Urgently looking for the solution to this Ioth math problem High score find

Solution: According to the topic.

The average score of the top six = the average score of the top ten + 3

This shows that when calculating the average score of the top 10 players, the top six people have a total of 3 6 = 18 (points) more to make up for the score of the bottom four, so the average score of the bottom four is less than the average score of the top 10.

18 4 = points).

When the last four people are adjusted to the second prize, the second prize has a total of 20 + 4 = 24 (people), and the average increase of 1 point per person is provided by the four people who are adjusted, and each person is provided equally.

24 4 = 6 (min).

The average score of the last four = (the average score of the original second prize) + 6

Compared with the average score of the first six people calculated earlier, it is known that the average score of the original first prize is more than the average score of the original second prize.

points).A: At this time, the average score of the first prize is higher than the average score of the second prize.

2 yuan 1st order equation.

The average score of the 1st prize is x, and the 2nd prize is y

The total score of the first class is 10x, and then 6*(x+3), the total score of 4x-182 and so on is 20y, and then 24*(y+1), and the total score of 4 people is 24+4y4x-18=24+4y, x-y = so the average of the first class is higher than that of the second class.

It's too fast to answer in detail! Khan!

Solution: Set the average score of the first prize x points and the average score of the second prize y points.

10x+20y=(10-4)*(x+3)+(20+4)*(y+1)10x+20y=6*(x+3)+24*(y+1)10x+20y=6x+18+24y+24

10x+20y=6x+24y+42

4x=4y+42

x=y+x-y=

It's too simple, it's stupid. Such a simple question is worth 100 points.

So is the second prize now 24 people?!

Let the unknown numbers x and y be the average score of the original first and second prizes, respectively, then the total score of all people is:

10x＋20y

After adjusting the rankings:

6（x+3）＋24（y＋1）

No matter how they adjust, the total score of all of them will not change, namely:

10x 20y 6(x+3) 24(y 1) x-y after simplification

So it turns out that the average score of the first prize is higher than that of the second prize.

The total score of the first prize is 10x

The total score of the second prize is 20y

After the change. The total score of the first prize is 6 (x+3).

The total score of the second prize is 24 (Y+1).

10x-6(x+3)

24(y+1)-20y

10x-6(x+3)=24(y+1)-20yx-y=multi-points.

The last 4 people in the first prize are gone, and the remaining 6 people will be improved by 3 points each, totaling 18 points (4 people will have less points than the average score of the first prize.)

The second prize came 4 people 1 to all 24 people each increased by 1 point Total 24 points (4 people have more points than the average score of the second prize.)

That's a 42-point difference, which is four times the average difference between the first prize and the second prize.

Therefore, the average score of the first prize is higher than that of the second prize.

The average score of the first prize is A, the average score of the second prize is B, the average score of the first six people is C, and the average score of the last four students is DThere is the following formula.

6*c+4*d=10*a;

c=a+3;

4*d+20*b=24*(b+1)

Solution: 10 out of 5.

Let the average score of the first prize be x and the average score of the second prize be y, then the average score of the first prize will be (x+3) and the average score of the second prize will be (y+1).

10x+20y=(10-4)(x+3)+(20+4)(y+1)10x+20y=6x+18+24y+24

10x-6x+20y-24y=18+24

4x-4y=42

4(x-y)=42

x-y = the average score of the original first prize is higher than the average score of the second prize.

Let the average score of the original first prize be x, the average score of the second prize is y, and the total score of the last 4 people of the first prize is z, then:

The original total score of the first prize is 10x, the total score of the second prize is 20y, the total score of the adjusted first prize is 10x-z, the average score is x+1, the total score of the adjusted second prize is 20y+z, and the average score is y+3, so there is: 10x-z) (10-4)=x+120y+z) (20+4)=y+3

Simplification. 4x-z=6

4y-z=-72

Subtract the two formulas and have 4(x-y)=78

So x-y=

That is, the original first prize is higher than the average score of the second prize.

Surface area of the keg: 5433 (1+2) = 1811 decimeters of dice Surface area of the drum: 1811 2 = 3622 dm of the bottom radius of the keg: decimeters.

Base area: square decimeters.

Side area: 1811-314 = 1497 square decimeters Radius of the bottom surface of the barrel: decimeters.

Base area: square decimeters.

Side area: square decimeters.

First of all, it is proportionally distributed: 5433*1 3=1811 (square decimeter) The bottom radius of the keg decimeter.

The bottom area of the keg.

The side area of the keg.

The method for large barrels is the same as for small barrels.

If the piece in the circle coincides with the triangle is (3), then (3)=100 -(1)The area of the triangle=1 2 ab bc=10bc2)=10bc-(3)=10bc-100 +(1)10bc=100 -7

bc=(100π-7)/10

Let this two-digit number be 10a+b, then its inverse ordinal number is 10b+a, and the problem knows that 10a+b=[(10b+a)+1] 2, that is, 19a-8b-1=0, solve this indefinite equation to get a=3 b=7, then this two-digit number is 37

Let the two-digit number be 10x+y, then it is derived from the proposition: 10x+y=(10y+x+1) 220x+2y=10y+x+119x=8y+1, that is, find the positive integer solution, when x=1, when x=2, when x=3, y=7, when x=4, when x=5, so this number is 37

2 (10x+y)=10y+x+1 solves 19x=8y+1 and takes all 1-9, and only one solution x=3 y=7 is 37

30 minutes = 1 2 hours.

When the van meets the car, it is km away from the bus (48+42)*.

The time it takes for the van to meet the car is 45 (60-42) = hours.

A and B are (60+48)*kilometers apart.