Question C high marks are given if the program is written .

#include

using namespace std;

int main()

int x;Number of hens.

int y;Number of attacks.

int z;The number of chicks, in multiples of 3.

for( z = 0; z <= 100;z += 3 ) The number of chicks is a multiple of 3, so add 3

double m = (double)4 / 3 * z - 100;

double n = 200 - double)7 / 3 * z;

x = (int) m;

y = (int) n;

if( (m - x) !=0 ||n - y) !=0) Determine whether the number of roosters and hens is an integer, not a continuation.

continue;

else if( m > 0 &&&n >0 ) to determine whether the quantity is greater than 0, and if so, to output the result.

cout<<"The number of hens is"Suppose you buy x female, y male, z small.

5x+3y+z/3<=100

x+y+z=100

Solve this system of equations.

Suppose you buy x female, y male, z small.

5x+3y+z/3<=100

x+y+z=100

Solve this system of equations.

(1) Original formula = root number 6 - root number 2 + root number 2-1 - (root number 6-2) = 1

2) Original formula = 5-1 - (root number 3-1) + 3-1 = - root number 3 + 7

Set up the production of product A x pieces, then the production of B product (50-x) pieces, the two products need a total of raw materials 9x + 4 (50-x) < = 360, the two products need a total of B original mill slow material 3x + 10 (50-x) < = 290, and the solution inequality is combined to obtain 30 < = x< = 32

So blind model x = 30, 31, 32

That is, plan 1: 30 pieces of product A, 20 pieces of product B, profit 30 * 700 + 20 * 1200 = 45,000 yuan.

Plan 2: 31 pieces of product A, 19 pieces of product B, profit of 31 * 700 + 19 * 1200 = 44,500 yuan.

Plan 3: 32 pieces of cherry blossom products produced by A and 18 pieces of product B, with a profit of 32 * 700 + 18 * 1200 = 44,000 yuan.

It is estimated that the maximum profit when producing 30 pieces of product A and 20 pieces of product B is 45,000 yuan.

Set up x pieces of production A products.

then there are 1100<45x+75(20-x)<1200=> 1100-1500<45x-75x<1200-1500=> 400>30x>300

That is, x>10 x is an integer.

then A is 11,12,13 and B is 9,8,7

1: A11B: A12B8'3: A13B7. I don't know if it's right or not.

Question 16 is 125 degrees.

Question 17 is 105 degrees.

I did the math myself, and I'm definitely right. Beg.

The midpoint of the g bit EF Because bf and ec are parallel, so the inner angles of the triangle BGF and the triangle egc are equal, respectively, and BG is equal to gc BF is equal to EC So these two triangles are congruent triangles, and the corresponding sides are equal, so eg is equal to FG

The second question is the middle point of the ef, and the result is the same.