How do I play with a bottle of barium nitrate? What experiments can be done?

1) In experiment 1, sodium carbonate can react with barium nitrate to form barium carbonate precipitate and sodium nitrate, so the white precipitate is barium carbonate; In experiment 3, the precipitated barium carbonate can react with dilute nitric acid to form barium nitrate, carbon dioxide and water, so the crystal obtained by evaporating the solution is barium nitrate; The addition of dilute nitric acid in experiment 4 can react with excess sodium carbonate to produce water, carbon dioxide and sodium nitrate; Therefore, the solution obtained by evaporating 4 in experiment 5 yields sodium nitrate.

2) Experiment 1: Excessive Na2CO3 solution was added to allow the barium nitrate to completely react into barium carbonate;

3) In experiment 4, nitric acid was added to the filtrate in order to remove the excess sodium carbonate and turn it into sodium nitrate;

4) In experiment 1, sodium carbonate can react with barium nitrate to generate barium carbonate precipitate and sodium nitrate;

In experiment 3, precipitated barium carbonate can react with dilute nitric acid to produce barium nitrate, carbon dioxide and water.

The addition of dilute nitric acid in experiment 4 can react with excess sodium carbonate to produce water, carbon dioxide, and sodium nitrate Answer: (1) Barium carbonate; barium nitrate; Sodium nitrate;

2) Experiment 1: Excessive Na2CO3 solution was added to allow the barium nitrate to completely react into barium carbonate;

3) In experiment 4, nitric acid was added to the filtrate in order to remove the excess sodium carbonate and turn it into sodium nitrate;

4）ba（no3）2+na2co3=baco3↓+2nano3；

baco3+2hno3=ba（no3）2+h2o+co2↑；

na2co3+2hno3=2nano3+h2o+co2

Dip the wire in the solution and burn it over fire.

Add sulfuric acid or sodium sulfate, there will be a white precipitate.

Nitric acid + barium = barium nitrate.

Choose one of the two answers above.

All substances formed by nitrate ions and sodium ions are soluble in water, barium ions can be converted into precipitate first, sodium nitrate is obtained by filtration, and then the precipitate is dissolved with nitric acid to obtain sodium nitrate, sodium carbonate is added to the mixture first, all barium ions are converted into barium carbonate precipitate, sodium nitrate is obtained by filtration, and then an appropriate amount of nitric acid is added to the barium carbonate precipitate to convert all the precipitate into barium nitrate, so the answer is: Na2

CO3 dilute Hno3

nano3ba（no3

All substances formed by nitrate ions and sodium ions are soluble in water, barium ions can be converted into precipitate first, sodium nitrate is obtained by filtration, and then the precipitate is dissolved with nitric acid to obtain sodium nitrate, sodium carbonate is added to the mixture first, all barium ions are converted into barium carbonate precipitate, sodium nitrate is obtained by filtration, and then an appropriate amount of nitric acid is added to the barium carbonate precipitate to convert all the precipitate into barium nitrate, so the answer is: Na2

CO3 dilute Hno3

nano3ba（no3