Is it possible that the object motion is perpendicular to the constant velocity trajectory of an ell

Probably, a uniform non-circular motion exists.

The force on the object is perpendicular to the velocity, and the magnitude of the force affects the amount of velocity change, that is, the degree of bending of the object's motion track. f = mv 2 r, the mass and velocity are constant, the greater the force, the smaller the radius, the greater the degree of bending (curvature) of the track.

If you divide the curved orbit into infinitesimal segments, each segment can be seen as an arc with equal curvature, and the curvature is greater where the ellipse is bent more (e.g., at the end of the long axis), and the same is true anyway.

In the encyclopedia "curvature", the reciprocal of curvature is the radius of curvature (this concept is rather nonsense, anyway, it is understood as the degree of curvature of the track, and the degree of curvature is negatively correlated with the radius by looking at circles of different sizes).

Combined with the formula f=mv 2 r, when the velocity of the object is constant, the rate of change of the orbit of the curvilinear motion is inversely proportional to the radius, i.e., directly proportional to the force experienced by the object perpendicular to the direction of motion.

Therefore, if the magnitude and direction of the force on the object are controlled so that the direction of the force is always perpendicular to the instantaneous velocity, and the magnitude of the force is always equal to the product of the curvature of the elliptical trajectory at that point and mv 2 (curvature=1 r), the trajectory of the object can be guaranteed to be elliptical. However, the motion of the object at this time is a uniform motion. That is, the velocity does not change, and the velocity direction changes non-uniformly.

If you have studied the high school magnetic field section, you will learn that the Lorentz force, its direction is always perpendicular to the direction of velocity, and its magnitude is related to the strength of the magnetic field. If a charged body is only affected by the Lorentz force in the magnetic field and the magnetic field strength is changed, the object will move in a uniform non-circular motion.

It has to be possible!! Circular motion is the direction of force on the object perpendicular to the direction of motion of the object! But the default condition --- force is constant.

It is elliptical when the force changes in it.

It should be a circle, and the uniform circular motion can be defined in such a way that the velocity of the object constantly changes direction, and the ellipse, like the motion of the planets.

No way. It should be circular because the force experienced by the object only changes the direction of the velocity, not the velocity.

It is possible that if there is a change in the magnitude of the force on the movement, the trajectory is not circular.

Is the circle: the centripetal force.

It is equal to the external force pointing towards the center of the circle. Namely.

When it is an ellipse, it ......It's a bit complicated, I asked the teacher when I was a freshman in high school, and then I learned other knowledge to know that the knowledge of the current (your freshman year of high school) can't be solved, let me put it this way: near the end of the object (at the focal point O1) on the long axis (point A, called perihelion in the motion of the planets.

where the velocity is too large, the centripetal force is greater than the gravitational force, and the centrifugal motion is done; Do a centripetal motion at point B. The object keeps speeding up from B to A, eh, overdoing it? Centrifuged? Quickly slow down, so A to B kept slowing down, and then lost ......That's probably what it means.

The object moves in a curvilinear way, and the trajectory of the motion is circular, and the centripetal force f=mv 2 is the radius of motion.

In the first year of high school physics. When the gravitational force becomes a centripetal force, it is possible to move in a circular motion. That is, gmm r 2 = mv 2 r

That is, when v 2 = gm r.

If the velocity v v of an object in a circular motion is made, the object will be centrifugal in motion. However, as the distance between objects increases, the velocity decreases (just as the Earth revolves around the Sun, and the farther away from the Sun, the velocity decreases) to a certain point, v will v. It will do centripetal movement again.

So the trajectory becomes elliptical.

These are Kepler's three laws.

Circle: The distance from the fixed point does not change during the movement;

Ellipse: The sum of the distances to two fixed points does not change during motion.

Curvilinear motion, in fact, can be regarded as the composition of an infinite number of arcs. Whereas, circular motion requires a certain speed and vertical velocity, and an unbalanced force in the direction constitutes a centripetal force. The magnitude of the velocity and centripetal force determines the curvature of the circular motion.

by gmm r2 = mv2r

The velocity of the near-earth orbit v1=(gm r) 1 2 The velocity of centrifugal motion at the same point in the elliptical orbit v2>(gm r) 1 2v2>v1

The acceleration at the same point in the near-Earth orbit and elliptical orbit is equal in the motion of a celestial body, which is determined by gmm r 2 = ma a = gm r 2

Summary. Hyperbola can also be a celestial trajectory.

When an object is subjected to a constant force in one direction, the trajectory of motion is parabolic. When an object is subjected to a gravitational force from a focal point, its trajectory is elliptical. Then what kind of force the object is subjected to is a hyperbola.

Hyperbola can also be a celestial trajectory.

The direction of the resultant external force and the initial velocity is not in a straight line, and the trajectory of motion is a curve.

The object moves in a curve, and the trajectory of the motion is circular, and the condition is that a centripetal force of equal magnitude f=mv 2 is the radius of motion.

In the high one thing dust liter acorn. When the gravitational force becomes a centripetal force, it is possible to move in a circular motion. That is, gmm r 2 = mv 2 r

That is, when v 2 = gm r.

If the velocity of an object moving in a circular motion is next to v v, the object will move centrifugally. However, as the distance between objects increases, the velocity decreases (just as the Earth revolves around the Sun, and the farther away from the Sun, the velocity decreases) to a certain point, v will v. It will do centripetal movement again.

So the trajectory becomes elliptical.

The direction of acceleration is always in line with the direction of the force. The trajectory of the object's motion (straight or curved) is determined by the directional relationship between the velocity and acceleration of the object (when the velocity and acceleration are in the same straight line, the object moves in a straight line; When the direction of velocity and acceleration are angled, the object moves in a curve).

Whether the combined motion of two rectilinear motions at angles to each other is a linear or curvilinear motion depends on whether their combined rolling velocity and the direction of the combined acceleration are collinear.

v, a in the same direction, uniform acceleration linear motion; V, A reverse, uniform deceleration linear motion; v and a are angled, and the uniform speed curve moves (the trajectory is between v and a, tangent to the direction of velocity v, and the direction gradually approaches the direction of a, but it is impossible to reach. ）

010-The problem of movement trajectory on the circle, the key to solving the problem is to find the center of the circle.

Determine the C motion trajectory: then determine another position of C to obtain the C motion trajectory.

Evaluation key: ABO'It is a right-angled triangle god shape, and the obm is all equal to o'bc, get を'c1, which is finally evaluable.

009 - Movement trajectory common exam questions, equilateral triangle accompanying points.

Find the G movement track:

There is any other position where the fixed Wangshan selling angle is trapped feg=60°, and the fixed ratio ef:eg=1:1 is found in g (generally a special position is taken).

When f is in b, in order to satisfy the fixed angle and fix the edge, then g is at n for the second time; Connect ng, two points to determine a straight line, ng is the g trajectory.

Evaluation. Find similar triangles: fbe is similar to nfg

The key point oec=30° is evaluated.

The displacement of an object moving in a straight line must be equal to the distance. This statement is false. The correct thing is that the displacement of an object that is moving in one direction must be equal to the distance.