Ask for a few elementary school math problems, a few elementary school math problems

1) 5525 is obviously divisible by the smallest prime number 5 except 1, which is the easiest to see, so after dividing 5, we can get 1105, and the same as above can obviously be divided by 5 again, and we get 221, which is already a prime number, so the 3 prime numbers found are 5,5,221, so the surface area can be s=2(5*5+5*221+5*221)=4470

2) Same as above, 510510 can be clearly seen to be divisible by the smallest prime number 2 in addition to 1 (because it is arranged from small to large, so from the smallest), to get 255255, because 2+5+5+2+5+5=24, divisible by 3, so divided by 3 to get 85085, and so on, we can get the prime factor of 2, 3, 5, 7, 11, 13, 17, so (a-b)*(b-c)*(c-d)*(d-e).=128

1.Decompose 5525 into the product of three prime numbers, 5525 = 5 * 5 * 221, so the length, width and height of the cuboid are , so its surface area is 2 (5 * 5 + 5 * 221 + 5 * 221) = 4470

All different prime factors 2 3 5 7 11 13 17a-b)*(b-c)*(c-d)*(d-e)*=-1 * 2 * 2 * 4 * 2 * 4=128

First the first one: because the volume is the mantissa of 5, so the three books must have a mantissa of 5, so it is simple, and the three numbers are . So that the surface area is understood.

The second, I don't know, right? There are four prime factors. You don't need me, right??

It's still awesome, I was wrong...

2.A + B + C + D = 72

Let A+5=B-5=C*5=D, 5=K

So A=k-5, B=k+5, C=k5, D=5k, so k-5+k+5+k5+k=72

The solution is k=10

So A, B, C, and D are 5, 15, 2, and 50 respectively

3.The number represented by the point c is -3 or 1

The distance between point c and point b is 8 or 4

1. 1+2+3+4+5+6+7+8*9=1002.A 5 B 15 C 2 D 503

Point C, whose distance from point A is equal to 2, represents 1 or -3, and the distance between point C and point B is equal to 4 or 8

+2 + 3 + 4 + 5 + 6 + 7 + 8 9 = 1002, A + B + C + D = 72

A + 5 = B - 5 = C 5 = D 5 = > A = B - 10 C = D 25 = > D = 25 or 50

After calculation, D = 50 C = 2 B = 15 A = 53, the number represented by the point c with a distance equal to 2 is -3 or 1, and the distance between point c and point b is equal to 8 or 4

(1) 1 + 2 2 3 + 4 5 + 6 + 7 8 + 9 = 100 (2) Let the equal number be x, A is x-5, B is x+5, C is x 5, D is 5xx-5 x+5 x 5 5x 72, and the solution is x 10.

x+5=10 x=5

x-5=10 x=15

x×5=10 x=2

x÷5=10 x=50

So A is 5, B is 15, C is 2, and D is 50

3) Point C represents -3 or 1, and the distance between point C and point B is equal to 8 or 4

2.(x+5)+(x-5)+5x+x 5=72x=10 so.

A = 5, B = 15, C = 2, D = 50

3.The number C represents -3 or 1, and the distance from point C to point B is 8 or 4