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grams can weigh 1-6g.
Add 15g to call 15-21.
With 15 minus can be called 9-14.
Add 40 to weigh 40-46, 49-54, 55-61.
Subtract 40 to have 34-39, 25-19, 26-31 and then finish, except for can be weighed, so a total of 61-6 = 55 kinds.
ps: When you encounter this kind of question with a small number during the exam, the quickest way is to enumerate, don't think about any simple and fast way, it's better to do it if you have time.
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A odd number of the number chain square divided by 4 remainder 1, pure grandson.
99 divided by 4 to the remainder of 3
So it's impossible to imitate it.
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What is a perfect square number?
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Let there be a sequence of positive integers (n>=0).
Then 2010*mn=2010*(1+n*10) makes 2010*mn=(n+1)!
Therefore, there is 2010*(1+n*10)=(n+1)!
n+1)!-20100*n=2010
n((n+1)(n-1)!-20100) = 2010 to get n = 9
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The conclusion should be correct, I don't know if there is a mathematical approach. When the computer calculates that n=14136, the first four digits of an are 2010.
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Obviously, any one person knows at least three people well.
And 3x7 21 is not divisible by 2, so at least one person knows 4 people well.
You might as well set him A, then the 6 people after excluding A will sit at the table according to the principle of acquaintance. Then two of A's four acquaintances must be next to each other, and A only needs to be among them.
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Solution: Suppose you can see the x-level, the escalator upward speed a, Li Ming's upward speed b, and the downward speed 3b, then the downward time is 150 (3b)=50 b In this time, the elevator goes up 50 (b a) level Xiao Ming walks from the top to the end, so (x+50) (b a)=150 is the same, and there is (x-75) (b a)=75{( x+50) (b a)=150
x-75)÷(b÷a)=75
The solution is x=120, that is, the elevator can see 120 steps.
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I don't understand at all that any six of them can sit down around a round table, and what that means is the key.
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2.(x 2-1)m-2x+1<0 for -2 =m =2 constant set y=(x 2-1)m-2x+1
y is a primary or constant function of m, and its image is straight, so the two endpoints corresponding to y are less than 0, and the whole line segment is below the x-axis, and y is less than 02 (x 2-1)-2x+1 0
2(x^2-1)-2x+1<0
After solving x, take the common part.
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