Summary of the knowledge points of Chapter 2, Section 1 of Chapter 2 of Senior 1 Compulsory Course

Updated on educate 2024-03-30
4 answers
  1. Anonymous users2024-02-07

    1.Calculation of enthalpy change of chemical reaction by bond energy, etc.: The difficulty of this problem lies in the problem related to the relevant structural knowledge in the elective textbook, such as: knowing the bond energy of c-c, o=o, calculate the enthalpy change of diamond (or graphite) reacts with O2 to form CO2.

    Tip: Pay more attention to the positive and negative enthalpy changes, which can reduce a lot of calculations.

    Difficulty 2: Galvanic cell and electrolytic cell: Judgment of galvanic cell and electrolytic cell; electrode-reactive writing;

    Skills: Judge from the composition conditions, energy changes, electron movement direction, current direction, etc. of the galvanic cell and electrolytic cell;

    Truly understand the order of oxidation and reduction of related substances (i.e., the order of discharge); Considering the environment of the reaction (the electrolyte is aqueous, it may be necessary to use H+, OH-, H2O, etc. to balance the electrode reaction formula; In the case of molten salt, it needs to be balanced with the anion (cation) ion of the salt or the corresponding oxide).

    Difficulty 3: Rate and Balance: Factors influencing Rate and Balance; Balance the direction of movement, sign judgment; equivalence balance (now the test is less and simpler); Calculation of equilibrium constants (ionization, hydrolysis, precipitation transformation).

    Skills: Truly understand the influence of external conditions on rate and balance (beginners are prone to confusion); To understand the basic characteristics of the equilibrium state, other equilibrium markers can be transformed into two basic features; Understanding Expressions for Equilibrium Constants – Mathematically understanding formula deformations.

    All these difficulties will not be difficult for the requirements of compulsory one, but now the teaching of various schools in the first year of high school is basically based on the requirements of electives. If you can ask this question, it is estimated that it is a good student who has higher requirements for himself, and it is estimated that the school will also have higher requirements, so it should not be taken lightly.

  2. Anonymous users2024-02-06

    The specific content of writing a lesson plan includes the following ten items:

    1. Topic (state the title of the lesson).

    2. Teaching objectives (or teaching requirements, or teaching objectives, which describe the teaching tasks to be completed in this lesson).

    3. Course type (indicate whether it is a new course or a review class).

    4. Lesson hours (indicate the number of class hours).

    5 Teaching focus (explain the key problems that must be solved in this lesson) 6 Teaching difficulties (explain the knowledge points that are prone to difficulties and obstacles in the learning of this lesson) 7 Teaching process (or classroom structure, explain the content, methods and steps of teaching) 9 Board book design (explain the content to be written on the blackboard during class) 10 Teaching aids (or teaching aid preparation, explain the tools used to assist teaching methods) In the process of writing lesson plans, the teaching process is the key, and it includes the following steps:

    1) Introduce new lessons.

    1. The design is novel and lively, and it should be summarized.

    3 Ask questions about the students, how much time it takes, etc.

    2) Teach new courses.

    1. Choose different teaching methods for different teaching contents.

    3) Consolidation exercises.

    1. The exercise is exquisitely designed, with layers, slopes, and densities.

    4) Summary.

    5) Assignment arrangement.

    When arranging those contents, we should consider the expansion of knowledge and ability.

  3. Anonymous users2024-02-05

    7.(1.The sum of the bond energies of the reactants = 946 + 436 * 3 = 2254 kj, and the bond energy of the product = 391 * 6 = 2346 kj

    So h = bond energy of reactant – bond energy of product = 2254-2346 = --92kJ (<0).

    So it is an exothermic reaction with an energy of 92kj

    2) Release, because the complete reaction of 3molH2 is exothermic 92kJ, and the complete reaction of 1molH2 is exothermic to 92 3kJ

  4. Anonymous users2024-02-04

    (1) Release; 92

    2) release; Hope it helps!!

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