=1/17-1/19

These two odd numbers are:

The sum is 17 + 19 = 36