Older brothers and sisters who are in the third or second year of junior high school are in and ther

Set up x sets of Class A machines for the first quarter of production.

1+10%)x+(1+20%)(480-x)=554x=220 480-220=260

In the first quarter, 220 machines were produced and 260 machines were produced.

Set up the first quarter to produce machine A x units, then the production of B machine 480-x units:

x*(1+10%)+480-x)*(1+20%)=554 The solution is x=220

Therefore, in the first quarter, 220 units of machine A were produced, and 260 units of machine B were produced.

Solution: Set up a production of X units.

1+10%)x+(1+20%)(480-x)=554x=220 480-220=260

In the first quarter, 220 machines were produced in class A and 260 machines in type B, right?

Let A be x and B be y

then x+y=480

x(1+10%)+y(1+20%)=554 Solve the equation to obtain:

x=220y=260

What grade are you? All of this stuff is searched on the Internet?

Study hard!

Let the production of A in the first quarter be x and B be y

If the outside is round, and the two lines of R length are 90 degrees... The shaded part is an isosceles right triangle, i.e.:

The area of an isosceles triangle is the base multiplied by the height and divided by 2, which is exactly r times r divided by 2

So the square of r divided by 2 equals 50

Calculate r=10

Then the area of the circle is multiplied by r squared.

Multiply the square of r.

That's 100 times that.

Equal to 314 By the way, you are too talented.

This circle was drawn with the Paint tool? Well drawn!

One half [r 2] = 50

r^2=100

r = root number 100 = 10

s circle = multiplied by r 2 = multiplied by 100 = 314

Some symbols won't hit, forgive me. Seek adoption.

S Yin = 50m, r = 10m, s circle = r = 100 (if there is a value for the question, please substitute it). This question is relatively simple, the point is to calculate r, which is the king.

The above answer is that in the case that the shaded part is an isosceles right triangle, if according to the first floor, the shaded part is not a right triangle, then it cannot be calculated in this way, and as far as I know, I feel that there is no solution. I am a new high school freshman, I hope I can help you.

First of all, are the two radii perpendicular?

Please ask.