Master of mathematical probability, master of mathematical probability

Binomial distribution: "the probability of an outcome event occurring remains constant throughout the series of trials", which is equivalent to putting back sampling;

Hypergeometric distribution: Yes no put-back sampling.

The reason why you don't put it back is because you take three at a time and take it three times at a time, if you take out three at a time and take one at a time in three times in a hypergeometric distribution, is there exactly the same probability of a defective product? Same.

If you put it back, you can't put it back at once, because in fact, three times may draw the same one, which is not the same as taking three at a time.

However, there is a situation where it is put back, and the situation is the same before each sampling, so the probability of defective products is equal each time

I don't know how many cards, if it is 1 deck of cards to remove the big and small king 52 cards, then each time take out 2 cards of equal size there are 52 * 3 kinds.

And each time to take out 2 cards there are 52 * 51 kinds, so the probability of equal size is 3 51 minus the equal size of the case, the remaining probability of winning or losing should be half, that is, winning and losing are (1-3 51) 2 = 24 51

In the case of excluding the possibility of cheating by the bookmaker, this is what it depends on.

Nine out of ten bets are lost, and theoretically, the odds of the player winning are always less than the banker's.

The probability of 2 cards being equal is 3 51. That is, the probability that the dealer will definitely win. In other cases, because the dealer is winning small and losing big, and the situation of 2 sides of the bet, according to the probability should be the same, that is, in terms of probability, when there are 2 cards of different sizes, the dealer is also a draw (because the money on the small side is paid to the big side).

Because of the existence of the probability of 3 51, the dealer seems to win for a long time. The probability of the player winning money is only 24 51 each time, less than half, in terms of probability, it is certain to lose in the long run, there is no trick.

Even if the 0 score is counted, if it all appears, it will be 5 points at the end, and 100 is impossible. p=0

I don't know what this question is, what is called "drawing black and white balls with different probabilities", in the case of 21 black balls and 9 white balls, the probability of drawing black balls and white balls must be 21:9=7:3, it can't be 1:2, the landlord doesn't understand the probability.

There are many more black balls than white balls, and the probability ratio of drawing black balls to white balls is 1:2

2.There are ten points for removing the pair, with a chance of 4 10= and less than 5 5 10=

Give me two thousand dollars, and I'll figure it out for you.

Set this mountain forest eggplant high judgment in the state of about x birds.

200 x = 10 150 can be solved x = 3000

200*150 10=3000 This is also OK.

,.. triangles, squares, and pentagonsThe sequential numbers are: a, b, c, d, e, f then draw to a, the inlay plane is: a, b, c, d, e, f to b, and the inlay plane is: b, d, e, f

Draw to c, the inlay plane is: c, f

Draw d, the inlay plane is: d

Draw to e, the plane that can be mosaic in the morning is: e

Draw to f, can be inlaid flat sleepy age face is: f

6 Lu Qi such as (6+4+2+1+1+1).

Use different shapes of cards to inlay different shapes of planes, such as using triangular cards to inlay triangle planes, hexagonal planes, and so on.

The total selection is c6 (8+5)=c6 13

Boys and girls each choose Qingdou 3, and the selection method is c3 Zheng Zheng brother 8 + c3 5

Therefore, the probability of 3 boys and 3 girls = (c3 8 + c3 5) shouting c6 13 = (56 + 10) (13 * 12 * 11) = 1 26

Any 6 people are always likely to be C13(6)=1716

3 male bioquibs: c8(3)=56

3 female students: c5(3)=10

The probability of the photographed worm is 56 * 10 1716 = 140 429