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First, the car battery leakage of about 1% per day, if the connection is not removed from the car, the car is used to maintain the minimum current (commonly known as "dormant" current) about 80mA, if there is an anti-theft alarm, it will also consume a certain amount of electric energy, the general battery has about 2 3% of the electricity consumed every day, charged in three situations:
1. Start the car and charge it with its own generator, which should be fully charged once every half a month.
The battery power is less than half, that is, when the voltage is lower, the battery fault light is on, and the car is difficult to start, and the first situation should be fully charged once every half a month.
2. Charge with an external charger, which should be fully charged once in 1 month.
The battery voltage is 10% lower than the rated voltage, that is, the battery has the risk of losing power in the front rush, and the second situation should be fully charged once a month.
3. The battery should be charged once in 3 months.
When leaving the car battery, the battery leaks about 1% per day, and the third case should be fully charged once every 3 months.
Second, the car battery fault light is on, need to be charged in time, can be charged with a charger, can also be charged with 1500 rpm for more than 60 minutes, and then charged with more than 1900 rpm for more than 60 minutes, the car battery is removed, there will be data loss, need to be initialized, commonly known as decoding or coding. The third charging method should be used with caution.
Extended Materials. The battery cannot be charged.
1. Fault phenomenon: first check whether the connection of the charging circuit is reliable, check whether the contact between the wire and the plug is intact, carefully check whether the socket and plug have the phenomenon of "ignition" arcing, whether there is line damage and disconnection, etc.
2. Check whether the charger is damaged and whether the charging parameters meet the requirements: that is, the initial charging current reaches only; The maximum charging voltage reaches only, the charging floating charge conversion current reaches only, and the floating charge voltage reaches only.
3. Check whether there is dryness inside the battery, that is, whether the battery is seriously deficient, and check whether there is irreversible sulfation on the plate. The irreversible sulfation of the plates can be determined by measuring the change in the terminal voltage of the plate by charging and discharging.
4. When charging, the voltage of the battery rises very quickly, and the voltage of some single cells is particularly high, which exceeds the normal value a lot; The voltage drops particularly quickly during discharge, and the battery stores no or very little power. In the above situation, it can be judged that the battery has irreversible sulfation.
5. Fault inspection and treatment: first connect the charging circuit firmly, and replace the charger when it cannot work normally. The dry battery should be supplemented with pure water or sulfuric acid, and the battery capacity should be repaired, charged, and discharged.
6. If irreversible sulfation is found, a balanced charge should be carried out to restore the capacity. The maximum current should be controlled for the maintenance and charging of the dry battery after liquid filling, and the voltage of the three batteries should be above for 10-15 hours.
I hope mine can help you.
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C: Lighting protection type (D: Power protection type).
6: The rated current is 6A.
C6: Indicates that the leakage protector (accurate name: residual current action circuit breaker) is a lighting protection type, and the rated current is 6A (amperes).
There are three conditions that can cause a properly working leakage protector to trip:
1. Leakage. When there is leakage on the line or someone is accidentally electrocuted, the protector will trip instantly, and the leakage button will bounce up, and it can only be closed if it is pressed, otherwise it will not be closed, and the protector will not be hot.
2. Short circuit. Tripping instantly, the protector is not hot, and it can be closed after troubleshooting.
3. Overload. When the current used exceeds the rated current of the protector, the protector will trip within an hour, and the protector will heat up, accompanied by a small buzzing sound before tripping.
The situation you encounter is a typical overload trip.
The current of 6A corresponds to the power of the electrical appliance is 1320W, that is, when the power of the electrical appliance used exceeds 1320W, it will be overloaded, and the leakage protector will trip and lose power.
Only replacing the protector with a higher rated current can solve the problem.
Current used = power of the appliance 220.
The rated current of the new protector should be slightly greater than the current used.
The meter should be sufficient, and there will be no problem, so you can replace it with confidence.
The leakage action current of this protector is 30 mA, and the leakage protection capability is the same, regardless of the size of the rated current.
Domestic brands are recommended to choose genuine products from Chint or Delixi;
Foreign brands recommend genuine products from Schneider and Siemens.
Household Leakage Protector Model:
c6、c10、c16、c20、c25、c32、c40、c50、c60。
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The leakage action current of the low-voltage leakage protector (switch) is divided into milliampere and other specification levels, and the rated current is divided into .Amps and other specifications.
Although it is clear in the national standard GB 50096-1999 "Residential Design Code" that each household should be installed, each unit should be installed, and the whole building should be installed with low-voltage leakage protectors, but in fact there are big problems, because as long as there is a little leakage; It will cause the whole household, the whole unit, the whole building, the tripping and power outage, and some power departments do not even plan to use the three-phase air switch for the unit distribution box, because "a one-phase short circuit will trip the whole unit together, expanding the scope of the power outage". So now we only implement the specification of "installing low-voltage leakage protectors (switches) in socket circuits."
Generally, each household should be equipped with a low-voltage leakage protector (switch), and the leakage action current can be selected as milliamperes, with a rated current of 32A (within 140 square meters) and 60 amperes (more than 160 square meters), each unit should be installed, and the whole building should be installed, and the rated current of the switch can be selected by multiplying the total number of households by 20 amperes. Choose a low-voltage leakage protector (switch) with a leakage action current of 100-300 mAh.
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The leakage protector also has a leakage value, it jumps when it reaches this value, it depends on the situation of your computer bucket, most of the hardware in your computer is in contact with the chassis, I suggest you also buy a leakage value of 30 mAh to install it or find an electrician to check it, electricity can not be joked, it is very dangerous, be careful.
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Of course it's going to break. As long as it exceeds the rated non-operation of 15 mA, the leakage protector will disconnect the current.
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No, only leakage current leakage protectors greater than 30mA will operate. In addition, the experimental button on the leakage protector simulates the leakage current of 30mA for testing.
That is, when the leakage reaches 30mA, the leakage insurance will act. This 30mA is the operating current.
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Leakage protection is to protect your life, after installing the protection switch, as long as the household appliances have leakage 3oma, it will trip, the display screen to distinguish is leakage must be repaired and eliminated. It is the induction electricity that can be solved by the grounding wire, and the induction electricity will not trip! For safety, it is best to install a leakage switch.
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Friend, the leakage protector has a short-circuit tripping function, you only use a very thin copper wire to directly short the zero wire and the live wire without tripping, that is, the short-circuit current generated by your short-circuit is very low, that is to say, the short-circuit current generated by your short-circuit is not up to the tripping action current of the switch at all, it simulates that it is the load current.
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There will be problems with such a small power operation switch, and it is related to the size of the power, which is generally caused by the loosening of the switch and other joints, resulting in the switch overheating tripping, you can first visually check whether the switch has overheating traces, and then use a screwdriver to tighten the joint screws, such as the wire joint black overheating and oxidation is serious, you need to deal with it or re-peel a new wire joint out and press it back.
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C6 means that the rated current is 5 A, the maximum load is 220V*6A=1320VA, and it is definitely not possible to open to 2000W, if it is a main switch, it will be replaced by C25 or C32.
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If you change a good deal, it costs only a few dozen dollars to buy a three-in-one protection switch with leakage, short circuit, and overcurrent.
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The leakage protector power is too small. Changing to a 20a can be solved.
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Find an electrician to take a look, it's easy to make and save trouble.
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Replace it, it's too small, and now the smallest household needs 32a.
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It's not like leakage protection! Like the air switch jumped aha, try to change the air switch above 15a.
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The leakage current is too small, don't want him, just short the wire.
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If your home appliances are fine. That is, the air protection switch is too small... Or maybe it's a little problem... It's okay to change it.
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Tear it down and buy it in the store!
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I guess the 0 on your c60 is gone.
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There are many reasons for malfunctioning. There are reasons from the line side, and there are reasons from the protector itself. The main causes of malfunction and analysis are as follows:
1) Wiring error For example, in the TN system, if the N wire does not pass through the protector with the phase wire, once the three phases are unbalanced, the protector will malfunction; The neutral wire behind the protector is connected or grounded with other neutral wires, or the phase wire behind the protector is connected with the inverting inverting wires of other branches, or the load is crossed on the power supply side and the load side of the protector, then when the load is turned on, it may also cause the protector to malfunction.
2) Insulation deterioration The insulation of one or two opposite to the ground behind the protector is damaged, or the asymmetrical insulation to the ground is reduced, which will produce unbalanced leakage current, resulting in the malfunction of the protector.
3) Impulse overvoltage When the low-voltage inductive load is quickly broken, an impulse overvoltage of 20 times the rated voltage may be generated, and the impulse overvoltage will produce a large unbalanced impulse leakage current, resulting in the malfunction of the fast leakage protection device.
4) Asynchronous closing When asynchronous closing, the first phase of the closing may produce a large enough leakage current to make the protector malfunction.
5) The stalled rotor current of the large equipment is very large, if the balance characteristics of the zero sequence current transformer in the protector are not good, the magnetic flux leakage of the primary line of the transformer may cause malfunction when starting.
6) Deviation from the use conditions The ambient temperature, relative humidity, mechanical vibration, etc. exceed the design conditions of the protector, which can cause its malfunction.
7) Poor quality of the protector Due to the low quality of the parts or the low quality of the assembly, the reliability and stability of the protector will be reduced, and lead to malfunction.
8) Additional magnetic field If the protection shield is not good, or there is a conductor flowing through a large current nearby, or a magnetic element or a large magnet, it can produce additional magnetic flux in the core of the transformer and cause malfunction.
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Are you referring to testing switchboxes with a leakage protector tester?
Looking at your description, it feels like it should be a normal situation, and the leakage protection trip time error in your switch box is relatively large.
During the test, it is normal for the upper and lower levels to jump first, so it is best to disconnect the upper level and test it separately.
In addition, whether the setting of leakage current is the same as the rating value of leakage protection, which will also affect the test results.
This display on the action time should be milliseconds, so the third time is actually unqualified. Each test is very different, indicating that the quality of this leakage protection is not very good.
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There must be something wrong with your leakage circuit breaker, it is normal to have a difference of about 10ms, depending on your description, this leakage circuit breaker should jump within 50ms.
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Wire leakage.
Wire leakage, even if the electrical appliance is not used, it will lead to leakage action;
In the absence of electricity, phase leakage (there is a current that does not return through the neutral line) can lead to leakage action;
After the wire is replaced, the original phase wire becomes the neutral line, because the neutral line has no voltage, so it will not form a current to the ground, and the leakage protection will not work.
Therefore, your situation is that the wire used to be used as a phase wire is not well insulated at a certain position, and the insulation strength gradually decreases under the action of voltage, and when the leakage reaches a certain level, it is a leakage trip.
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It is recommended that you remove the missing cable and try again. If it doesn't trip, check the insulation of the line to the ground!
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Definitely, first of all, the principle of the leakage protection device is to measure the total current overflow value of three phases or (three phases and four wires), under normal circumstances, the three cables connected to the motor are all stuck with a transformer or clamp meter, and the current should be 0, the reason is that the three phases form a loop between each other, and the flow direction of the current back and forth just cancels out the electromotive force of each other, so the mutual inductance value is basically 0 at this time, if one of the wires is grounded or touches other conductors, part of the current will be shunted, flowing into the earth or other circuits, At this time, the three-phase measurement at the same time, there will be a current, and the current is actually the current flowing into other circuits or the earth, also called leakage current, leakage protection device is to use this feature to protect the back-end equipment or people, the general protection device is protected by the milliampere value of leakage (usually 20mA 50mA 100mA).
1. High-power loads, especially when starting, the multiplied current will cause the motor and cable to appear magnetic field, and the resulting interference magnetic field will forcibly interfere with the protection device, so that the protection device will be triggered by malfunction.
Second, the motor winding and cable are only relatively insulated, under the strong electromagnetic field between each other, there will definitely be a certain leakage value and peak, the principle is the same as the withstand voltage test.
It is recommended to use high-power leakage protection devices, try to choose switches with leakage gear adjustment and strong anti-interference, and then judge the use of working conditions, some equipment in the industry can not use this device, such as: excitation, rectification, grid-connected feedback, etc.
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