Ask some math problems solve them with equations, ask for processes .

1.Let each pencil be x yuan, so 7x+2*, i.e. x = yuan).

2.If the pear is shipped xkg, so 2x-250=2500, then x=1375 (kg).

3.Let the height be xdm, so (, then x=6(dm).

4.If there are x basketballs, then there is one football, so x+, that is, x=48, then one).

5.Let the peach tree be x, then the apple tree is 4 5x, so x+4 5x=360, that is, x=200, then 4 5x=160 (pieces).

6.If there are x students in the sixth grade, so (1-1 5) x = 120, then x = 150 (people).

7.Set up a professional breeding household to raise x chickens, so x * (30%) - 30 = 600, then x = 2100 (only).

Study hard.

1.Solution: Set x yuan for each pencil.

7x+2x=solution: set up a supermarket to transport pears xkg.

2x-250=2500

x=1375

3.Solution: Set height to xdm.

x=64.Solution: Set up x basketball and football.

x+x=485.Solution: Set x peach trees and 4 5x apple trees.

x+4/5x=360

x=2006.Solution: There are x people in the sixth grade.

x-1/5x=120

x=1507.Solution: Set up x chickens.

30％x-30=600

x=2100

I'm so tired of fighting!!

The children's shoes on the first floor don't use equations, so they can't do the sixth problem.

Suppose there are x people in the sixth grade (120-x) x=4 5

In fact, before you ask the question, you should indicate whether you want to solve the equation for one yuan at a time or several yuan: let 20 yuan a kilogram of candy need x kilograms, and 28 yuan a kilogram of candy needs (100 x) kilograms, then.

20x＋28(100-x)＝2500

20x＋2800－28x＝2500

20x－28x＝-2800+2500

8x＝-300）

Solve x 100 x 100

I don't know if you want the process, so I added the process, but we don't need the process to learn.

25 yuan per kilogram is lost, 125 yuan.

If there are two non-specific needs x and y kilograms, then 128x+120y=125*100x+y=100

x=, y= for solving a system of equations.

Let the candy of 28 yuan be x kilograms of yuan (100-x kilograms: 28x (100 x) 20 25 100 solution x = A: 28 yuan is kilograms, and 20 yuan is (kilograms. If you don't understand, you can ask me.

Solution: Let the first candy be x kilograms, then the second candy (100--x) kilograms.

28x+20(100--x)=25 times 10028x+2000--20x=2500

8x=500

x = kilograms) Answer: kilograms and kilograms each.

The title is a bit of a problem, right? The price of mixed candy is 25 yuan per kilogram, which should be 125, right?

The price of this mixed candy is set to be 125 yuan per kilogram, and the candy needs to be 128 yuan per kilogram and 120 yuan per kilogram respectively.

xkg, ykg, according to the title:

x+y=100 (1) total weight of mixed sugar.

128x+120y) (x+y) =125 (2) The amount of the two original sugars in the mixed sugar mix divided by the total weight is the selling price.

8x+120(x+y)] (x+y)=125 (3) Bring (1) into (3) to get:

8x 100 +120 =125 Solve the equation to get: x=bring in (1) to get: y=

Answer: You need to use candy of 128 yuan per kilogram and 120 yuan per kilogram respectively

Think of it this way:

1. According to "the first root is a multiple of the second root," it can be seen that the second root is 1 part, and the first root is a part.

2. And because, "the first root is half of the third", then. "The third root is twice as large as the first". This is the key to solving the problem.

3. The third root is the second root: times), which is where the difficulty lies.

4. The second root:

5. The first root:

If the second steel pipe is x meters long, the first steel pipe is long and the third steel pipe is meters long.

The columnable equation is: 2

3x=2x=

x = A: The length of the first steel pipe is meters.

Solution: Let the first steel pipe have xm, then the second one is, and the third one is 2xm, so the solution is x=

A: The first steel pipe has 3,2m.

Let the length of the first root be x, the second root be y, and the third root be zx=

2x=zz-y=

Then 2x-x x=

Let the first root be xm, the second root be x, and the third root be 2x

2x-x/x=

The length of the three tubes is x1, x2, and x3

So x1=x3-x2=

So x2 = x3 = x1=

(1) Set up a store to sell x pieces. Store B sells 2x pieces. From the title, 100*20 *2x—100*30 x=4000

The solution is x=400

So store B sells 800 pieces.

2) Let the side length of the truncated small square be x, which is solved by the meaning of the question 2500x=4500.

So the original square side length is.

3) Set up x hours to elapse. From the meaning of the title, 180-360x+30x=90x=3 11 (hours).

The second time 360x—180—30x=90, the solution is x=9 11 (hours).

The minute hand turns 360° per hour. The hour hand turns 30° per hour. The first minute hand did not catch up with the hour hand. The second minute hand exceeds the hour hand. ）

The solution is x=3 11 (hours).

The inner diameter of the bottom surface of the flower bed is 4m, and the radius is 3m

The amount of soil required is multiplied by 2 squared and multiplied.

Equal to the cube.

Cubic meters: This flower bed needs to be filled with a total of cubic meters.

If workshop B donates x yuan, C donates x-72 yuan.

Workshop A donated 2 3 * (x+x-72) = 4x 3-48 The donation amount of workshop B is 3 5 of the donation amount of workshop A and workshop C, and the equation is obtained as: x = 3 5 * (4x 3-48 + x-72).

Solution: x=180

Therefore, C is 180-72 = 108, A is 4 * 180 3-48 = 192 The three workshops donated: 180 + 108 + 192 = 480 yuan.

Set up three workshops A, B and C to donate x, y and z yuan respectively.

x=2(y+z) 3, i.e., 3x=2y+2z, y=3(x+z) 5, i.e., 5y=3x+3z, y-z=72

Substituting yields 5y=2y+2z+3z

i.e. 3y=5z

y=5z/3④

Substituting yields 5z 3-z = 72

z = 108 substitution.

y=180x=2(y+z)/3=192

The three workshops A, B and C donated 192,180,108 yuan respectively, a total of 480 yuan.

Solution: Let A, B, and C donate a, b, and c yuan respectively, and the following equation can be obtained according to the meaning of the question:

a/(b+c)=2/3;

b/(a+c)=3/5;

c=b-72;

The simultaneous three equations are solved:

a=192;

b=180;

c=108;

Therefore, the total donation of the three workshops is A+B+C=480 yuan.

What grade is it? If you can solve the equation, the equation is relatively simple, and it may be difficult for elementary school students to understand the equation.

Let me start with the equations.

If the amount of donation from workshop B is x yuan, then car C will donate (x-72) yuan, and workshop A will donate 2 3 * (x+x-72) yuan.

Then the equation can be established, according to the third sentence.

x= [2 3*(x+x-72)+(x-72)] 3 5 Solve the equation, I won't write about the specific process, I don't understand it and ask again.

x=180x-72=108 yuan.

2 3*(x+x-72)=192 yuan.

Set up B workshop to donate x yuan, C is x-72, B + C = 2x-72, A = (2x-72) multiplied by 2 3 = 4 3x-48, x = (x-72 + 4 3x-48) multiplied by 3 5, x=180, C is 180-72 = 108 yuan, A is (180 + 108) multiplied by 2 3 = 192 yuan, A + B + C = 192 + 180 + 108 = 480 yuan.

Let workshop B be x, then workshop C is (x-72), and workshop A is 2 3 (2x-72).

Then the equation is x (x-72) + 2 3 (2x-72) = 3 5

Let's figure it out for ourselves

In total, x, A is 2 3 of B C, then A 2 5x, B is A C 3 5 B 3 8x, C (1-2 3-3 8) x = 9 40x. C is 6 less than B 40x=72 to get x=480

Set up workshop A to donate a, workshop B to donate b, workshop C to donate c, from the meaning of the title: 3a = 2b + 2c, 5b = 3a + 3c, b - c = 72, the simultaneous equation a = 192, b = 180, c = 108, three workshops total donation = 192 + 180 + 108 = 480

If workshop B donates x yuan, then workshop C donates x-72 yuan.

Workshop A donated 2 3 * (x+x-72) = 4x 3-48 The donation amount of workshop B is 3 5 of the donation amount of workshop A and workshop C, and the equation is obtained as: x = 3 5 * (4x 3-48 + x-72).

Solution: x=180

Therefore, workshop C is 180-72=108, and workshop A is 4*180 3-48=192

The total amount of money donated by the three workshops is: 180 + 108 + 192 = 480 yuan.

If workshop B has a donation of x yuan, then workshop C has a donation of (x-72) yuan.

Then, workshop A has 2 3 * (x+x-72) yuan donation x=3 5*(2 3*(x+x-72)+(x-72))x=7 5*x-72

Solution: x=180

Therefore, workshop A has 192 yuan.

Workshop B has 180 yuan.

Workshop C has 108 yuan.

The three workshops donated a total of 192 + 180 + 108 = 480 (yuan).

Solution: Set up three workshops with a total of x

Workshop A is [2 (2 3)] x 0·4x

B is [3 5 3 ] x 0·375x

C is 0·225x

then 0·375x

x 480 A: The three workshops donated a total of 480 yuan.

Let B be x, then C is x-72, and A is 2 3 (2x-72) Therefore, x=3 5 2 3 (2x-72)+(x-72) solution x=180, then the donations of A, B, and C are x+(x-72)+2 3 (2x-72)=480-

Solution: If workshop B donates x yuan, workshop C donates (x-72) yuan, and workshop A donates 2 3 (x+x-72) yuan.

After X years, Dad's age is 3 times that of Xiao Fang's age.

then 43+x = 3(11+x).

43+x =33+3x

x-3x =33-43

2x=-10

x=5A: After 5 years, Dad's age is 3 times that of Xiaofang.

The solution of the equation 5m+2x=1 2+x about x is greater than the solution of the equation x(m+1)=m(x+1) about x2 when m is the value

The solution of 5m+2x=1 2+x is x=1 2-5m, and the solution of x(m+1)=m(x+1) is x=m

and 1 2-5m-m=2 gives m=-1 4