5 The remainder of 1 number may be 1234, right?

Wrong. Divide 5 by a number, and the remainder may be 1,2,3. It can't be 4.

For example: 5 2, the remainder is 3;

5 3, the remainder is 2;

5 4, the remainder is 1

5 1=5, divisible, no remainder.

Hope, thank you.

Hello, glad to be able to your question. The remainder of 5 1 number may be 123, but it cannot be 4. So the question is wrong.

If the dividend is an integer, the remainder is likely to be 1234, mainly because the remainder cannot be greater than or equal to the dividend.

5 divided by a number means that 5 is the divisor. The remainder cannot be greater than the divisor, so divide 5 by a number, and the remainder cannot be 1234. The correct way to say it would be 5 divided by a number, and the remainder could be 1 or 2 or 3 or 4

Wrong. 5 1 number remainder may be 1234(True) Analysis: 5 In 5 1 numbers, 5 is the dividend, and "1 number" does not know what it is, so it is wrong to say that the remainder may be 1234.

Wrong. The remainder cannot be greater than (or equal to) the divisor.

Here the dividend is 5, the divisor is 1, the remainder cannot be greater than or equal to the divisor, it cannot be 1, and it cannot be 2, 3, 4.

For example, 5 3 = 1 ......2

2 is smaller than 3.

Wrong. In division with remainders, the remainder is less than the divisor. So 5 is divided by a number, and what is its remainder is determined by the divisor.

No, 5 14 has no remainder, it is an integer. Because this 5 1 = 5

5 divided by a number cannot be 1,2,3,4, but 1,2

Because the remainder of a number divided by 9 is equal to the sum of its numbers divided by the remainder of 9, mu.

The sum of 5151 digits = 12, and the remainder divided by 9 is equal to 3

So 1234....The remainder of 101 9 is 3. Hail celebrations.

There is a remainder, and the remainder is 1.

See the diagram below: the quotient is 6172160 and the remainder is 1.

12344321 divide by 2 and have a remainder.

12344321 2, the quotient is 6172160 the remainder is 2.

The single digit of 12344321 is 1, so 12344321 2 has a remainder (the remainder is 1).

12344321 divide by 2 is definitely a remainder, unless you can tolerate or allow decimals.

Either that 6172160 or 1

There is a remainder, which is 1

Odd numbers divided by 2 have remainders, and the remainders are all 1

There is a remainder, the remainder is 1, and the result is 6172160 remainder 1

900 200 = 9 2 – that's right.

9÷2=4...1 - That's right.

But, overall, the correct answer is: 900 200 = 4 ......100 You can use the inverse operation to excite the slippery lead to sell a letter to tease!

Summary. 9 divided by 5 is the remainder of 4.

9 divided by 5 is the remainder of 4.

Why does the teacher say that the remainder can be 123 and cannot be 4, this sentence is correct Isn't there also an equation where the remainder is 4.

There is a premise for this, such as 13 4 = 3...1, because the divisor is 4, the remainder cannot be 4

In this way, this sentence can be considered correct. Oh. Thank you.

It's okay, it's okay, no thanks.

Wrong. 16÷5=3…1 (read as 3 more than 1).

So the remainder is 1Instead of 3

That's not right. In addition to the Min Na Envy Law, there are only Shang and Yu Qiaopai's statement.

16 5=3 1

Reads as quotient is 3 and the remainder is 1

The remainder of 1000 divided by 36 is 28, and the remainder of 28*1000 divided by 36 is also exactly 28Therefore, the remainder of that super-large number divided by 36 should be 1234 remainders of 28 divided by 36. This is the remainder of 4*28 divided by 36.

Answer: Min Yu Bi's case is 4

In 6, because the vertical divisor of the first lead is 6, if there is a remainder in the excitation town, the remainder may be , whichever is greater;

So the answer is:

We're glad to answer for you! If the remainder is the same, then this number must be the least common multiple of 123 and 234 plus the remainder (the remainder must be less than 123), and the least common multiple of 123 and 234 is 9594. So this number is between 9595 and 9717.