Of the 23 apples, 22 are balanced, and one is not, and can only be weighed three times, how do you w

Suppose "one" apple is heavier (and the same is true) than the other

1. Divide the apples into five piles

2. Weigh 9 and 9 (1 time), if the weight is equal, weigh 2 and 2 (2 times), if it is equal, then "there is one" apple is the remaining one.

3. Weigh 9 and 9 (1 time), if the weight is equal, weigh 2 and 2 (2 times), if not equal, divide the heavier pile into pieces, and weigh (3 times), the heavier one is.

4. Weigh 9 and 9 (1 time), if the weight is not equal, divide the heavy pile into two, weigh any two of them (2 times), if the weight is equal, it is the heavy pile, and the unequal is the pile that is not weighed, and find a heavy one among the 3, right? (Weigh two as you like) (3 times).

OK! Just the numbers for words:

Divided into , if 9=9, 2=2, is 1; If 9=9,2≠2, it is the heavy one on the heavy side; If 2 = 2, 9≠9, divide the heap and call it arbitrary, =, in the pile that is not weighed, and ≠ in the heap.

I don't know how to ask me, q337665218, the mailbox is QQ mailbox.

Choose any 14 7:7 as well. Take 6 of the 9 3:3 if the remaining 3 are 1:1, such as 3:3 is not the same as the heavy side 1:1

For example, 7:7 is different. Take 6 3:3 on the side of the heavy one, take one for the same heavy one, and take 2 1:1 for the side that is not the same weight

If the apple is lighter, use the lighter side than the other).

This question is a variant of Microsoft's puzzle question, the original question is, 1 out of 12 balls is different from the weight of other balls, I don't know whether it is heavier or lighter, the weight of other balls is the same, and the appearance is not different. Use the scale 3 times to find the different balls and know if the ball is heavy or light. If this question is answered, your question will be easy to answer.

Because we only need to take 12 to do it, and if we can't find the bad one out of 12 by weighing it three times, it must be the 13th, but we can't know whether it's heavy or light.

Here are the names of the 12 ones.

Divide 12 into 1 to 12 1 4 group, 5 8 group, 9 12 group Put 1 4 and 5 8 on both sides of the scale, and weigh The result of the first weighing is three: a: balance b:

1 No. 4 heavy c: 1 No. 4 light a: Explain that 1 8 is good, 9 12 has unequal weight Put 9 11 and 1 3 on both ends of the balance, and weigh the result of the second weighing

A1: Balance: Explain that No. 12 is unequal, compare No. 12 with No. 1 to know the weight A2:

9 11 is heavy, indicating that there is a heavier of 9 10, and 9 and 10 are called, who is heavier and who is heavier, equal to 11 is heavier A3: 9 11 is lighter, and 9 10 is lighter, 9 and 10 are called, who is lighter and who is lighter, equal to 11 is light b: Explain that 9 12 is good, either 1 4 is heavy, or 5 8 is light, put 1, 2, 5 and 3, 4, 9 on both ends of the scale, weigh.

There are three results of the second weighing: B1: Balance B2:

1,2,5 is heavy b3: 1,2,5 is light b1: 1 5 is good, 6,7,8 is light, 6 and 7 are called, who is lighter and who is lighter, equal to 8 is light b2:

Explain that No. 1 and No. 2 are more important, and No. 1 and No. 2 are called, and who is heavier and who is heavier. B3: Explain that either No. 5 is light, or there is a heavier No. 3 and No. 4, who is heavier and who is heavier, equal to No. 5 is lighter The same reason as case B (if you don't understand what is the same, you can change No. 1 4 to No. 5 6, and No. 5 6 to No. 1 4).

Let the unknown apple weigh xWeigh 13 total weights z first, then randomly select 2 from 13, weigh the weight a, b: 1 respectively, if a=b, then x=z-12a; 2. If A is not equal to B, it must be A or B, then test A=Z-12B and B=Z-12A, which holds X is which!

22 (8,8,6), put two groups of 8 on the balance of the cherry blossom roll, you can find out a group of defective products, and then put 8 (3,3,2), you can find a group of defective products, and then divide 3 into (1,1,1), you can find out the defective products, you need to 3 times

If the defective product is in a group of 7, then divide the 8 into (3,3,1) put two 3 groups on the balance and weigh, can be found out a group of defective products, and then 3 into (1,1,1), you can find out the defective products need 3 times

If it is in a group of 1, it takes 2 times to find out the defective product directly

Therefore, with the balance scale, at least 3 times can ensure that the defective parts are found, so the answer is: 3

The first time: take 12 apples from 13 apples, divide them into 2 equal parts, 6 pieces each, and place them at both ends of the balance scale, if the balance scale is balanced, then the apple is lighter in weight, if it is not balanced, the second time: divide the 6 apples at the higher end of the balance scale into 2 equal parts, 3 in each portion, and put them at both ends of the balance scale, and the third time: take 2 of the 3 apples in the higher end of the balance scale, and put them at both ends of the balance scale, if the balance scale is balanced, then the apple that is not taken is the lighter weight, if it is not balancedThe apples at the higher end of the scale are the lighter apples, so the answer is: three

2 apples = 3 peaches.

Let the weight of a single peach be and x, and the weight of a single apple be y, which is obtained by the balance of the balance and the balance of the sail

4x+2y=x+4y

2y=3x So 2 apples = 3 peaches.

I don't understand what it means 2 pcs?

(1) Divide the 12 apples into two groups: 6 in 1 group, and weigh them for the first time, then the defective products are in the lighter group;

2) Divide the lighter 6 apples into 2 groups: 3 for 1 group, and weigh them a second time, so that the defective products are in the lighter group;

3) Divide the lighter 3 apples into 3 groups: 1 group of 1 and 1 left, if the left and right are equal, then the remaining one is defective, if the left and right are not equal, then the lighter one is defective, A: So after 3 times you can find out the lighter quality of the apple, so the answer is: 3