Help with the puzzles, thanks! A puzzle to solve!

1) Since Xiao Ming, who knows the month, said: "If I don't know, Xiao Qiang definitely doesn't know", which means that the month in his hand is definitely not June and December. Because if it is June or December, Xiaoqiang may have 2 or 7 in his hand, so that Xiaoqiang can directly judge it.

As long as Xiao Ming is not 6 or 12 in his hand, Xiao Qiang will definitely not be 2 or 7 in his hand, so Xiao Ming dares to make this judgment.

2) Xiaoqiang said: "I don't know at first" means: Xiaoqiang acquiesced that it was not 2 or 7(If it is these two days, because the date is unique, Xiaoqiang can immediately judge the correct one, contrary to what he said.) ）

Therefore, the months that Xiao Ming knows may be March and September; The date that Xiaoqiang knows may be 1,4,5,8,3) Since through Xiao Ming's words, Xiaoqiang can and only exclude June and December, and at this time, Xiaoqiang can determine the exact date precisely because of this exclusion, and it is certain that Xiaoqiang must not have 5 in his hand, otherwise Xiaoqiang will not be able to judge the month.

3) In this way, there are March 4, 8 and September 1 that are eligible. In the end, Xiao Ming said that I also knew, which means that he can determine the date by the month, so it will be September 1st.

Xiao Ming said: If I don't know, Xiao Qiang definitely doesn't know. It means that it is impossible for Xiao Ming to hold June or December, because there are 2 and 7 days in these two months.

Xiao Qiang said: I didn't know it originally, but now I know" means that Xiao Qiang heard what Xiao Ming meant, and looked for it in March and September, but he found it at once, indicating that it was impossible to hold it in his hand on the 5th, so what month and day was it? Xiao Ming gave the final answer, he said:

Xiao Ming said: Oh, then I know too. It means that March is excluded, so the answer is only September 1.

Big brother, September 10th is Teacher's Day, don't talk nonsense.

It's very clear upstairs, don't say much.

September 1st Teacher's Day! How can students know the teacher's birthday, but students know that Teacher's Day is ......

Because your question book is incomplete, you can only give two answers: one is 6 books (which refers to the number of books in the box) and the other is an infinite number of books (the number of books can exceed the capacity of the box).

5 copies. Lay three books flat, you can place one book at 10 cm in the remaining two directions, for a total of five books.

Put 3 books first, and then put 1 book vertically in the back, and then put 1 book horizontally on the side, a total of 3+1+1 5 books.

You can put five books and 5 books, one at the bottom, and two books vertically at work. Put one more on each side.

Put three books in a flat stack, and insert two books vertically, for a total of 5 books.

Put 5 copies, and it is not right to divide the volume directly by volume.

Five copies, three flat, two vertical.

Because 50 + 25 + 12 + 6 + 3 + 2 + 1 = 99 (field).

So, a total of 99 matches will be played.

Starting from the serial number 1, it belongs to the number of 6n+1 dyeing, when 6 * 9 + 1 = 55, the remainder of 50 is 5, so 6n + 5 are stained, when 6 * 17 + 1 = 103, the balance of 50 is 3, so 6n + 3 are dyed, and finally 6 * 25 + 1 = 151 to 50 is 1, so it is exactly the number of 6n + 1, so all the odd numbers in the 50 numbers are dyed, so there are 25 numbers dyed.

The least common multiple of 2,3,4,6 is: 12

The common multiples of 2, 3, 4, 6, are: 12, 24, 36, 48, 60, 72....

12+1) 7=13 7 is not divisible.

24+1) 7=24 7 is not divisible.

36+1) 7=37 7 is not divisible.

60+1) 7=61 7 is not divisible.

72+1) 7=73 7 is not divisible.

Therefore, his age is 49 years old.

Multiples of 7 within 90 are: , excluded multiples remain: and then look for these numbers minus 1 to multiples the number is 49.

I didn't know how to count it after watching it for a long time, and I only thought of a stupid way to eliminate them one by one.

Because her age is divisible by 7 and less than 90, so.

Probably one of 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77, 84.

And because divided by 2, the remainder is 1, that is, it is an odd number that is not divisible by 2, so.

Probably one of 7, 21, 35, 49, 63, 77.

Because divide by 4 or 6, the remainder is 1, so.

Her age is 49 years old.

1.Numbers greater than or equal to 100 and less than 200.

2.Numbers greater than or equal to 200 and less than 300.

InheritanceNumbers greater than or equal to 300 and less than 400.

Tell the fiberA number greater than or equal to 400 and less than 500.

5.Numbers greater than or equal to 500 and less than 600.

6.Numbers greater than or equal to 600 and less than 700.

7.Numbers greater than or equal to 700 and less than 800.

8.Numbers greater than or equal to 800 and less than 900.

9.Numbers greater than or equal to 900 and less than 1000.

Actually, the reason is very simple.

27+2, it doesn't mean anything, these two numbers can't be added together at all. The reason is very simple, what is 27 is the sum of the actual fee of 25 yuan and the 2 yuan hidden by the waiter. It already contains 2, and adding 2 doesn't make sense.

Correct algorithm: the actual fee is 25 yuan, and the waiter hides 2 yuan, which is a total of 27 yuan; "The remaining 3 yuan was distributed to the three people, and each person was given 1 yuan", 27 + 3 = 30, which is the money paid by the first three people. In this way, there is no contradiction.

There are already 3 yuan in 27 yuan that were taken away by the guy, and it can no longer be +"2" should be +"3".

The boss is 25 yuan, and the waiter hides 2 yuan, a total of 27 yuan; The 3 yuan refunded will be divided into 1 yuan per person, 25 + 2 + 3 = 30

The 2 yuan that the young man took was in the 3 9 yuan they came out, so how to use 3 9 27 to add 2, this text question, how can there be a solution if the question is wrong?

The last question is if the sum of the other two numbers is equal to the third number.

However, if the student cannot see the numbers on his own head and the numbers on the heads of the other two people, he can see them.

Just add those two numbers together and you will equal your own number. In this way, the question is wrong, because it has to conform to a formula x+y=z

x+z=yz+y=x

There is only one case that makes 3 equations hold.

That's x=y=z=0

But the third number is 144

So this question is wrong.

Is it not the sum of two arbitrary numbers that is greater than (not equal to) the third number, so that there is a solution.