The diagonal of a square is 4 decimeters, and what is its area

The square is a special diamond, and the area algorithm is the same as the diamond (i.e. half of the diagonal product).

s = 4 * 4 * square decimeters.

The area is 8 square decimeters.

Since the diagonal length is 4 decimeters, the side length is 4 2 = 2 2 decimeters, so the area is (2 2) 2 = 8 square decimeters.

Because the diagonal is 4 decimeters long and the four sides of the square are equal, the square side length is (4 2 2) = 8 (dm).

So the square area is 8 2=8(dm).

The best way to calculate this is the area of the diamond = the product of the two diagonals divided by 2

So it's 4*4 2=8

The square is also diamond-shaped.

It's time to use the Pythagorean theorem.

Let the sides of the square be x decimeters.

x squared 2 = 4 decimeters squared.

The solution is x = root number 8 = the length of the side of the square.

s square = side length side length = root number 8 root number 8 = 8 square decimeters.

Diagonal 4dm

2 times the length of the side root 2dm

The area is 8dm*2

Let the sides of the square be x decimeters.

x squared 2 = 4 decimeters squared.

The solution is x = root number 8 = the length of the side of the square.

s square = side length side length = root number 8 root number 8 = 8 square decimeters pkpk'l;'l[pl

The square is divided into two isosceles RT triangles.

Each base angle is 45°

Side length = 4 2 = 2 2 (dm).

2√2）∧2=8（dm∧2）

Quadratic functions in 5th grade? ）

Break the square diagonally into two right triangles, and then put the two triangles together into a right triangle with a base length of the diagonal and a height as long as the diagonal, and then the base * height is 2, and you get it.

Its area is 8 square centimeters.

The solution process is as follows, let the side length of the square be a cm, according to the nature of the square: the four sides are equal, and the four corners are right angles, so the diagonal is equal to 2 times a square is equal to 16, then the square of a is equal to 8 is equal to the area of the square.

According to the inscription, it can be known:

The diagonal of the square is 4 cm, which, according to the characteristics of the square, divides the square into two isosceles right triangles. From the Pythagorean theorem, the side length of the square can be found to be 2 times the root number two.

Therefore, the area of the square can be found as:

S is 2 times the root number 2 2 times the root number 2 8 square centimeters.

The square diagonal divides the square into two right triangles, and the intersection divides the diagonal in two.

The triangle area formula base multiplies the height divided by 2

A: Its area is 8 square centimeters.

Its area is 8 square centimeters.

If the length of the side is x, then the square of x is equal to the area of the square.

The diagonal divides the square into two isosceles right triangles, according to the trilateral relationship formula of an isosceles triangle: a + b = c

a, b are equal, c = 4 cm. The result is a=2, i.e. the square side length is 2 cm. Area s = 2 = 4 square centimeters.

A diagonal line of a square piece of paper is 4 centimeters long, and its area is (8) square centimeters.

A diagonal line of a square piece of paper is 4 cm long, and the side length is 4 2 cm, 4 2)2 = 8 (square centimeters).

So its area is 8 square centimeters.

A diagonal line of a square piece of paper is 4 centimeters long, and its area is the square of the diagonal divided by 2, i.e. 4 2 = 8 (square centimeters).

The four corners of the square are all right angles, so according to the Pythagorean theorem:

Square diagonal length squared = sum of squares of the sides of the square = 2x sides squared.

So the square of the side length = 4x4 2 = 8 square centimeters.

The area of the square is equal to the square of the length of the side.

So the area of the square = 8 square centimeters.

The calculation process is as follows:

4 2 = 2 (cm).

4 2 2 = 4 (square centimeters).

4 2 = 8 (square centimeters).

A: Its area is 8 square centimeters.

Hello, this question has been answered.

If you are satisfied, please click.

2a 2 = 16 and a 2 = 8, so its area is 8 square centimeters.

According to the Pythagorean theorem or trigonometric function, calculate the side length of a square, for example, if the side length is a, then there is: a 2 + a 2 = 4 2, 2a 2 = 16

a 2 = 8 (square centimeters), i.e. the area of a square is 8 square centimeters.

It is known that the diagonal of the square is: 4 cm, then: the diagonal divides the square into two isosceles right triangles, and the right angle is the side length of the square.

According to the Pythagorean theorem: hypotenuse square 2 right angle side squared.

4 2 = 2 square of the right angled side, square the right angle side 16 2 8 The area of the square The square of the length of the side of the square The square of the right angle of the right side of the triangle 8 square centimeters.

Let the side length of the square be a, then.

2a^2=4^2

a 2 = 8 So, the area of a square is 8 square centimeters.

It has an area of 8 square centimeters.

4 2 = 2 (cm).

4 2 2 = 4 (square centimeters).

4 2 = 8 (square centimeters).

The diagonal is 4 cm, then the side length of this square is 2 cm, and the area is the side length multiplied by the side length, which is 2x2=4

Since the diagonal of the square is equal to twice the length of the sides, the side length is 4 2 = 2 2 cm, and the area is 2 2 2 2 = 8 square centimeters.

4x4 2 8 cm².

A: Its area is 8 square centimeters.

The area of the square is: diagonal*diagonal2

His area is 8 square centimeters.

A diagonal line of a square piece of paper is 4 centimeters long, and its area is ( ) square centimeters?

4x4 2 8 cm².

The area of the square is equal to the length of the side of the side.

It can also be represented as a diagonal.

Diagonal 2 so the square area is.

4 4 2 = 8 square centimeters.

The area of this square can be calculated like this:

8 square centimeters.

SquareIf you know the diagonal length, then the area = (1 2) x diagonal = (1 2) x 4 = 8 square centimeters.

Square area = diagonal 2

8 square centimeters.

Let the sides of the square be a centimeter long.

From RT, we can get: a squared + a squared = 4 squared.

The solution yields the root number 2 of a = 2 times

The area of the square: s=a=8

Think of it as two triangles, so the square area is equal to 4 4 2 = 8

Square area 1 2 4 4

8 square centimeters.

The square area is multiplied diagonally by diagonals divided by 2

4 4 2 = 8 (square decimeter), A: The area of this square is 8 square decimeters

So the answer is: 8

Because it is a positive disturbance carrying square, the diagonal can divide the square into two triangles, and the bottom of this triangle is the diagonal, and the height is half of the diagonal, so the area of this square is the sum of the two triangles, the area of a triangle is the bottom * height 2 that is, 4 * 2 2 = 4 square decimeters, and the square area is 4 * 2 = 8 square decimeters.

Diagonal. The length is meters.

The Pythagorean law of a right triangle.

The square of the diagonal = square of the side length + square of the side length.

Pair of lease leakage angle line = 2 times the root number of the side length.

I hope I can help you, I understand

Area of the square = side length * side length = side length 2

The side length of a square of 4 square meters at a time is equal to 4 kai, and the square is equal to 2 meters. Therefore, the side length of the square is 20 decimeters (1 meter = 10 decimeters).

Solution: Area of the square = side length x side length;

Square circumference = side length x4

The area of the square is 4 square decimeters, the side length is 2 decimeters, and the circumference is 8 decimeters.

The area of the square is 4 square decimeters, how many decimeters are the side lengths, and what are the decimeters in circumference?

Solution: Let the side length be a decimeter, according to the topic, get.

a²=4a=±2

a1=2, a2=-2 (not in place, discard).

c = 4a = 4 2 = 8 (decimeter).

A: The side length is 2 decimeters, and the circumference is 8 decimeters.

4=2x2

So the side length is 2 decimeters.

Circumference 2x4=8 dm.

The length of this square diagonal is 2 2 cm.

Because the area of the square s=a = 4 and a is the length of the sides of the square, the diagonal and side lengths of the a=2 square form an equilateral right triangle with the diagonal as the hypotenuse, so the length of the diagonal = 2 + 2 = 2 2