Elementary school 3rd grade math condensed difficult solutions, 3rd grade math puzzles

The average weight of the orange is 2 kg less than that of the three fruits, so in the average division, the apple and the pear should be evenly divided into 2 kg of the orange, and the orange becomes the average, and the weight of the apple and pear together: 10 + 6-2 = 14 (kg).

You only need to divide the remaining apples and pears equally: 14 2 = 7 (kg) and the three fruits will be divided equally.

The average of the three fruits is: 7 kg.

The weight of oranges is: 7-2 = 5 (kg).

Suggestion: It is best to let the child swing with his hands to be more visual and intuitive, and feel the average score.

Bought 5 kg of oranges.

The weight is an integer:

Apples, pears, oranges, average weight.

10 6 11 9 11 is greater than 9

7-5=2 is in line with the topic.

Solution: Let oranges be x kilograms.

10+6+x)/3=x+2

16+x)/3=x+2

16x(1/3)+(1/3)x=x+2

16/3=x+2-(1/3)x

16/3=(2/3)x+2

16/3)-2=(2/3)x

3 and (1 3) = (2 3) x

x=3 and (1 3) (2 3).

x=5 x is an unknown x is a multiplication sign and the unknown x cannot be set aside on its own.

Set oranges x kilograms.

This yields x=(10+6+x) 3-2 x=5

Oranges 5 kg.

This question hurts the eye.

First of all, let's be clear, there is a two-fold quantitative relationship.

For example, if A has 6 flowers, then A will give B 6 flowers, and B will have 12 flowers, which means that there is a 2-fold relationship.

After figuring out this relationship, this question uses the backward method:

The total number of flowers is clear, 72 in total.

After the C split, the number of flowers of the three is: A 24 B 24 C 24 Total 72

According to the two-fold relationship, A has 12 flowers and B has 12 flowers before the C flower, and according to the total number of 72 flowers, C has 48 flowers.

That is, before the C flower (that is, after the B flower), the number of flowers of the three people is: A 12 B 12 C 48

In the same way, it can be determined that the number of flowers of the three people before the second division is: A6 B42 C24

Further, the number of flowers of the three people before the division of A is determined as: A39 B21 C12

That is, the original number of flowers of A, B and C was 39, 21 and 12 respectively.

The number of flowers in A, B and C was 39, 21 and 12 respectively.

Solution: Let A, B, and C originally have x, y, and z duos.

1) After A gives B C:

A: x-y-z

B: 2yC: 2z

2) After B gives A and C:

A: 2 (x-y-z).

B: 2y-(x-y-z)-2z=3y-x-zC: 4z

3) After C is given to A and B:

A: 4 (x-y-z).

B: 2 (3y-x-z).

C: 4z-2(x-y-z)-2(3y-x-z)=2z-y 4(x-y-z)=24 (a).

2（3y-x-z）=24 （b）

2z-y=24 (c) Solve the system of equations composed of abc to obtain: x=81;y=42；z=33, that is, A has 81 flowers, B has 42 flowers, and C has 33 flowers.

Solution: A gives B according to the existing number of paper flowers in B, and then gives C the existing number according to C, B gives the same number of flowers to A, at this time A has the remaining 2 times, and C gives the same number of flowers, at this time A is the remaining 2 * 2 = 4 times, at this time A has 24 flowers, then the remaining flowers after A gives B and C are 24 4 = 6, and it is just the same as the flowers in B C's hand.

There are a total of 24 3 = 72 flowers, so the flowers given out are (72-6) 2 = 33 then A, there are 33 flowers + 6 = 39 flowers, so there are 33 flowers in the original B and C.

Because there are 24 flowers in the end, before C gives flowers to A and B, A and B have 12 flowers each, and C's flowers are 72-12-12 = 48 flowers.

Then the original flowers of C are 48 2 2 = 12 flowers.

B's original flowers were 33-12=21.

Answer: It turns out that A, B and C each have 39, 21 and 12 paper flowers.

1 pineapple = 2 pears, 1 pineapple = 2 peaches + 1 banana + 1 pear, you can deduce that 1 pear = 2 peaches + 1 banana.

In this way, 1 pineapple = 2 peaches + 1 banana + 2 peaches + 1 banana, that is, 1 pineapple = 4 peaches + 2 bananas.

And 1 pineapple = 4 bananas, so 4 peaches = 2 bananas, i.e. 1 banana = 2 peaches, so 1 pineapple = 8 peaches = kilograms.

2 kg is simpler because 1 pineapple = 2 pears so 1 pear = half of a pineapple.

Since 1 pineapple = 4 bananas, so 1 banana = a quarter of a pineapple, so 2/2 + 1/4 = 3/4 according to the final equation.

2 peaches = a quarter of a pineapple i.e. a quarter of the mass of a pineapple is.

2 times then divide by a quarter = 2 then the mass of a pineapple is 2 kilograms.

1 pineapple = 2 peaches + 1 banana + 1 pear.

4 pineapples = 8 peaches + 4 bananas + 4 pears.

8 peaches + 1 pineapple + 2 pineapple (because 1 pineapple = 2 pears; 1 pineapple = 4 bananas).

That is: 4 pineapples = 8 peaches + 3 pineapples.

So: 1 pineapple = 8 peaches.

x 82 (kg).

Solution: 1 pineapple = 2 peaches + 1 banana + 1 pear.

1 pineapple = 2 peaches + 1 4 pineapples + 1 2 pineapples.

1 pineapple - 1 4 pineapple - 1 2 pineapple = 2 peaches.

1 4 pineapples = 2 peaches.

1 pineapple = 8 peaches = 8 * kg).

1 pineapple = 2 pears;

1 pineapple = 4 bananas).

1 pineapple = 2 peaches + 1 banana + 1 pear.

4 pineapples = 8 peaches + 4 bananas + 4 pears.

4 pineapples = 8 peaches + 1 pineapple + 2 pineapples.

1 pineapple = 8 peaches = 8 * kg).

1 pineapple = 2 pears, so 1 pear = pineapple;

1 pineapple = 4 bananas, so 1 banana = pineapple;

1 pineapple = 2 peaches + 1 banana + 1 pear.

It can be converted to: 1 pineapple = 2 peaches + pineapple + pineapple.

Pineapple = 2 peaches = 2*kg.

So: 1 pineapple = = 2 kg.

Since there is only the quality of peaches, our first idea was to associate pineapple with peaches only. From the remarks, it can be seen that a pear is equal to a pineapple. One banana is equal to one pineapple.

So: one pineapple = one pineapple + one pineapple + two peaches.

So one pineapple = 8 peaches.

So one pineapple weighs 2 kg.

Grade 3 Math Addition Oral Arithmetic Problems.

3rd grade math subtraction oral arithmetic problems.

Grade 3 math multiplication oral arithmetic problems.

Grade 3 math division oral arithmetic problems.

One drink 300 ml. Xiao Ming drank one-half of a drink, Xiao Qiang drank two-thirds of a drink, how many milliliters did they each drink?

Xiao Ming: 300 times half equals 150 ml.

Xiaoqiang: 300 times two-thirds equals 200 ml.

Answer: "Xiao Ming drank 150 ml, Xiao Qiang drank 200 ml. ”