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Here's how: My Computer-Management-Local Users and Groups-Users.
Find the user you want to delete (administrator can't be deleted, can only be renamed), right-click and select Delete, and that's it.
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Right-click on my desktop computer and select management, you can see one: local users and groups, click on it to see, the users displayed on the left, you can see all your users in the click, then you can delete the users you don't want.
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First, confirm whether your current user has administrator privileges.
2. Right-click "My Computer" on the desktop, select "Management", select "Local Users and Groups", select "Users", and delete the unused users in the user list on the right!
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Generally, in the system, the administrator user tries the system user, and the user can't delete it, but only disables it, and if you try other users, you use the administrator user to log in to the system.
My Computer - Right-click - Manage - Local Users & Groups - Select the user you want to delete.
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Turn on F8 into safe mode.
Click on My Computer, right-click Manage --> Local Users and Groups --> Users, right-click to delete the user you want to delete It should solve the problem.
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Your hard drive is probably NTFS partitioned. There are two users, one is the administrator and the other is the guest user! You can disable the guest user and you're good to go!
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My Computer, right-click Manage --> Local Users & Groups --> Users, right-click to delete the user you want to delete.
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Question 1:
Question 2: Question 3:
Timely praise and acceptance, thank you
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Proof: AE CD, CE AB
The quadrilateral ADCE is a parallelogram.
acb = 90° and d is the midpoint of ab.
cd=ad (the hypotenuse of a right-angled triangle is equal to half of the hypotenuse) The quadrilateral ADCE is a diamond (a parallelogram with equal adjacent sides is a diamond).
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Hello! The homework help customer service is looking for answers for you, only the first defeat Kai asks you to give a dry hole, and the customer service will automatically give you the answer within 5 minutes. Thank you for your great support of Homework Helper!!
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The student did not do work on the wall, so there was no positive or negative work. Exclude CDs.
In my opinion, if you choose A, you are subjected to a reaction force by the wall, and the angle between the direction of the force and the displacement direction of the point of action of the force is less than 90° and greater than or equal to 0°.
First of all, it is necessary to make clear that there are three situations in which no work has been done on the object:
1. The object is not affected by force in the direction of motion, and due to inertia passing a certain distance, there is no force to do work on the object.
2. The object is acted on by the force, but the object is stationary and there is no passing distance in the direction of the force, and this force does not do work on the object. (So exclude option c).
3. The object is affected by the force, and the object is also moving, but the direction of motion is always perpendicular to the direction of the force, that is, the distance of the object moving in the direction of the force is zero, and this force does not do work on the object.
Secondly, positive work is when the angle between the direction of the force and the displacement direction of the point of action of the force is less than 90° and greater than or equal to 0° (i.e., the acute angle), and the positive work is done according to the formula force a.
Negative work is regarded as when the angle between the direction of force and the direction of displacement of the force is greater than 90° and less than or equal to 180°, then cos 0, according to the formula, the work is negative.
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a!If you have a problem, hi me directly, and I will give you a detailed explanation!
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Choose A! The walls are not displaced by force! The shares did not work.
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