A third grade math problem called for help

If you haven't learned equations in the third grade now, that's it.

Drawing a basketball and a soccer ball on a piece of paper and then drawing an equal sign equals drawing a football and a volleyball = again

Draw basketball and volleyball again =

So you tell him that the price of the hand, which adds up to 2 basketballs, 2 soccer balls, and 2 volleyballs, is 98

Divide this total by 2 to get 1 basketball, 1 football, and 1 volleyball, for a total price of 49 yuan.

If a basketball and soccer dollar are given in the question, then the price of basketball, soccer and volleyball together is subtracted from the price of basketball and soccer ball, which is the price of volleyball, and so on.

When I talk about it, I use a small picture to say that I can draw it if I subtract it, so that it is more intuitive and easy for children to understand. The columnar form is.

Volleyball. Basketball. Football.

Let basketball be $x, football $y, and volleyball $z.

x+y＝y+z＝

X+Z Synoptic. x+

x＝ y＝ z＝

Put, add up, that is, basketball, volleyball, soccer each 1 add up to *2 money, so to 2, and then subtract the price of basketball and soccer in turn, the price of soccer and volleyball, the price of basketball and volleyball, you can calculate the price of volleyball, basketball, and soccer in turn!

1 Soccer 1 Basketball 2 Volleyball The sum of the four balls.

1 basketball 1 soccer ball The difference between two balls.

The total price of a basketball and a soccer ball (yuan) The difference between a basketball and a soccer ball (yuan) The price of two soccer balls (yuan) is divided by 2, which is the price of a soccer ball (yuan).

The total price of 1 basketball and 1 soccer ball minus the football (yuan) is the ** (yuan) of basketball.

The total price of 1 basketball and 1 volleyball minus the basketball's ** (yuan) is the ** (yuan) of volleyball.

You can start with this:

Basketball + Football = Meta.

Football + Volleyball = Yuan.

Basketball + Volleyball = Meta.

It can be found that in the three equations, there are 2 basketballs, 2 footballs, and 2 volleyballs. You can add up the three equations:

Yuan) is calculated as 2 basketballs, 2 footballs, and 2 volleyballs. According to this condition, you can calculate how much is the sum of 1 basketball, 1 football, 1 volleyball: 98 2 = 49 (yuan) and then look at the column formula in front:

Basketball + football = yuan But the sum of the three of them is known to be 49, with yuan) is to remove basketball and football, leaving a volleyball money of several yuan. And then let's look at the second column: Football + Volleyball = Yuan According to the previous method, the sum of the three balls is basketball.

Basketball and volleyball are all known, and subtracting basketball and volleyball from the total amount of money from their three balls is football: yuan).

I've been detailed enough, but it's my original. Others may copy me, don't be deceived, you must choose me!

Also, no one is allowed to plagiarize, otherwise

Same as the answer above!

It is to add football and volleyball to basketball and volleyball, then it becomes 2 volleyballs and 1 football and 1 basketball, then the equation is set up to subtract the number of football and basketball and divide by 2 to calculate volleyball. Then the comprehensive equation is: (is the number of volleyballs.)

Then the number of football and basketball can be counted, and I won't talk about it.

This third-grade math problem is to multiply a number by 15. The largest can get a three-digit number. There is also the smallest number that can get 4 digits. 999÷15=。So the first number is, and the second number is 67.

Analysis: The sales volume of A mineral water is 4 times that of B mineral water, that is, if B mineral water is one part, A mineral water is 4B, and together it is 5 parts B mineral water. Because A mineral water and B mineral water were sold in the morning, a total of 275 bottles of 275 bottles were sold, of which B mineral water accounted for 1 part, so the number of B mineral water bottles sold was:

275 (1+4) = 55 (bottle).

A The number of bottles of mineral water sold is: 275-55 = 220 (bottles).