A problem that I think is difficult to chemically speculate on solid products

Updated on educate 2024-02-26
4 answers
  1. Anonymous users2024-02-06

    As long as you're willing to do the math, it's easy to do......

    The added mass of the solid is the mass of the oxygen element in the oxide, for.

    The mass ratio of iron to oxygen is 56:22=28:11

    1. The mass ratio of iron to oxygen in ferric tetroxide is 56*3:16*4=21:82, and the mass ratio of iron to oxygen in iron oxide is 56*2:

    16*3=7:33, the mass ratio of iron to oxygen in ferrous oxide is 56:16=28:

    828:11 should be between the ratios of all solid products, so there must be iron oxides. (Only this one is bigger than it), choose C.

  2. Anonymous users2024-02-05

    3fe+2o2=fe3o4

    x solution yields x=2fe+o2=2feo

    The solution yields y=4fe+3o2=2fe2o3

    56---z

    The solution is z=8g

    Now it is found that iron is burned in a sufficient amount of O2 to obtain a solid, only the solid mass obtained by combustion to produce Fe2O3 is greater than that, and the mass of the other two oxides obtained is less than that, to meet the final mass is, there must be part of Fe2O3, and part of Fe3O4 or FeO

    From this, it can be known that C is chosen

    Since it is a sufficient amount of oxygen, d can be excluded.

  3. Anonymous users2024-02-04

    The amount of iron in the solid

    Iron content in Fe3O4 168 232=

    Iron content in feo = 56 72 =

    The iron content in Fe2O3 = 112 160 = 70% Since it is a sufficient amount of oxygen, it is impossible to have iron element.

    So the answer is cFe3O4 and Fe2O3 (choose one greater than and one less than.)

  4. Anonymous users2024-02-03

    A multiple-choice question, it would be too cost-effective to calculate for so long, let me make a simple one.

    In fact, because it has been said that there is enough oxygen, there can be no iron, so a and d are excluded first.

    The difference between b and c lies in these oxides of iron. In fact, FeO, Fe2O3, and Fe3O4 can be regarded as the combination of one iron and 1 oxygen, and 4 3 oxygen, respectively. Because it is iron, if it is pure oxide, it must be the one with more oxygen binding that is the heaviest, that is, Fe2O3 grams, other Fe3O4 grams, FeO grams.

    Now it's grams, if fe3o4 and feo are combined, there is no way to achieve this result, so the result must be c.

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