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Because x 2 + y 2 > = 2xy
y^2+z^2>=2yz
x^2+z^2>=2xz
So 1=x 2+y 2+z 2>=xy+yz+xz, so there is a maximum value of 1
x+y+z) 2=x 2+y 2+z 2+2(xy+yz+zx) 0, and x 2+y 2+z 2=1
So 1+2(xy+yz+zx) 0
So (xy+yz+zx) -1 2
So there is a minimum value of -1 2
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The question should be known that positive numbers x, y, and z are all real numbers, right?
2xy=2yz=2xz=2(xy+yz+xz)= 2(x2+y2+z2), so xy+yz+xz= 1 if and only if x=y=z=1 takes the maximum.
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The question is wrong, and the positive integer is removed as the 12th question of the 2004 college entrance examination mathematics national test paper 1.
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What is a positive integer, x 2 + y 2 + z 2 = 1 = xy + yz + xz
Can x, y, z be root numbers 3 3?
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xy+yz+xz= 1 if and only if x=y=z=1 is the maximum.
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I bring the solution of the A into 2 and get it. b = 50, and the solution of B is brought into 1 to obtain a = -1, then the original system of equations is -x+5y=15(1) 4x-50y=-2(2
Solution: x -74 3, y -29 15
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A reads the wrong equation (1), then A's solution is in accordance with equation (2), and B is found. B reads Eq. (2) incorrectly, then B's solution conforms to Eq. (1), and finds A. You will.
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Let the remainder be a and the divisor be b
273-a)/b-(237-a)/b=4273-a-237+a=4b
b = 9 means that the divisor is 9
To calculate the remainder, use 237 b = 237 9 = 26 ......3 means that the remainder is 3
Even the quotient can be calculated together to be 26
Arithmetic: From 237 to 273, the difference is 273-237=36.
The quotient which it divides by this number is 4.
The divisor is 36 4 = 9
Reason: Because 273 is 36 larger than 237, it has an extra quotient of 4 when dividing by the divisor.
In other words, 273 has 4 more quotients than 237 because 273 is 36 more than 237, and because there are 36 more, there are 4 more quotients in division.
Divisor = 36 4 = 9
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The one that earned 20% was sold at a price that was multiple of the original price, so the original price was 4,800 yuan; Blocking.
The one that lost 20% was sold at multiple times the original price, so the original price was 4,800 yuan.
That is to say, the price of these two goods is 10,000 yuan, and the actual selling price is 9,600 yuan, a loss of 400
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Solve the stove ruler: Let the distance between A and B be S kilometers.
s/500+s/400=
4s+5s=13500
9s=13500
s=1500
Answer: The air distance between A and B is 1,500 kilometers.
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Set: It took X hours to go.
500x=400(
Solution: x=3 (when the base of the mountain).
Distance between two places: 3 500 = 1500 meters.
A: The distance between the two places is 1,500 meters.
Hope it helps tease you.
You can take a look.
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The air distance between A and B is x.
x Scramble 500 + x 400 =
x/5+x/4=675
4x+5x=13500
x=1500
Answer: Sullenness; The air distance between the two annihilators is 1,500 kilometers.
500x3=
I guess so.
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Time 3:2
The efficiency ratio is 2:3
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You have to be clear about the equationsa-1|+[b+2)squared] = 0, there are two cases, one is that the sum of two numbers that are opposite to each other is 0, and the other is that 0 plus 0 equals 0, and the problem can only satisfy the latter case.
So a-1=0 and (b+2) 2=0, i.e. a=1, b=-2, so a+b=-1
So the value of [(a+b) to the power of 2010] + [a to the power of 2011] = 1 + (-1) = 0
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a-1 = 0 (b+2) squared = 0 a = 1 b = -2 (a+b) to the power of 2010 = 1 a2011 power = 1
The end result is equal to 2
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a=1,b=-2
a + b) to the power of 2010] + [a to the power of 2011] value of 2
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