Math problems, from 1 to 9, can not repeat numbers, each number can only appear once, fill in the fo

Quite simply, there are two ways to do this:

1. For any equation, there may be the following situations.

Odd + Odd = Even.

Odd + Even = Odd.

Even + Even = Even.

In either case, for an equation, odd numbers will always appear even times, and even numbers will appear odd times. So, for the three equations in the original question, there should be odd even numbers, and even odd numbers. And in 1-9 is an odd number of odd numbers and even numbers is an even number, which is obviously contradictory, so there is no solution.

2. In fact, the second formula can also be written in the form of ()+=(). So it's three ()+=(). You might want to set it to a+b=c

d+e=fh+i=j

Adding up the three equations, there is a+b+d+e+h+i=c+f+j

Add c+f+j on both sides, and there is a+b+c+d+e+f+g+h+i+j=2(c+f+j).

The left side of the equation is exactly 1+2+3+4+5+6+7+8+9=45 is an odd number, but the right side of the equation 2(c+f+j) is an even number, so it is contradictory.

Therefore, there is no solution to this problem.

Perfect, right?

There is no solution to this question.

The addition of several numbers on either side of the equation of addition and subtraction must result in an even number.

For example, 2+3=5 then the sum of 2+3+5 must be even, and 7-3=4 then the sum of 7+3+4 must also be even).

Then the sum of the nine numbers of the three equations must be even.

And 1 9 adds up to 45 for an odd number. So there is no solution!

There's something wrong with this question! The single digit of the subtraction can only be filled in as "6", but it cannot be repeated with the number required in the question (the ten digits of the difference are already 6). Regardless of the requirements in this question, there can be the following two filling results:

There are only two answers: (9) 4 (2) (6) 68, or (8) 4 (1) (6) 68, but there are always numbers that repeat the difference in the subtracted or subtracted numbers.

=-=73+4=9-2=7*1=56 8 First consider the potato line *=7 because 7 is a prime number, so only 1*7=7*1=7, here 1 and 7 are used and then consider -=7, only 9-2=8-1=7 because 1 is used in front So only 9-2=7, here 2 and 9 are used in the look +=7 has 1+6=2+5=3+4=4+3=5+2=6+1=7 because the previous number is used 1,2,7,9.

There is no solution to this question. If you don't say that you fill in 10 blanks with 9 numbers, it is impossible to use 0 to 9 without repeating.

First of all, ()6+()=74, then the third blank can only be filled with 8

Then ()2-()=63 then the third blank can only be filled with 9The first empty can only be greater than 6, and the first 8 and 9 are used so it can only be 7The second null can only be 0

()=82 The single digit of the sum of the second empty + the fourth empty is 2 It can't be 1+1 , it can't be 2+0 0 repeated, it can't be 3+9 9 repeated, it can't be 4+8 8 it repeats It can't be 5+7 7 also repeats It can't be 6+6

Therefore, there is no solution to this problem.